/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 34E Evaporation from swimming pools.... [FREE SOLUTION] | 91影视

91影视

Evaporation from swimming pools. A new formula for estimating the water evaporation from occupied swimming pools was proposed and analyzed in the journal Heating Piping/Air Conditioning Engineering (April 2013). The key components of the new formula are number of pool occupants, area of pool鈥檚 water surface, and the density difference between room air temperature and the air at the pool鈥檚 surface. Data were collected from a wide range of pools for which the evaporation level was known. The new formula was applied to each pool in the sample, yielding an estimated evaporation level. The absolute value of the deviation between the actual and estimated evaporation level was then recorded as a percentage. The researchers reported the following summary statistics for absolute deviation percentage: x=18, s=20. Assume that the sample containedn=15 swimming pools

a. Estimate the true mean absolute deviation percentage for the new formula with a 90% confidence interval.

b. The American Society of Heating, Refrigerating, and Air-Conditioning Engineers (ASHRAE) handbook also provides a formula for estimating pool evaporation. Suppose the ASHRAE mean absolute deviation percentage is =40%. (This value was reported in the article.) On average, is the new formula 鈥渂etter鈥 than the ASHRAE formula? Explain

Short Answer

Expert verified
  1. The true mean absolute deviation percentage for the new formula with a 90% confidence interval is8.906,27.094
  2. Yes the new formula is better than the ASHRAE formula because the ASHRAE mean absolute deviation percentage is =34%does not lie between the lower and upper limits .that is =34%,

Step by step solution

01

Given information

Sample mean x=18,

Sample standard deviation s=20

Sample size n=5

02

Calculating the true mean absolute deviation percentage for the new formula with 90% confidence interval..

To estimate the true mean absolute deviation percentage for the new formula with 90% confidence interval.

The degree of freedom can be calculated as

df=n1=151=14

Confidence coefficient is given 0.90. hence,

1=0.90=10.90=0.1

2=0.05

Therefore, from the 鈥渢able 3 appendix D鈥 the vale of t0.05,14=1.761

90% of confidence interval is obtained as:

xt2sn=181.7612015=189.094=189.094,18+9.094

xt2sn=8.906,27.094

Hence, the true mean absolute deviation percentage for the new formula with a 90% confidence interval is8.906,27.094

03

Calculating the true mean absolute deviation percentage for the new formula with 90% confidence interval..

Yes the new formula is better than the ASHRAE formula because the ASHRAE mean absolute deviation percentage is=34% does not lie between the lower and upper limits .that is 8.906,27.094,

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Methyl t-butyl ether (MTBE) is an organic water contaminant that often results from gasoline spills. The level of MTBE (in parts per billion) was measured for a sample of 12 well sites located near a gasoline service station in New Jersey (Environmental Science & Technology,January 2005). The data are listed in the accompanying table.

a. Give a point estimate for m, the true mean MTBE level for all well sites located near the New Jersey gasoline service station.

b. Calculate and interpret a 99% confidence interval for m.

c. What assumptions are required for the interval, part b, to be valid? Are these assumptions reasonably satisfied?

FindZ/2for each of the following:

a.= .10

b.= .01

c.= .05

d.= .20

Question: Heart rate variability of police officers. Are police officers susceptible to higher-than-normal heart rates? The heart rate variability (HRV) of police officers was the subject of research published in the American Journal of Human Biology (January 2014). HRV is defined as the variation in time intervals between heartbeats. A measure of HRV was obtained for each in a sample of 355 Buffalo, N.Y., police officers. (The lower the measure of HRV, the more susceptible the officer is to cardiovascular disease.) For the 73 officers diagnosed with hypertension, a 95% confidence interval for the mean HRV was (4.1, 124.5). For the 282 officers who are not hypertensive, a 95% confidence interval for the mean HRV was (148.0, 192.6).

a. What confidence coefficient was used to generate the confidence intervals?

b. Give a practical interpretation of both 95% confidence intervals. Use the phrase 鈥95% confident鈥 in your answer.

c. When you say you are 鈥95% confident,鈥 what do you mean?

d. If you want to reduce the width of each confidence interval, should you use a smaller or larger confidence coefficient? Explain.

Who prepares your tax return? Refer to the Behavioral Research and Accounting (January 2015) study on income tax compliance, Exercise 5.50 (p. 321). Recall that in a sample of 270 U.S. adult workers, the researchers found that 37% prepare their own tax return.

a. Construct a 99% confidence interval for the true proportion of all U.S. adult workers who prepare their own tax return.

b. Suppose an IRS tax consultant claims that 50% of all U.S. adult workers prepare their own tax return. Make an inference about this claim.

c. According to the researchers, about 70% of the sampled workers were recruited from a shopping mall (where they were reimbursed $5 for their time) and about 30% were full-time workers enrolled in a professional graduate degree program. How might this information impact the inference you made in part b?

Question: Explain the differences in the sampling distributions of xfor large and small samples under the following assumptions.

a. The variable of interest, x, is normally distributed.

b. Nothing is known about the distribution of the variable x.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.