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The last \(21 \mathrm{Mr}\). Americas' had a variance of \(6 \mathrm{in}^{2}\) in their chest size while the last \(16 \mathrm{Mr}\). U.S.A.s' had a variance of 4 in \(^{2}\) in the same category. Assuming normality, find a \(.98\) confidence interval estimate of [(Variance Mr. America) / (Variance Mr. U.S.A.)] .

Short Answer

Expert verified
The \(98\%\) confidence interval estimate for the ratio of Mr. America's chest size variance to Mr. U.S.A.'s chest size variance is \(0.414 < \frac{\sigma_1^2}{\sigma_2^2} < 1.524\).

Step by step solution

01

Identify the given information

We have the following information: - Sample size of Mr. America: \(n_1 = 21\) - Variance of Mr. America: \(s_1^2 = 6\text{ in}^2\) - Sample size of Mr. U.S.A: \(n_2 = 16\) - Variance of Mr. U.S.A: \(s_2^2 = 4\text{ in}^2\) - Confidence level: \(0.98\)
02

Calculate the degrees of freedom for both samples

Degrees of freedom for the two samples are: - \(df_1 = n_1 - 1 = 21 - 1 = 20\) - \(df_2 = n_2 - 1 = 16 - 1 = 15\)
03

Find the F-distribution critical values

We need to find the critical values \(F_{\alpha/2}\) and \(F_{1-\alpha/2}\) from an F-distribution table. Since the confidence level is \(0.98\), the significance level (\(\alpha\)) is \(1-0.98=0.02\). Therefore, we have \(\alpha/2=0.01\). Now, we look for the F-distribution table values corresponding to \(0.01\) and \(0.99\) with degrees of freedom \(df_1 = 20\) and \(df_2 = 15\). From the F-distribution table, we find the following values: - \(F_{0.01}(20,15) \approx 0.254\) - \(F_{0.99}(20,15) \approx 3.62\)
04

Calculate the confidence interval for the ratio of variances

Now, we just need to put the values in the formula for the confidence interval estimate of the ratio of variances: \[\frac{s_1^2}{s_2^2} \cdot \frac{1}{F_{1-\alpha/2}(df_1, df_2)} < \frac{\sigma_1^2}{\sigma_2^2} < \frac{s_1^2}{s_2^2} \cdot F_{\alpha/2}(df_1, df_2)\] Substituting the values, we get: \[\frac{6}{4} \cdot \frac{1}{3.62} < \frac{\sigma_1^2}{\sigma_2^2} < \frac{6}{4} \cdot 0.254\] Calculating the values: \[0.414 < \frac{\sigma_1^2}{\sigma_2^2} < 1.524\]
05

Interpret the result

The confidence interval estimate for the ratio of Mr. America's chest size variance to Mr. U.S.A.'s chest size variance is \(0.414 < \frac{\sigma_1^2}{\sigma_2^2} < 1.524\) with a \(98\%\) confidence level. This means that we are \(98\%\) confident that the true ratio of their chest size variances lies within this interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance Ratio
The variance ratio is a fundamental concept for comparing variability between two different groups. In the given exercise, students are tasked with understanding how the variance of chest sizes among Mr. America contestants compares to that of Mr. U.S.A. contestants. To do so, one calculates the ratio of the variances of the two groups, denoted as \( \frac{s_1^2}{s_2^2} \).

Why is this important? Variance measures how data points differ from the mean, and in many scientific inquiries, comparing these measures can reveal important differences between groups. For example, a higher variance in chest size among Mr. America contestants might suggest a more diverse group of body types compared to Mr. U.S.A. contestants. When we calculate this ratio, we assess whether these variances are significantly different or not.
F-distribution
The F-distribution plays a crucial role in performing hypothesis testing when comparing two variances, such as in the exercise above. It is a continuous probability distribution that arises naturally when considering the ratio of two sample variances drawn from normally distributed populations.

Understanding the shape and behavior of the F-distribution is fundamental when working with variance ratio tests. It is characterized by two parameters: the degrees of freedom of the numerator and the degrees of freedom of the denominator. Different combinations of degrees of freedom give rise to different shapes of the F-distribution. The critical values of an F-distribution are used to establish the boundaries of the confidence interval for the variance ratio, and they change based on the chosen significance level and the degrees of freedom.
Degrees of Freedom
Degrees of freedom, often abbreviated as \(df\), are a concept tied deeply to the notion of sample size and the number of independent values that can vary. To find the degrees of freedom for each sample in our problem, we subtract 1 from each respective sample size: \(df_1 = n_1 - 1\) and \(df_2 = n_2 - 1\). These values are then used in conjunction with the F-distribution.

The concept of degrees of freedom is crucial since it adjusts the calculation of various statistics to account for the size of the sample. In essence, they provide a measure of how 'free' the data are to vary and are necessary for accurately determining the critical values from the F-distribution table needed to establish our confidence interval.
Statistical Significance
Statistical significance is a measure of whether the results observed in a study or experiment are due to random chance or if they reflect a true effect. In the context of our exercise, we determine the statistical significance of our findings using confidence levels and significance levels which are complementary (a 0.98 confidence level corresponds to a 0.02 significance level).

When computing a confidence interval, the level of confidence reflects how certain we are that the true value lies within that interval. For instance, a 98% confidence level means we can expect the true variance ratio to fall within our calculated range 98 times out of 100. By using such a high level of confidence, we reduce the likelihood of a Type I error, which is rejecting a true null hypothesis, and thereby infer with high certainty that our findings are significant and not merely due to random variation.

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Most popular questions from this chapter

State briefly the assumptions involved in establishing a confidence interval using the standard normal distribution and the \(t\) distribution.

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