/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q166SE Find az -score, call itz0, such... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find az-score, call itz0, such that

a.P(z≤z0)=.5080

b.P(z≥z0)=.5517

c.P(z≥z0)=.1492

d.P(z0≤z≤.59)=.4773

Short Answer

Expert verified

a.z0=0.02

b.z0=-0.129

c. z0=1.039

d. z0=-0.689

Step by step solution

01

Given information

z-score is denoted by.z0

02

CalculateP(z≤z0)=.5080

P(z≤z0)=.5080Φ(z0)=.5080z0=Φ−1(.5080)z0=0.02

Hence.z0=0.02

03

CalculateP(z≥z0)=.5517

P(z≥z0)=.55171−P(z≤z0)=.55171−Φ(z0)=.5517Φ(z0)=1−.5517Φ(z0)=0.4483z0=Φ−1(0.4483)z0=-0.129

Hencez0=-0.129.

04

CalculateP(z≥z0)=.1492

P(z≥z0)=.14921−P(z≤z0)=.14921−Φ(z0)=.1492Φ(z0)=1−.1492Φ(z0)=0.8508z0=Φ−1(0.8508)z0=1.039

Hence.z0=1.039

05

CalculateP(z0≤z≤.59)=.4773

P(z0≤z≤.59)=.4773P(z≤.59)−P(z≤z0)=.4773P(z≤z0)=P(z≤.59)−.4773Φ(z0)=0.7224−0.4773Φ(z0)=0.2451z0=Φ−1(0.2451)z0=-0.689

Hence z0=-0.689.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Public transit deaths. Millions of suburban commuters use the public transit system (e.g., subway trains) as an alter native to the automobile. While generally perceived as a safe mode of transportation, the average number of deaths per week due to public transit accidents is 5 (Bureau of Transportation Statistics, 2015).

a. Construct arguments both for and against the use of the Poisson distribution to characterize the number of deaths per week due to public transit accidents.

b. For the remainder of this exercise, assume the Poisson distribution is an adequate approximation for x, the number of deaths per week due to public transit accidents. Find E(x)and the standard deviation of x.

c. Based strictly on your answers to part b, is it likely that more than 12 deaths occur next week? Explain.

d. Findp(x>12). Is this probability consistent with your answer to part c? Explain.

Which of the following describe discrete random variables, and which describe continuous random variables?

a. The number of damaged inventory items

b. The average monthly sales revenue generated by a salesperson over the past year

c. Square feet of warehouse space a company rents

d. The length of time a firm must wait before its copying machine is fixed

Find each of the following probabilities for the standard normal random variable z:

a.P(-≤z≤1)b.P(-1.96≤z≤1.96)c.P(-1645≤z≤1.645)d.P(-2≤z≤2)

Suppose x is a normally distributed random variable with μ= 11 and σ= 2. Find each of the following:

a)P(10≤χ≤12)

b) P(6≤χ≤10)

c)P(13≤χ≤16)

d)P(7.8≤χ≤12.6)

e)P(χ≥13.24)

f)P(χ≥7.62)


Blood diamonds. According to Global Research News (March 4, 2014), one-fourth of all rough diamonds produced in the world are blood diamonds, i.e., diamonds mined to finance war or an insurgency. (See Exercise 3.81, p. 200.) In a random sample of 700 rough diamonds purchased by a diamond buyer, let x be the number that are blood diamonds.

a. Find the mean of x.

b. Find the standard deviation of x.

c. Find the z-score for the value x = 200.

d. Find the approximate probability that the number of the 700 rough diamonds that are blood diamonds is less than or equal to 200.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.