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A die is rolled 10 times. Find the chance of \(-\) (a) getting 10 sixes. (b) not getting 10 sixes. (c) all the rolls showing 5 spots or less.

Short Answer

Expert verified
(a) \( \left(\frac{1}{6}\right)^{10} \); (b) \( 1 - \left(\frac{1}{6}\right)^{10} \); (c) \( \left(\frac{5}{6}\right)^{10} \).

Step by step solution

01

Understanding the Problem

We are rolling a fair six-sided die 10 times, and we need to work out three probabilities: (a) the probability of rolling ten 6's, (b) the probability of not rolling ten 6's, and (c) the probability that all 10 rolls show a number from 1 to 5.
02

Calculate probability of rolling 10 sixes

The probability of rolling a 6 on a single die is \( \frac{1}{6} \). Since each roll is independent, the probability of rolling a 6 ten times in a row is \( \left(\frac{1}{6}\right)^{10} \). Calculate this to find the probability of getting 10 sixes.
03

Calculate probability of not getting 10 sixes

The probability of not rolling ten 6's in all attempts is the complement of getting 10 sixes. Hence, it is given by \( 1 - \left(\frac{1}{6}\right)^{10} \).
04

Calculate probability of rolling numbers 1 to 5

The probability of rolling any number from 1 to 5 on a single die is \( \frac{5}{6} \). To find the probability that all 10 rolls result in numbers 1 to 5, calculate \( \left(\frac{5}{6}\right)^{10} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence of Events
Understanding the independence of events is a crucial concept in probability. When dealing with probability, two events are considered independent if the occurrence of one event does not affect the occurrence of the other. In simpler terms, whether the first event happens or not, it doesn’t change the chances of the second event occurring.
When tossing a fair die, each roll is independent of the others. If you roll a die once, the probability of getting any number, including a 6, remains constant at \( \frac{1}{6} \). Now, if you roll the die again, the results of the first roll do not impact what you get on the second roll; the probability is still \( \frac{1}{6} \).
This independence principle allows us to calculate the probability of a sequence of events by multiplying the probability of each event. For example, when rolling a die ten times in a row, each roll being a 6 has a probability of \( \left(\frac{1}{6}\right)^{10} \) for all ten rolls landing on six.
Complement Rule
The complement rule in probability is a handy tool for simplifying calculations. It states that the probability of an event not occurring is equal to 1 minus the probability of it occurring. This is because the total probability of all possible outcomes adds up to 1.
For example, if we're looking at rolling a 6 ten times in a row, the probability of this happening is given by \( \left(\frac{1}{6}\right)^{10} \). The complement rule allows us to find the probability of not rolling ten 6's by using the formula:
  • Probability of not rolling ten 6's = 1 - Probability of rolling ten 6's
Thus, we calculate it as \( 1 - \left(\frac{1}{6}\right)^{10} \), showing how complement can be a simple yet powerful way to approach probability problems.
Probability of a Sequence
In probability, calculating the chance of a sequence of events is about understanding how each event in the sequence affects the outcome. For independent events, each has no impact on another. Thus, the overall sequence probability is the product of the probabilities of each individual event.
When you roll a die, the probability of getting any number between 1 and 5 is \( \frac{5}{6} \). If you roll the die ten times, and you want all to be numbers from 1 to 5, the events are independent and their combined probability must be calculated as:
  • Probability of rolling numbers 1 to 5 each time = \( \left(\frac{5}{6}\right)^{10} \)
This is the method to calculate how specific sequences occur, particularly in scenarios where each individual event is independent and equally likely, such as the continuous rolling of a fair die.

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Most popular questions from this chapter

A deck of cards is shuffled and the top two cards are placed face down on a table. True or false, and explain: (a) There is 1 chance in 52 for the first card to be the ace of clubs. (b) There is 1 chance in 52 for the second card to be the ace of diamonds. (c) The chance of getting the ace of clubs and then the ace of diamonds. 1\(/ 52 \times 1 / 52\) .

A die is rolled four times. What is the chance that- (a) all the rolls show 3 or more spots? (b) none of the rolls show 3 or more spots? (c) not all the rolls show 3 or more spots?

A coin is tossed six times. Two possible sequences of results are (i) HTTHTH (ii) HHHHH (The coin must land \(\mathrm{H}\) or \(\mathrm{T}\) in the order given \(; \mathrm{H}=\) heads \(, \mathrm{T}=\) tails. \()\) Which of the following is correct? Explain. (a) Sequence (i) is more likely. (b) Sequence (ii) is more likely. (c) Both sequences are equally likely.

You are thinking about playing a lottery. The rules: you buy a ticket, choose 3 different numbers from 1 to \(100,\) and write them on the ticket. The lottery has a box with 100 balls numbered from 1 through \(100 .\) Three balls are drawn at random without replacement. If the numbers on these balls are the same as the numbers on your ticket, you win. (Order doesn't matter.) If you decide to play, what is your chance of winning?

Two cards will be dealt off the top of a well-shuffled deck. You have a choice: (i) To win \(\$ 1\) if the first is a king. (ii) To win \(\$ 1\) if the first is a king and the second is a queen.Which option is better? Or are they equivalent? Explain briefly.

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