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4.132 Suppose xis a random variable best described by a uniform

probability distribution with c= 3 and d= 7.

a. Find f(x)

b. Find the mean and standard deviation of x.

c. FindP(-x+)

Short Answer

Expert verified

a. The probability density function is

f(x)=0.253x70;otherwise

b. The mean is 5 and standard deviation is 1.1547.

c.P(-x+)

Step by step solution

01

Given Information

Here, x is a uniform random variable with parameters c=3 and d=7.

02

Finding the pdf of x

a.

The probability density function random variable x is given by

f(x)=1d-c;c<x<d

Here, c=3 and d=7.

So, the pdf of x is:

f(x)=17-3=14=0.25

Thus, f (x) = 0.25 ; 3 < x < 7

03

Finding the mean and standard deviation of x.

b.

The mean of the random variable x is given by,

=c+d2=3+72=102=5

The standard deviation of x is given by,

=d-c12=7-312=423=23=1.1547

Thus, the mean =5and standard deviation =1.1547.

04

Finding the P(μ-σ≤x≤μ+σ)

c.P(-x+)=-+f(x)dx=-+0.25dx=0.25-+dx=0.25x-+=0.25+-+=0.252=0.5023=0.5774

So, the required probability is 0.5774.

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