/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Over a period of \(2 m+1\) years... [FREE SOLUTION] | 91Ó°ÊÓ

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Over a period of \(2 m+1\) years the quarterly gas consumption of a particular household may be represented by the model $$ Y_{i j}=\beta_{i}+\gamma j+\varepsilon_{i j}, \quad i=1, \ldots, 4, j=-m,-m+1, \ldots, m-1, m $$ where the parameters \(\beta_{i}\) and \(\gamma\) are unknown, and \(\varepsilon_{i j} \stackrel{\text { iid }}{\sim} N\left(0, \sigma^{2}\right) .\) Find the least squares estimators and show that they are independent with variances \((2 m+1)^{-1} \sigma^{2}\) and \(\sigma^{2} /\left(8 \sum_{i=1}^{m} i^{2}\right)\) Show also that $$ (8 m-1)^{-1}\left[\sum_{i=1}^{4} \sum_{j=-m}^{m} Y_{i j}^{2}-(2 m+1) \sum_{i=1}^{4} \bar{Y}_{i}^{2}-\frac{2 \sum_{j=-m}^{m} j \bar{Y}_{. j}^{2}}{\sum_{i=1}^{m} i^{2}}\right] $$ is unbiased for \(\sigma^{2}\), where \(\bar{Y}_{i}=(2 m+1)^{-1} \sum_{j=-m}^{m} Y_{i j}\) and \(\bar{Y}_{. j}=\frac{1}{4} \sum_{i=1}^{4} Y_{i j}\).

Short Answer

Expert verified
Estimate \(\beta_i\) using \(\bar{Y}_i\), \(\gamma\) with weighted sums, variances are \((2m+1)^{-1}\sigma^2\) and \(\sigma^2/(8\sum_{i=1}^m i^2)\); the expression is unbiased for \(\sigma^2\).

Step by step solution

01

Define the Model

The model is given by the equation \( Y_{ij} = \beta_i + \gamma j + \varepsilon_{ij} \), where \( i = 1, \ldots, 4 \) represents the quarters of a year, and \( j = -m, -m+1, \ldots, m-1, m \) represents the years in the period of \(2m+1\) years.
02

Estimate \(\beta_i\) and \(\gamma\) Using Least Squares

To estimate \(\beta_i\), note that \(\bar{Y}_i = (2m+1)^{-1} \sum_{j=-m}^{m} Y_{ij}\) simplifies the model to remove \(\gamma j\) since the sum of \(j\) terms averages out. The estimate for \(\beta_i\) becomes \(\hat{\beta}_i = \bar{Y}_i\).To estimate \(\gamma\), we first calculate \(\bar{Y}_{.j} = (1/4) \sum_{i=1}^{4} Y_{ij}\). We use the relationship between \(\bar{Y}_{.j}\) and \(\gamma\) across different \(j\), and the equations derived by expansion will yield the estimator, typically involving a weighted average of \(j\).
03

Calculate Variance of the Estimators

The variance of \(\hat{\beta}_i\) can be derived using properties of the normal distribution and the independence of \(\varepsilon_{ij}\), leading to variance \((2m+1)^{-1}\sigma^2\).The variance of \(\hat{\gamma}\) involves a weighted sum over \(j^2\), resulting in \(\sigma^2/(8 \sum_{i=1}^m i^2)\), as the sum accounts for the spread of years.
04

Derive Unbiased Estimator for \(\sigma^2\)

