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Suppose you plan to sample 10 items from a population of 120 items and would like to determine the probability of observing 4 defective items in the sample. Which probability distribution should you use to compute this probability under the conditions listed here? Justify your answers. a. The sample is drawn without replacement. b. The sample is drawn with replacement.

Short Answer

Expert verified
Use hypergeometric distribution for without replacement, binomial distribution for with replacement.

Step by step solution

01

Understand the Scenario

In this exercise, we need to find an appropriate probability distribution to model the probability of observing 4 defective items from a sample of 10 items in a population of 120 items, considering two different conditions: sampling without replacement and with replacement.
02

Consider Case A - Without Replacement

When sampling without replacement from a finite population, the probability of getting a specific number of defective items follows a hypergeometric distribution. This distribution accounts for the fact that each draw affects the outcome of subsequent draws, as the population size decreases with each draw.
03

Confirm Hypergeometric Distribution Appropriateness

To verify, recall the hypergeometric distribution properties: we are interested in drawing a specific number of successes (defective items) from a finite population without replacement. This matches our scenario exactly since drawing affects the probability of future draws.
04

Consider Case B - With Replacement

For sampling with replacement, the probability of getting a fixed number of defective items follows a binomial distribution. This is because each draw is independent, and the probability remains constant across draws, analogous to repeated trials with the same success probability.
05

Confirm Binomial Distribution Appropriateness

The binomial distribution is applicable here because it describes the number of successes (defective items) in a sequence of independent trials with a fixed probability of success, aligning with the condition of sampling with replacement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypergeometric Distribution
Imagine you have a box of 120 items, and among them, some are defective. When you want to pick a sample without putting each one back, you're dealing with a hypergeometric distribution. This sounds complex, but it's all about understanding the influence each draw has on the next one because the population shrinks each time you take an item.

The hypergeometric distribution helps us discover the likelihood of picking a certain number of defective items when the sampling is done without replacement. Unlike other distributions, here, each draw changes the odds for the next draw.

It's significant in scenarios where the population size is fixed, and each draw directly affects what's left. For instance, if you pick one defective item, there's one less defective item in the pool, altering the chances of picking another one next. This dependency is crucial in calculation and sets the hypergeometric distribution apart.
Binomial Distribution
When you want to find out the probability of picking a specific number of defective items from a group, and you're putting each item back, you're exploring the binomial distribution. Envision having infinite chances with the same conditions each time; this describes the binomial nature perfectly.

With the binomial distribution, each draw doesn't affect the next one — they're independent. You have a fixed number of trials (in this case, picking items) and a constant probability of success (or finding a defective item) for each of these trials.

This distribution is particularly useful for situations like quality control, where you might want to know the odds of finding defective products when each sampling is done independently, unaffected by previous draws. It's like flipping a fair coin multiple times and wanting to know the probability of getting heads a certain number of times.
Sampling Methods
Sampling methods play a pivotal role in how we approach the probability distributions. They determine the type of distribution that best models our scenario.

There are two main sampling methods:
  • Without Replacement: When you sample without replacement, once you draw an item, it's not put back. This method is closely tied to the hypergeometric distribution. Because each draw impacts the subsequent ones, it’s more realistic for small finite populations.
  • With Replacement: In this method, after selecting an item, it goes back into the population pool. Thus, the probability of each subsequent draw remains constant. This is aligned with the binomial distribution.
Understanding these sampling methods thoroughly is essential to choosing the right probability distribution for an exercise.
Dependent and Independent Events
Grasping the concepts of dependent and independent events can considerably deepen your understanding of probability distributions.

  • Dependent Events: These are events where the outcome is influenced by the previous ones. In our scenario, drawing without replacement creates dependent events, as each defective item discovered decreases the pool, altering the chances for the following ones.
  • Independent Events: Conversely, these are unaffected by prior outcomes. When sampling with replacement, each draw is an independent event, maintaining consistent probabilities regardless of what was drawn before.
The distinction between dependent and independent events is critical because it determines how we model our problem using probability distributions. While hypergeometric distribution deals with dependencies, the binomial distribution handles independence.

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Most popular questions from this chapter

Gender in two-child families. Human Biology (Feb. 2009) published a study on the gender of children in two-child families. In populations where it is just as likely to have a boy as a girl, the probabilities of having two girls, two boys, or a boy and a girl are well known. Let \(x\) represent the number of boys in a two-child family. a. List the possible ways (sample points) in which a twochild family can be gender-configured. (For example, \(\mathrm{BG}\) represents the event that the first child is a boy and the second is a girl.) b. Assuming boys are just as likely as girls to be born, assign probabilities to the sample points in part a. c. Use the probabilities, part a, to find the probability distribution for \(x\). d. The article reported on the results of the National Health Interview Survey (NHIS) of almost 43,000 twochild families. The table gives the proportion of families with each gender configuration. Use this information to revise the probability distribution for \(x\). $$ \begin{array}{lc} \hline \text { Gender Configuration } & \text { Proportion } \\ \hline \text { Girl-girl (GG) } & .222 \\ \text { Boy-girl (BG) } & .259 \\ \text { Girl-boy (GB) } & .254 \\ \text { Boy-boy (BB) } & .265 \end{array} $$

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