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Chapter 6: Q26E (page 348)

Question: Let t0 be a specific value of t. Use Table III in Appendix D to find t0 values such that the following statements are true.

a.P(t鈮�t0)=.025wheredf=11b.P(t鈮�t0)=.01wheredf=9c.P(t鈮�t0)=.005wheredf=6d.P(t鈮�t0)=.05wheredf=18

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Answer

  1. True
  2. True
  3. True
  4. True

Step by step solution

01

Determining the value of t0 when the probability is 0.025 and degrees of freedom is 11

a.

In this subpart, the one-tailed test is applicable, for which, with the help of MS Excel, the exact value of t0 can be found to be 2.201 when the degrees of freedom is 11.This shows that the given statement is true because the value of t0 is exactly equal to the value of t.025,which is found after taking reference from Appendix D.

02

Determining the value of t0 when the probability is 0.01 and degrees of freedom is 9

b.

In this subpart, the one-tailed test is applicable, for which, with the help of MS Excel, the exact value of t0 can be found to be 2.821 when the degrees of freedom is 9.This shows that the given statement is true because the value of t0 is exactly equal to the value of t.01,which is found after taking reference from Appendix D.

03

Determining the value of t0 when the probability is 0.005 and degrees of freedom is 6

c.

In this subpart, the one-tailed test is applicable, for which, with the help of MS Excel, the exact value of t0 can be found to be 3.707 when the degrees of freedom is 9.This shows that the given statement is true because the value of t0 is exactly equal to the value of t.005,which is found after taking reference from Appendix D.

04

Determining the value of t0 when the probability is 0.05 and degrees of freedom is 18

d.

In this subpart, the one-tailed test is applicable, for which, with the help of MS Excel, the exact value of t0 can be found to be 1.734 when the degrees of freedom is 18. This shows that the given statement is true because the value of t0 is exactly equal to the value of t.05,which is found after taking reference from Appendix D.

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