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Assume that xis a random variable best described by a uniform distribution with c=10andd=90.

a. Findf(x).

b. Find the mean and standard deviation of x.

c. Graph the probability distribution for xand locate its mean and theintervalon the graph.

d. FindP(x60).

e. FindP(x90).

f. FindP(x80).

g. FindP(-x+).

h. FindP(x>75).

Short Answer

Expert verified

a.fx=180;10x90

b. The mean is=50 and the standard deviation is =23.094.

c. The graph is a symmetrical curve.

d. P(x60)=0.625

e. P(x90)=0

f. P(x80)=0.875

g. P(-<x<+)=0.57735

h. P(x>75)=0.57735

Step by step solution

01

Given information

X is auniformrandom variable.

c=10d=90

02

Calculate f(x)

a.

The p.d.f of X is

fx=1d-c;cxd=190-10=180;10x90

Hence, f(x)=180;10x90.

03

Calculate mean and standard deviation

b.

Mean=

=c+d2=10+902=1002=50

Standard deviation=

=d-c12=90-1012=8012=23.094

Hence, the mean is=50and standard deviation is =23.094.

04

Plot the graph

c.

2=50223.0945046.188=3.812,96.188

05

Calculate P(x≤60)

d.

Px60=1060fxdx=1060180dx=1801060dx=18050=58=0.625

Hence, P(x60)=0.625.

06

Calculate P(x≥90)

e.

Px90=1-Px<90=1-1090fxdx=1-1090180dx=1-18080=1-1=0

Hence, P(x90)=0.

07

Calculate P(x≤80)

f.

Px80=1-8090fxdx=1-8090180dx=1-18010=1-18=0.875

Hence, P(x80)=0.875.

08

Calculate P(μ-σ≤x≤μ+σ)

g.

P-<x<+=-+fxdx=26.90673.094180dx=18046.188=0.57735

Hence,role="math" localid="1660281305747" P(-<x<+)=0.57735.

09

Calculate

h.

Px>75=7590fxdx=7590180dx=18015=316=0.57735

Hence, P(x>75)=0.57735.

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