Chapter 11: Problem 346
Given a normal population with \(\mu=25\) and \(\sigma=5\), find the probability that an assumed value of the variable will fall in the interval 20 to 30 .
Short Answer
Expert verified
The probability that a value will fall between 20 and 30 for the given normal population with \(\mu=25\) and \(\sigma=5\) is approximately 0.6826, or 68.26%.
Step by step solution
01
Write down the known parameters and the interval
We are given the following parameters for the normal distribution:
- Mean (\(\mu\)): 25
- Standard deviation (\(\sigma\)): 5
We are asked to find the probability that a value will fall between 20 and 30.
02
Standardize the values using the z-score formula
To find the probability, we need to first standardize the values using the z-score formula:
\(z = \dfrac{X - \mu}{\sigma}\)
Where:
- z is the z-score
- X is the value we want to standardize
- \(\mu\) is the mean
- \(\sigma\) is the standard deviation
Let's standardize the values 20 and 30.
\(z_1 = \dfrac{20-25}{5} = -1\)
\(z_2 = \dfrac{30-25}{5} = 1\)
So, the z-scores for 20 and 30 are -1 and 1, respectively.
03
Find the probabilities for the z-scores using the standard normal distribution table or calculator
Next, we need to find the probabilities for these z-scores using the standard normal distribution table or calculator. The probability that a value falls below a given z-score is represented by the area under the curve to the left of that z-score.
\(P(Z \le z_1) = P(Z \le -1)\)
\(P(Z \le z_2) = P(Z \le 1)\)
You can use a standard normal distribution table or a calculator to find these probabilities:
\(P(Z \le -1) = 0.1587\)
\(P(Z \le 1) = 0.8413\)
04
Calculate the probability that a value will fall between 20 and 30
Finally, to find the probability that a value will fall between 20 and 30, we need to subtract the probability of a value falling below 20 (z-score of -1) from the probability of a value falling below 30 (z-score of 1):
\(P(20 \le X \le 30) = P(-1 \le Z \le 1) = P(Z \le 1) - P(Z \le -1)\)
\(P(20 \le X \le 30) = 0.8413 - 0.1587 = 0.6826\)
So, the probability that a value will fall between 20 and 30 is approximately 0.6826, or 68.26%.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-score
A Z-score is an essential concept in statistics often used to standardize data points relative to the mean of a dataset. Essentially, it tells us how many standard deviations a particular value is from the mean. This standardization allows us to compare scores from different datasets or different ranges.To calculate a Z-score, use the formula:
- \( z = \dfrac{X - \mu}{\sigma} \)
- \( X \) is the value of the element.
- \( \mu \) is the mean of the population.
- \( \sigma \) is the standard deviation of the population.
Standard Deviation
Standard deviation is a vital measure in statistics that quantifies the amount of variation or dispersion in a set of data values. A low standard deviation indicates that data points tend to be close to the mean, while a high standard deviation suggests more spread out data points.It can be mathematically represented as:
- \( \sigma = \sqrt{ \dfrac{1}{N} \sum_{i=1}^{N} (X_i - \mu)^2 } \)
- \( \sigma \) is the standard deviation.
- \( X_i \) are the individual data points.
- \( \mu \) is the mean of the data set.
- \( N \) is the number of data points.
Probability Calculation
Probability calculation in the context of a normal distribution helps determine how likely an event is to occur within a specified range. Once we have the Z-scores, these figures are used to determine the probabilities using a standard normal distribution table or calculator.
To find the probability that a value will fall between two points, you can follow these steps:
- Calculate the Z-scores for the boundary values as shown in previous sections.
- Use a standard normal distribution table to find the probabilities associated with each Z-score.
- Subtract the lower probability from the higher probability to find the probability that a value falls between the two points.