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Use principal component analysis to determine the factor-loadings and the minimum number of common factors that could give rise to the following correlation matrix : \begin{tabular}{|l|l|l|} \hline & \(\mathrm{X}_{1}\) & \(\mathrm{X}_{2}\) \\ \hline \(\mathrm{X}_{1}\) & \(1.00\) & \(.48\) \\ \hline \(\mathrm{X}_{2}\) & \(.48\) & \(1.00\) \\ \hline \end{tabular}

Short Answer

Expert verified
The eigenvalues of the given correlation matrix are \(\lambda_1=1.48\) and \(\lambda_2=0.52\). Since \(\lambda_1 \geq 1\), we consider it significant, which leads to the minimum number of common factors being 1. The eigenvector corresponding to \(\lambda_1\) is \(\textbf{v}_1=\begin{bmatrix} 0.71 \\ 0.71 \end{bmatrix}\). The factor-loadings for this principal component are \(0.71\sqrt{1.48} \approx \begin{bmatrix} 0.87 \\ 0.87 \end{bmatrix}\). Therefore, we can conclude that 1 common factor can explain the given correlation matrix, with factor-loadings of approximately \(0.87\) for both \(X_1\) and \(X_2\).

Step by step solution

01

Compute the eigenvalues and eigenvectors

First, let's find the eigenvalues and eigenvectors of the given correlation matrix. To compute the eigenvalues, we need to solve the characteristic equation: \[\text{det}(A -\lambda I) = 0\] where \(A\) is the correlation matrix, \(\lambda\) are the eigenvalues, and \(I\) is an identity matrix. So, we have: \[\text{det}\begin{bmatrix} 1.00 -\lambda & 0.48 \\ 0.48 & 1.00-\lambda \\ \end{bmatrix} = 0\] Expanding the determinant, we get a quadratic equation for \(\lambda\): \[(1-\lambda)(1-\lambda) - (0.48)(0.48) = 0\] Now, let's solve this equation to find the eigenvalues.
02

Determine the number of principal components

Solving the quadratic equation, we obtain two eigenvalues, \(\lambda_1\) and \(\lambda_2\). We will consider the eigenvalue to be significant if it is greater than or equal to 1. Based on the number of significant eigenvalues, we can determine the minimum number of common factors that could give rise to the given correlation matrix.
03

Calculate factor-loadings

Now, we need to find the eigenvectors associated with the significant eigenvalues. Let's denote them by \(\textbf{v}_1\) and \(\textbf{v}_2\). Once we have the eigenvectors, we can compute the factor-loadings using the following formula: \[\text{Factor-loadings} = \textbf{v} \cdot \sqrt{\lambda}\] Here, \(\textbf{v}\) is the eigenvector and \(\lambda\) is the significant eigenvalue. Calculate the factor-loadings for each of the significant eigenvalues and their corresponding eigenvectors.
04

Analyze the results

Now, we have the factor-loadings for each significant eigenvalue and their corresponding eigenvectors. These factor-loadings represent the strength of the relationship between the original variables and the principal components. By observing the magnitude and sign of the factor-loadings, we can interpret the meaning of each principal component. Also, we can conclude the minimum number of common factors that could give rise to the given correlation matrix based on the number of significant eigenvalues we found in step 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues and Eigenvectors
In principal component analysis (PCA), eigenvalues and eigenvectors play a crucial role. They are mathematical constructs that help us understand the variance and direction of our data when transforming it.
PCA starts by identifying these eigenvalues (lambda) and eigenvectors for the correlation matrix of the dataset. The correlation matrix measures how variables relate to each other—how they "co-vary." This helps deduce the underlying patterns in data.

Eigenvalues tell us how much variance is explained by each principal component. If an eigenvalue is large, that means that component explains a significant amount of variation. Eigenvectors, on the other hand, point in directions in space that maximize the variance. Think of them as arrows pointing in the direction of most change in your data.

To find the eigenvalues and eigenvectors, solve the equation:
  • \( \text{det}(A -\lambda I) = 0 \)
Here, \(A\) is the correlation matrix, \(\lambda\) represents the eigenvalues, and \(I\) is the identity matrix. Solving this will help pinpoint the most meaningful directions in the data.
Factor Loadings
Once you have the eigenvalues and corresponding eigenvectors from the PCA, you can compute factor loadings. These are core to understanding the relationships between original data variables and the derived components.
Factor loadings indicate how strongly each original variable is associated with a principal component. They provide insight into which variables are most important for each component, effectively reducing the dimensional complexity of the data.

To calculate factor loadings, use the formula:
  • \( \text{Factor-loadings} = \text{v} \cdot \sqrt{\lambda} \)
Here, \(\text{v}\) represents the eigenvector, and \(\lambda\) stands for the significant eigenvalue. Multiplying the eigenvector by the square root of its eigenvalue scales the vector, resulting in the factor loadings.

