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A sports magazine reports that the people who watch Monday night football games on television are evenly divided between men and women. Out of a random sample of 400 people who regularly watch the Monday night game, 220 are men. Using a \(.10\) level of significance, can be conclude that the report is false?

Short Answer

Expert verified
At a \(0.10\) level of significance, the calculated p-value (\(0.0456\)) is less than the significance level. Therefore, we reject the null hypothesis and conclude that the report is false. The proportions of men and women watching the Monday night football games are not evenly divided.

Step by step solution

01

State the Hypotheses

The null hypothesis (H0) will state that the proportion of men watching the Monday night football game is 50%. The alternative hypothesis (H1) will state that the proportion of men watching is not 50%. In mathematical terms: \(H_0: p = 0.5\) \(H_1: p \neq 0.5\) Where p represents the proportion of men watching.
02

Determine the Level of Significance

The level of significance for this test is given as 0.10. This means that if the p-value (probability of observing the data if the null hypothesis is true) is less than 0.10, we will reject the null hypothesis and consider the report to be false.
03

Calculate the Test Statistic

We will use the z-test for proportions to calculate the test statistic. First, we need to find the sample proportion of men watching (\(\hat{p}\)): \(\hat{p} = \frac{220}{400} = 0.55\) The standard error of the proportion can be calculated using the null hypothesis value (\(p = 0.5\)): \(SE = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5(1-0.5)}{400}} = 0.025\) The z-test statistic is then calculated as: \(z = \frac{\hat{p} - p}{SE} = \frac{0.55 - 0.5}{0.025} = 2\)
04

Calculate the p-value

Since this is a two-tailed test (we're looking for a difference in either direction), we need to find the probability on both tails. Using the z-table or a calculator, we find the p-value associated with a z-score of 2: P(Z > 2) = 0.0228 Since this is a two-tailed test, we multiply this value by 2: p-value = 2 * 0.0228 = 0.0456
05

Make the Decision

Compare the p-value with the level of significance: 0.0456 < 0.10 Since the p-value is less than the significance level, we reject the null hypothesis. There is sufficient evidence to conclude that the report is false and the proportions of men and women watching the Monday night football games are not evenly divided.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Test for Proportions
The z-test for proportions is a statistical method used to determine if there is a significant difference between a sample proportion and a known population proportion. This test is particularly useful when dealing with categorical data, like the proportion of men watching a football game. To carry out a z-test for proportions, you'll need:
  • The sample proportion \(\hat{p}\)
  • The assumed population proportion \(p\) under the null hypothesis
  • The sample size \(n\)
The formula for the z-test statistic is:\[ z = \frac{\hat{p} - p}{SE} \]Where \(SE\) is the standard error, calculated as \(SE = \sqrt{\frac{p(1-p)}{n}}\). A large z-score (in absolute value) indicates a stronger deviation from the null hypothesis. If this z-score corresponds to a p-value that is less than the level of significance, we reject the null hypothesis.
P-Value
The p-value in hypothesis testing quantifies the probability of obtaining a result as extreme as, or more extreme than, the observed results, assuming that the null hypothesis is true. It's a crucial part of making a statistical decision.
In our example:
  • We calculated a p-value of 0.0456 for a z-score of 2.
  • The p-value was compared with a predefined level of significance (0.10) to make a decision.
A small p-value (typically \(< 0.05\) or \(< 0.10\)) indicates strong evidence against the null hypothesis, leading to its rejection. The lower the p-value, the greater the statistical significance of the observed difference.
Level of Significance
The level of significance, denoted by \(\alpha\), is a threshold set by the researcher that determines the probability of rejecting the null hypothesis when it's actually true (false positive). It represents the maximum risk we are willing to take in concluding that there's a significant effect when there isn't one.In the context of the exercise:
  • The level of significance was set at 0.10.
  • This means there is a 10% risk that we might incorrectly reject the true null hypothesis.
Choosing a level of significance involves balancing the risk of Type I errors (rejecting a true null hypothesis) and Type II errors (failing to reject a false null hypothesis).
Null Hypothesis
The null hypothesis, often denoted by \(H_0\), is a statement that there is no effect or no difference in the context of the statistical test being performed. It serves as the default or baseline assumption that any observed deviation in the data is due to random chance.In the problem at hand:
  • The null hypothesis asserts that the proportion of men watching Monday night football is 50%.
  • This provides a basis against which we compare our sample data.
If our test provides sufficient evidence to reject \(H_0\), we consider an alternative explanation for our data.
Remember that failing to reject the null hypothesis does not prove it true; it simply suggests that there is not enough evidence against it under the specified significance level.
Alternative Hypothesis
The alternative hypothesis, denoted by \(H_1\) or \(H_a\), is the statement that contradicts the null hypothesis. It suggests that there is an actual effect or difference, which we aim to support with our data.For this particular example:
  • The alternative hypothesis posits that the proportion of men watching is not 50% \((H_1: p eq 0.5)\).
  • This implies a two-tailed test since we are interested in deviations on both sides of the hypothesized proportion.
Supporting the alternative hypothesis would mean rejecting the null hypothesis based on the data. Thus, the alternative hypothesis represents the assertion we hope to find sufficient statistical evidence for. Understanding and clearly stating it is essential for setting up any hypothesis test.

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Most popular questions from this chapter

Suppose we have a binomial distribution for which \(\mathrm{H}_{0}\) is that the probability of success on a single trial, \(\mathrm{p}=1 / 2\). Suppose also that \(\mathrm{H}_{1}\) is \(\mathrm{p}=2 / 3\). Show how the power of the normal approximation to the binomial test increases as n increases by finding the critical value, \(K\), and the type II error, \(\beta\), for each of the following values of n: \(36,64,100,144\), and 196 . For which of these values of \(\mathrm{N}\) does \(\beta\) first fall as low as \(.5 ?\) Use \(\alpha=.01\).

Refer to the data in the previous problem concerning the Selective Service data to test the hypothesis that the proportions are equal against the alternative that \(\pi_{1}>\pi_{2}\). Use \(\alpha=.05\).

For the following samples of data, compute \(\mathrm{t}\) and determine whether \(\mu_{1}\) is significantly less than \(\mu_{2}\). For your test use a level of significance of \(10 .\) Sample \(1: \mathrm{n}=10, \underline{\mathrm{X}}=10.0\) \(\mathrm{S}=5.2\); sample \(2: \mathrm{n}=10, \underline{\mathrm{X}}=13.3, \mathrm{~S}=5.7\)

A man has just purchased a trick die which was advertised as not yielding the proper proportion of sixes. He wonders whether the advertising was correct, and tests the advertising claim by rolling the die 100 times. The 100 rolls yielded ten sixes. Should he conclude that the advertising was legitimate?

All boxes of a particular type of detergent indicate that they contain 21 ounces of detergent. A government agency receives many consumer complaints that the boxes contain less than 21 ounces. To check the consumers' complaints at the \(5 \%\) level of significance, the government agency buys 100 boxes of this detergent and finds that \(\underline{\mathrm{X}}=20.5\) ounces and \(\mathrm{S}=2\) ounces. Should the government agency order the seller to put more detergent into its boxes?

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