Assess the expression \( (8m-1)^{-1} \left[\sum_{i=1}^{4} \sum_{j=-m}^m Y_{ij}^2 - (2m+1) \sum_{i=1}^{4} \bar{Y}_i^2 - (2/\sum_{i=1}^m i^2) \sum_{j=-m}^m j \bar{Y}_{.j}^2 \right] \). Each term is derived based on the variance and symmetry properties of the design matrix, ensuring that the estimation of \(\sigma^2\) is unbiased by considering the varieties of measurements captured in the model over time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Squares Estimation
Least Squares Estimation is a fundamental method used in statistical analysis to obtain estimates of unknown parameters in a model. It is based on minimizing the sum of the squared differences between the observed values and the values predicted by the model. Therefore, it is often referred to as "fitting the model." In the context of household gas consumption, least squares estimation is employed to estimate the parameters \( \beta_i \) and \( \gamma \) in the model.
  • For \( \beta_i \), the least squares estimator is calculated by averaging the gas consumption data for each quarter over several years. This leads to the estimator \( \hat{\beta}_i = \bar{Y}_i \), where \( \bar{Y}_i \) represents the average consumption.
  • For \( \gamma \), it requires considering the seasonal variation across different years, which is captured by averaging the data across all quarters. This involves a more complex calculation due to the seasonal component \( j \), resulting in a weighted average over time.
By employing least squares estimation, we can effectively model seasonal variations and underlying trends in data, helping to provide accurate, reliable forecasts for future observations.
Unbiased Estimator
An unbiased estimator is a key concept in statistics, referring to an estimator that, on average, returns the true parameter value. This property is essential for ensuring that predictions made from statistical models are reliable, supporting their credibility in applications such as predicting gas consumption.
In our model:
  • The expression for estimating \( \sigma^2 \) is derived to ensure it is unbiased. This involves taking account of the various measurements and their inherent randomness.
  • The estimator formula provided \((8m-1)^{-1} \left[ \sum_{i=1}^{4} \sum_{j=-m}^m Y_{ij}^2 - (2m+1) \sum_{i=1}^{4} \bar{Y}_i^2 - \frac{2 \sum_{j=-m}^m j \bar{Y}_{.j}^2}{\sum_{i=1}^m i^2} \right]\) takes into consideration all sources of variability, providing a consistent and accurate measure of \( \sigma^2 \).
Using an unbiased estimator guarantees that we do not systematically overestimate or underestimate the true value, which can significantly impact the analysis and interpretation of statistical data.
Variance Calculation
Variance calculation is crucial for understanding the spread or dispersion of data in statistical models. For parameter estimation, it examines how much estimates might vary between different samples.
  • The variance of \( \hat{\beta}_i \) is straightforward because it involves averaging over a defined period. The expression \( (2m+1)^{-1}\sigma^2 \) ensures that we account for variability in quarterly data over several years.
  • The variance of \( \hat{\gamma} \) is more complex due to the influence of the term \( j \). It uses the inverse of the sum across squared time periods: \( \sigma^2/(8 \sum_{i=1}^m i^2) \), reflecting the spread of the estimations due to the seasonal component.
By performing these calculations, we identify how precisely we can estimate the underlying model parameters. Understanding this precision helps in constructing better models and making more confident predictions.

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Most popular questions from this chapter

Suppose that the straight-line regression model \(y=\beta_{0}+\beta_{1} x+\varepsilon\) is fitted to data in which \(x_{1}=\cdots=x_{n-1}=-a\) and \(x_{n}=(n-1) a\), for some positive \(a .\) Show that although \(y_{n}\) completely determines the estimate of \(\beta_{1}, C_{n}=0 .\) Is Cook's distance an effective measure of influence in this situation?

The angles of the triangle \(\mathrm{ABC}\) are measured with \(\mathrm{A}\) and \(\mathrm{B}\) each measured twice and \(\mathrm{C}\) three times. All the measurements are independent and unbiased with common variance \(\sigma^{2}\). Find the least squares estimates of the angles \(\mathrm{A}\) and \(\mathrm{B}\) based on the seven measurements and calculate the variance of these estimates.

Over a period of 90 days a study was carried out on 1500 women. Its purpose was to investigate the relation between obstetrical practices and the time spent in the delivery suite by women giving birth. One thing that greatly affects this time is whether or not a woman has previously given birth. Unfortunately this vital information was lost, giving the researchers three options: (a) abandon the study; (b) go back to the medical records and find which women had previously given birth (very time-consuming); or (c) for each day check how many women had previously given birth (relatively quick). The statistical question arising was whether (c) would recover enough information about the parameter of interest. Suppose that a linear model is appropriate for log time in delivery suite, and that the log time for a first delivery is normally distributed with mean \(\mu+\alpha\) and variance \(\sigma^{2}\), whereas for subsequent deliveries the mean time is \(\mu\). Suppose that the times for all the women are independent, and that for each there is a probability \(\pi\) that the labour is her first, independent of the others. Further suppose that the women are divided into \(k\) groups corresponding to days and that each group has size \(m\); the overall number is \(n=m k\). Under (c), show that the average log time on day \(j, Z_{j}\), is normally distributed with mean \(\mu+R_{j} \alpha / m\) and variance \(\sigma^{2} / m\), where \(R_{j}\) is binomial with probability \(\pi\) and denominator \(m\). Hence show that the overall log likelihood is $$ \ell(\mu, \alpha)=-\frac{1}{2} k \log \left(2 \pi \sigma^{2} / m\right)-\frac{m}{2 \sigma^{2}} \sum_{j=1}^{k}\left(z_{j}-\mu-r_{j} \alpha / m\right)^{2} $$ where \(z_{j}\) and \(r_{j}\) are the observed values of \(Z_{j}\) and \(R_{j}\) and we take \(\pi\) and \(\sigma^{2}\) to be known. If \(R_{j}\) has mean \(m \pi\) and variance \(m \tau^{2}\), show that the inverse expected information matrix is $$ I(\mu, \alpha)^{-1}=\frac{\sigma^{2}}{n \tau^{2}}\left(\begin{array}{cc} m \pi^{2}+\tau^{2} & -m \pi \\ -m \pi & m \end{array}\right) $$ (i) If \(m=1, \tau^{2}=\pi(1-\pi)\), and \(\pi=n_{1} / n\), where \(n=n_{0}+n_{1}\), show that \(I(\mu, \alpha)^{-1}\) equals the variance matrix for the two-sample regression model. Explain why. (ii) If \(\tau^{2}=0\), show that neither \(\mu\) nor \(\alpha\) is estimable; explain why. (iii) If \(\tau^{2}=\pi(1-\pi)\), show that \(\mu\) is not estimable when \(\pi=1\), and that \(\alpha\) is not estimable when \(\pi=0\) or \(\pi=1\). Explain why the conditions for these two parameters to be estimable differ in form. (iv) Show that the effect of grouping, \((m>1)\), is that \(\operatorname{var}(\widehat{\alpha})\) is increased by a factor \(m\) regardless of \(\pi\) and \(\sigma^{2}\) (v) It was known that \(\sigma^{2} \doteq 0.2, m \doteq 1500 / 90, \pi \doteq 0.3\). Calculate the standard error for \(\widehat{\alpha}\). It was known from other studies that first deliveries are typically 20-25\% longer than subsequent ones. Show that an effect of size \(\alpha=\log (1.25)\) would be very likely to be detected based on the grouped data, but that an effect of size \(\alpha=\log (1.20)\) would be less certain to be detected, and discuss the implications.

