/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 In the gas mileage test describe... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 13: Problem 9

In the gas mileage test described in this chapter, would you prefer a smaller or a larger sample size if you were (a) the car manufacturer? Why? (b) a vigorous prosecutor for the federal regulatory agency? Why?

Short Answer

Expert verified
A car manufacturer would prefer a larger sample size to get a more accurate representation of the true gas mileage, while a prosecutor for a regulatory agency might prefer a smaller sample size to find more extreme outliers that could signal potential problems with the car.

Step by step solution

01

Analyzing Perspective of Manufacturer

Car manufacturers would generally prefer a larger sample size because it would lead to more reliable test results. Larger sample sizes reduce sampling error and variability and provide a more accurate representation of the true gas mileage.
02

Analyzing Perspective of Regulatory Agency Prosecutor

In contrast, a prosecutor for a regulatory agency might prefer a smaller sample size. This is because they are looking for any outliers or extreme results that may indicate a potential problem with the car. Smaller sample sizes may reveal more extreme results due to their high variability, which can trigger further investigation into the car's performance.
03

Underlying Reasoning

Overall, the reasoning here revolves around variability. Larger sample sizes will reduce variability and give a more accurate measurement of the true gas mileage. This benefits the car manufacturer as it reflects the true performance of their car. On the other hand, smaller sample sizes have more variability and are more likely to produce outlier results, which might be of interest to the prosecutor from the regulatory agency. They are not necessarily interested in the car's 'average' performance, but rather in identifying any potential issues that could signal a fault with the car.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

It's well established, we'll assume, that lab rats require an average of 32 trials in a complex water maze before reaching a learning criterion of three consecutive errorless trials. To determine whether a mildly adverse stimulus has any effect on performance, a sample of seven lab rats were given a mild electrical shock just before each trial. (a) Given that \(\bar{X}=34.89\) and \(s=3.02\), test the null hypothesis with \(t\), using the .05 level of significance. (b) Construct a 95 percent confidence interval for the true number of trials required to learn the water maze. (c) Interpret this confidence interval.

Assume that, on average, healthy young adults dream 90 minutes each night, as inferred from a number of measures, including rapid eye movement (REM) sleep. An investigator wishes to determine whether drinking coffee just before going to sleep affects the amount of dream time. After drinking a standard amount of coffee, dream time is monitored for each of 28 healthy young adults in a random sample. Results show a sample mean, \(\bar{X},\) of 88 minutes and a sample standard deviation, \(s,\) of 9 minutes. (a) Use \(t\) to test the null hypothesis at the .05 level of significance. (b) If appropriate (because the null hypothesis has been rejected), construct a 95 percent confidence interval and interpret this interval.

A library system lends books for periods of 21 days. This policy is being reevaluated in view of a possible new loan period that could be either longer or shorter than 21 days. To aid in making this decision, book-lending records were consulted to determine the loan periods actually used by the patrons. A random sample of eight records revealed the following loan periods in days: \(21,15,12,24,20,21,13,\) and 16 . Test the null hypothesis with \(t\), using the .05 level of significance.

A consumers' group randomly samples 10 "one-pound" packages of ground beef sold by a supermarket. Calculate (a) the mean and (b) the estimated standard error of the mean for this sample, given the following weights in ounces: \(16,15,14,\) 15,14,15,16,14,14,14.

Even though the population standard deviation is unknown, an investigator uses \(z\) rather than the more appropriate \(t\) to test a hypothesis at the .05 level of significance. (a) Is the true level of significance larger or smaller than .05? (b) Is the true critical value larger or smaller than that for the critical z?
See all solutions

Recommended explanations on Math Textbooks

Probability and Statistics

Read Explanation

Applied Mathematics

Read Explanation

Calculus

Read Explanation

Pure Maths

Read Explanation

Discrete Mathematics

Read Explanation

Logic and Functions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.