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In a test of \({H_0}:\mu = 100\) against \({H_a}:\mu \ne 100\), the sample data yielded the test statistic z = 2.17. Find the p-value for the test.

Short Answer

Expert verified

The p-value for the hypothesis test is 0.030.

Step by step solution

01

Given information

The hypothesis test is:\({H_0}:\mu = 100\)versus\({H_a}:\mu \ne 100\).

The test statistic is \(z = 2.17\).

02

Computing the p-value

The p-value for the two-tailed test is:

\(\begin{aligned}p &= 2P\left( {Z > 2.17} \right)\\ &= 2\left( {1 - P\left( {Z \le 2.17} \right)} \right)\\ &= 2 \times \left( {1 - 0.9850} \right)\\ &= 2 \times 0.0150\\ &= 0.030\end{aligned}\).

The probability of a z-score less than or equal to 2.17 is obtained from the z-table.

Hence the p-value is 0.030.

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