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Water pollution testing. The EPA wants to test a randomlyselected sample of n water specimens and estimate themean daily rate of pollution produced by a mining operation.If the EPA wants a 95% confidence interval estimatewith a sampling error of 1 milligram per liter (mg/L),how many water specimens are required in the sample?Assume prior knowledge indicates that pollution readingsin water samples taken during a day are approximately

normally distributed with a standard deviation equal to5 mg/L.

Short Answer

Expert verified

The number of water specimens required in the sample are n=97.

Step by step solution

01

Given Information

In water pollution testing the EPA is randomly selecting a sample with n water specimens to estimate the mean daily rate of pollution. The EPA wants a confidence interval of 95% level of significance with a sampling error of 1 mg/L.

The prior knowledge tells that the sample standard deviation is 5mg/L.

02

Step 2:Defining the parameters

Therefore, the parameters here are:

=5mg/LS.E.=1mg/LCI=0.95

Now, the formula for sampling error is:

S.E.=zn

Also, the z value for 0.95 confidence interval is 1.96

Step 2:Substituting the values

S.E.=zn1=1.965nn=9.8n=96.04n97

Therefore, n=97 water specimens are required

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