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Refer to Exercise 2.141. Assuming all populations are approximately mound-shaped, for parts a–d, determine whether the values 0, 4, and 12 are outliers.

Short Answer

Expert verified

a. Outlier – 12

b. Outlier - 12

c. Outlier - 0

d. No Outliers

Step by step solution

01

Determining whether 0, 4, 12 are outliers when the mean is 2 and the standard deviation is 1 

If the distribution is mound-shaped, most of the population should lie within 3 standard deviations from the mean. Therefore, if the z-score is greater than 3, the value is an outlier.

When the mean is 2 and the standard deviation is 1, the z-scores are -2, 2, and 10 for 0, 4, and 12 respectively. Thus,only 12 is the outlier.

02

Repeating Step 1 for mean = 4 and s = 2

Thez−scorevaluesare0=−24=012=4

Using the same logic as above, again 12 is an outlier.

03

Finding the outlier from 0, 4, and 12

Thez−scorevaluesare0=−44=−212=2

Following the above procedure, 0 is an outlier.

04

Identifying the outlier with µ = 8 and σ = 8

Thez−scorevaluesare0=−14=−0.512=0.5

None of the values are outliers because they lie between (-3,3).

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