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Let t0 be a particular value of t. Use Table III in Appendix D to find t0 values such that the following statements are true.

a.=P(-t0<t<t0).95wheredf=10b.P(t-t0ortt0)wheredf=10c.P(tt0)=.05wheredf=10d.P(t-t0ortt0)=.10wheredf=20e.P(t-t0ortt0)=.01wheredf=5

Short Answer

Expert verified

Answer

  1. Not true.
  2. Not applicable
  3. True
  4. True
  5. True

Step by step solution

01

Determining the value of t0 when the probability is 0.95 and degrees of freedom is 10

a.

The two-tail test is applicable in this case. With the help of MS Excel, the exact value of t0 can be found to be 0.064298 when the degrees of freedom is 10. This shows that statement is not true. The value of t0 is very less than the values of t (taking reference from Appendix D).

02

Determining the value of t0 when the probability is unknown and degrees of freedom is 10

In this subpart, the solution cannot be found as the value of the probability is not there.The value of the probability is required in this subpart to denote the value of the t0.

03

Determining the value of t0 when the probability is 0.05 and degrees of freedom is 10

c.

In this subpart, the one-tail test is applicable. With the help of MS Excel, the exact value of t0 can be found to be 1.81246 when the degrees of freedom is 10. This shows that statement is true. The value of t0 is greater than the value of t at t.050, which is 1.725 (taking reference from Appendix D).

04

 Step 4: Determining the value of t0 when the probability is 0.10 and degrees of freedom is 20

e.

In this subpart, the two-tail test is applicable, and so, with the help of MS Excel, the exact value of t0 can be found to be 1.72472 when the degrees of freedom is 20. This shows that statement is true as the value of t0 is greater than the value of t at t.100, which is 1.325 (taking reference from Appendix D).

05

Determining the value of t0 when the probability is 0.01 and degrees of freedom is 5

f.

In this subpart, the two-tail test is applicable, and so, with the help of MS Excel, the exact value of t0 can be found to be 4.0321 when the degrees of freedom is 5. This shows that statement is true as the value of t0 is greater than the value of t at t.010, which is 3.365 (taking reference from Appendix D).

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Most popular questions from this chapter

Identify the rejection region for each of the following cases. Assume

v1=7andv2=9

a. Ha:蟽12&濒迟;蟽22,伪=.05

b. Ha:蟽12&驳迟;蟽22,伪=.01

c. Ha:蟽1222,伪=.1withs12>s22

d. Ha:蟽12&濒迟;蟽22,伪=.025

Question: Consumers鈥 attitudes toward advertising. The two most common marketing tools used for product advertising are ads on television and ads in a print magazine. Consumers鈥 attitudes toward television and magazine advertising were investigated in the Journal of Advertising (Vol. 42, 2013). In one experiment, each in a sample of 159 college students were asked to rate both the television and the magazine marketing tool on a scale of 1 to 7 points according to whether the tool was a good example of advertising, a typical form of advertising, and a representative form of advertising. Summary statistics for these 鈥渢ypicality鈥 scores are provided in the following table. One objective is to compare the mean ratings of TV and magazine advertisements.

a. The researchers analysed the data using a paired samples t-test. Explain why this is the most valid method of analysis. Give the null and alternative hypotheses for the test.

b. The researchers reported a paired t-value of 6.96 with an associated p-value of .001 and stated that the 鈥渕ean difference between television and magazine advertising was statistically significant.鈥 Explain what this means in the context of the hypothesis test.

c. To assess whether the result is 鈥減ractically significant,鈥 we require a confidence interval for the mean difference. Although this interval was not reported in the article, you can compute it using the information provided in the table. Find a 95% confidence interval for the mean difference and interpret the result. What is your opinion regarding whether the two means are 鈥減ractically significant.鈥

Source: H. S. Jin and R. J. Lutz, 鈥淭he Typicality and Accessibility of Consumer Attitudes Toward Television Advertising: Implications for the Measurement of Attitudes Toward Advertising in General,鈥 Journal of Advertising, Vol. 42, No. 4, 2013 (from Table 1)

Corporate sustainability of CPA firms. Refer to the Business and Society (March 2011) study on the sustainability behaviors of CPA corporations, Exercise 2.23 (p. 83). Recall that the level of support for corporate sustainability (measured on a quantitative scale ranging from 0 to 160 points) was obtained for each of 992 senior managers at CPA firms. The accompanying Minitab printout gives the mean and standard deviation for the level of support variable. It can be shown that level of support is approximately normally distributed.

a. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is less than 40 points.

b. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is between 40 and 120 points.

c. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is greater than 120 points.

d. One-fourth of the 992 senior managers indicated a level of support for corporate sustainability below what value?

Descriptive Statistics: Support

Variables

N

Mean

StDev

Variance

Minimum

Maximum

Range

Support

992

67.755

26.871

722.036

0.000

155.000

155.000

Shopping vehicle and judgment. Refer to the Journal ofMarketing Research (December 2011) study of shopping cart design, Exercise 2.85 (p. 112). Recall that design engineers want to know whether the mean choice of the vice-over-virtue score is higher when a consumer鈥檚 arm is flexed (as when carrying a shopping basket) than when the consumer鈥檚 arm is extended (as when pushing a shopping cart). The average choice score for the n1 = 11 consumers with a flexed arm was x1= 59, while the average for the n2 = 11
Consumers with an extended arm was x2= 43. In which scenario is the assumption required for a t-test to compare means more likely to be violated, S1= 4 and S2= 2, or, S1= 10 and S2 = 15? Explain.

Shared leadership in airplane crews. Refer to the Human Factors (March 2014) study of shared leadership by the cockpit and cabin crews of a commercial airplane, Exercise 8.14 (p. 466). Recall that each crew was rated as working either successfully or unsuccessfully as a team. Then, during a simulated flight, the number of leadership functions exhibited per minute was determined for each individual crew member. One objective was to compare the mean leadership scores for successful and unsuccessful teams. How many crew members would need to be sampled from successful and unsuccessful teams to estimate the difference in means to within .05 with 99% confidence? Assume you will sample twice as many members from successful teams as from unsuccessful teams. Also, assume that the variance of the leadership scores for both groups is approximately .04.

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