These factor loadings help interpret the principal components by showing which original variables mostly contribute to each component, guiding us on how the data might be simplified.
Correlation Matrix
A correlation matrix is a table that displays the correlation coefficients between subsets of variables. Each element in the matrix measures how much two variables co-relate; it ranges between -1 and 1.
A value closer to 1 indicates a strong positive correlation, meaning as one variable increases, so does the other. A value closer to -1 suggests a strong negative correlation, where one variable increases as the other decreases. A value around 0 indicates no correlation.

Correlations are a key part of PCA because they help identify relationships within the dataset that might not be immediately obvious. By setting up a correlation matrix, we prepare the data to find those all-important eigenvalues and eigenvectors. These, in turn, help create the principal components used in PCA.

Such a matrix simplifies examining relationships in larger datasets, allowing us to summarize data characteristics. It gives a preliminary overview before delving deeper with PCA steps, making it foundational for understanding data dynamics.

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Most popular questions from this chapter

A large automobile agency wishes to determine the relationship between a salesman's aptitude test score and the number of cars sold by the salesman during his first year of employment. A random sample of 15 salesmen's files reveals the following information. \begin{tabular}{|c|c|c|} \hline Salesman & Test score \(\mathrm{X}\) & Number of cars \(\mathrm{Y}\) \\ \hline \(\mathrm{A}\) & 72 & 341 \\ \hline \(\mathrm{B}\) & \(88.5\) & 422 \\ \hline \(\mathrm{C}\) & 70 & 322 \\ \hline \(\mathrm{D}\) & 87 & 440 \\ \hline \(\mathrm{E}\) & 71 & 287 \\ \hline \(\mathrm{F}\) & 85 & 415 \\ \hline \(\mathrm{G}\) & 89 & 463 \\ \hline \(\mathrm{H}\) & 93 & 497 \\ \hline \(\mathrm{I}\) & 98 & 510 \\ \hline \(\mathrm{J}\) & 96 & 512 \\ \hline \(\mathrm{K}\) & 86 & 432 \\ \hline \(\mathrm{L}\) & 82 & 390 \\ \hline \(\mathrm{M}\) & 88 & 453 \\ \hline \(\mathrm{N}\) & 83 & 374 \\ \hline \(\mathrm{O}\) & 80 & 385 \\ \hline \end{tabular} Calculate the coefficient of rank correlation to measure the degree of relationship between test scores and the number of cars sold.

From a sample of 103 cases, \(r=.80\). (a) Establish the 95 percent confidence interval for the correlation coefficient. (b) Test the hypothesis that \(\rho=.90\).

The heights of fathers, \(X\), and the heights of their oldest sons when grown, \(\mathrm{Y}\), are given as measurements to the nearest inch. \begin{tabular}{|l|l|l|l|l|l|l|} \hline \(\mathrm{X}\) & 68 & 64 & 70 & 72 & 69 & 74 \\ \hline \(\mathrm{Y}\) & 67 & 68 & 69 & 73 & 66 & 70 \\ \hline \end{tabular} (a) Construct a scattergram. (b) Find the equation of the least squares regression line. (c) Compute the standard error of estimate. (e) Compute the coefficient of correlation \(\mathrm{r}\).

Show that if \((\mathrm{X}, \mathrm{Y})\) has a bivariate normal distribution, then the marginal distributions of \(\mathrm{X}\) and \(\mathrm{Y}\) are univariate normal distributions; that is, \(\mathrm{X}\) is normally distributed with mean \(\mu_{\mathrm{x}}\) and variance \(\sigma^{2} \mathrm{x}\) and \(\mathrm{Y}\) is normally distributed with mean \(\mu_{\mathrm{y}}\) and variance \(\sigma^{2} \mathrm{y}\).

Suppose a new method is designed for determining the amount of magnesium in sea water. If the method is a good one, there will be a strong relation between the true amount of magnesium in the water and the amount indicated by this new method. 10 samples of "sea water" are prepared, each sample containing a known amount of magnesium. The samples are then tested by the new method. The data from this experiment is present in the form of the summary statistics. \(\mathrm{X}\) represents the true amount of \(\mathrm{Mg}\) present and \(\mathrm{Y}\) the corresponding amount determined by the new method. The data is $$ \begin{array}{lll} \sum X_{i}=311 & \sum X_{i}^{2}=10,100 \quad \sum X Y=10,074 \\ \sum Y_{i}=310.1 & \text { and } \sum Y_{i}^{2}=10,055.09 \end{array} $$ Find the regression equation, the standard error \(\sigma\) and \(\mathrm{r}^{2}\), the coefficient of variation. Develop \(95 \%\) confidence intervals for \(\alpha\) and \(\beta^{\wedge}\) and test the hypotehsis that the true equation has parameters \(\alpha=0\) and \(\beta=1\).

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