Chapter 23: Problem 853
Derive the Hardy-Weinberg probabilities in a population with random mating.
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Chapter 23: Problem 853
Derive the Hardy-Weinberg probabilities in a population with random mating.
These are the key concepts you need to understand to accurately answer the question.
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A pharmaceutical company wants to test the eftectiveness of a new vaccine in preventing a certain disease. It is estimated that 40 per cent of the people exposed to the disease will contract it under normal circumstances. A group of 12 persons who have been exposed to the disease volunteer to be vaccinated. Two of them later contract the disease. An effective vaccine would reduce the probability that a person exposed to the disease will actually contract it. However, if the vaccine has no effect the probability of any given exposed person contracting the disease is \(\mathrm{p}=0.4\) Use a .05 significance level to decide if the vaccine is effective.
Suppose it is desired to compare the effects of two analgesic drugs \(\mathrm{A}\) and \(\mathrm{B}\) in the treatment of a certain disease, and eight patients volunteer for the experiment. The following results are obtained: Data on the effects of two analgesic drugs: $$ \begin{array}{|c|c|c|c|} \hline \text { Patients } & \begin{array}{l} \text { Hours of relief } \\ \text { with analgesic } \\ \text { A } \end{array} & \begin{array}{l} \text { Hours of relief } \\ \text { with analgesic } \\ \text { B } \end{array} & \begin{array}{l} \text { Relative } \\ \text { advantage } \\ \text { of } B \text { in } \\ \text { Hours (x) } \end{array} \\ \hline 1 & 3.2 & 3.8 & +0.6 \\ 2 & 1.6 & 1.0 & -0.6 \\ 3 & 5.7 & 8.4 & +2.7 \\ 4 & 2.8 & 3.6 & +0.8 \\ 5 & 5.5 & 5.0 & -0.5 \\ 6 & 1.2 & 3.5 & +2.3 \\ 7 & 6.1 & 7.3 & +1.2 \\ 8 & 2.9 & 4.8 & +1.9 \\ \hline \text { Means } & 3.62 & 4.67 & +1.05 \\ \hline \end{array} $$ Test the hypothesis that drugs \(\mathrm{A}\) and \(\mathrm{B}\) are equally effective.
Consider the model below for the circulation of phosphorus, in a simple pasture ecosystem: Assume further that, (1) whenever an atom of phosphorus is in the soil at the beginning of the day, then the sample space giving its location at the end of the day is \(\\{\mathrm{S}=(3 / 5), \mathrm{G}=(3 / 10), \mathrm{O}=(1 / 10)\\}\) (In the case if where 0 occurs, the molecule has been lost to the pasture by erosion.) (2) Whenever an atom of phosphorus is in the grass at the beginning of the day, then its probable location at the end of the day is given by the sample space \(\\{\mathrm{S}=(1 / 10), \mathrm{G}=(4 / 10), \mathrm{C}=(1 / 2)\\}\) so that the probability is \((1 / 2)\) that the atom of phosphorus will be eaten by cattle. (3) Similarly, whenever the atom of phosphorus starts in cattle, \(\\{\mathrm{S}=(3 / 4), \mathrm{C}=(1 / 5), \mathrm{O}=(1 / 20)\\}\) in the sample space for its location at the end of the day. (Note the high probability \((3 / 4)\) of the ingested phosphorus being returned to the soil via feces).(4) Finally, if an atom of phosphorus is outside the pasture it stays outside, so that a sample space for its location at the end of the day is If an atom of phosphorus starts in the soil, what is the probability that it will be outside the system in three days?
The mean difference in length between the right and left femurs of 36 skeletons of a certain species is found to be \(2.0234 \mathrm{~cm}\). The sum of the squared deviations from the mean, \(\sum(\mathrm{X}-\underline{\mathrm{X}})^{2}\), , is \(418.6875\). Test the hypothesis that on the average the left and right femurs are of equal lengths.
Assume four rats are given a dose of a drug. After two days, the number of dead rats are observed. Each rat has the same probability, \(\mathrm{p}\), of dying. Find the binomial distribution of \(0,1,2,3\), and 4 rats dying. Why might the binomial model fail?
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