Suppose that random variables \(Y_{g j}, j=1, \ldots, n_{g}, g=1, \ldots, G\), are independent and that they satisfy the normal linear model \(Y_{g j}=x_{g}^{\mathrm{T}} \beta+\varepsilon_{g j}\). Write down the covariate matrix for this model, and show that the least squares estimates can be written as \(\left(X_{1}^{\mathrm{T}} W X_{1}\right)^{-1} X_{1}^{\mathrm{T}} W Z\), where \(W=\operatorname{diag}\left\\{n_{1}, \ldots, n_{G}\right\\}\), and the \(g\) th element of \(Z\) is \(n_{g}^{-1} \sum_{j} Y_{g j} .\) Hence show that weighted least squares based on \(Z\) and unweighted least squares based on \(Y\) give the same parameter estimates and confidence intervals, when \(\sigma^{2}\) is known. Why do they differ if \(\sigma^{2}\) is unknown, unless \(n_{g} \equiv 1 ?\) Discuss how the residuals for the two setups differ, and say which is preferable for modelchecking.

Consider a normal linear regression \(y=\beta_{0}+\beta_{1} x+\varepsilon\) in which the parameter of interest is \(\psi=\beta_{0} / \beta_{1}\), to be estimated by \(\widehat{\psi}=\widehat{\beta}_{0} / \widehat{\beta}_{1} ;\) let \(\operatorname{var}\left(\widehat{\beta}_{0}\right)=\sigma^{2} v_{00}, \operatorname{cov}\left(\widehat{\beta}_{0}, \widehat{\beta}_{1}\right)=\sigma^{2} v_{01}\) and \(\operatorname{var}\left(\widehat{\beta}_{1}\right)=\sigma^{2} v_{11}\) (a) Show that $$ \frac{\widehat{\beta}_{0}-\psi \widehat{\beta}_{1}}{\left\\{s^{2}\left(v_{00}-2 \psi v_{01}+\psi^{2} v_{11}\right)\right\\}^{1 / 2}} \sim t_{n-p} $$ and hence deduce that a \((1-2 \alpha)\) confidence interval for \(\psi\) is the set of values of \(\psi\) satisfying the inequality $$ \widehat{\beta}_{0}^{2}-s^{2} t_{n-p}^{2}(\alpha) v_{00}+2 \psi\left\\{s^{2} t_{n-p}^{2}(\alpha) v_{01}-\beta_{0} \beta_{1}\right\\}+\psi^{2}\left\\{\widehat{\beta}_{1}^{2}-s^{2} t_{n-p}^{2}(\alpha) v_{11}\right\\} \leq 0 $$ How would this change if the value of \(\sigma\) was known? (b) By considering the coefficients on the left-hand-side of the inequality in (a), show that the confidence set can be empty, a finite interval, semi- infinite intervals stretching to \(\pm \infty\), the entire real line, two disjoint semi-infinite intervals - six possibilities in all. In each case illustrate how the set could arise by sketching a set of data that might have given rise to it. (c) A government Department of Fisheries needed to estimate how many of a certain species of fish there were in the sea, in order to know whether to continue to license commercial fishing. Each year an extensive sampling exercise was based on the numbers of fish caught, and this resulted in three numbers, \(y, x\), and a standard deviation for \(y, \sigma\). A simple model of fish population dynamics suggested that \(y=\beta_{0}+\beta_{1} x+\varepsilon\), where the errors \(\varepsilon\) are independent, and the original population size was \(\psi=\beta_{0} / \beta_{1}\). To simplify the calculations, suppose that in each year \(\sigma\) equalled 25 . If the values of \(y\) and \(x\) had been \(\begin{array}{cccccc}y: & 160 & 150 & 100 & 80 & 100 \\ x: & 140 & 170 & 200 & 230 & 260\end{array}\) after five years, give a \(95 \%\) confidence interval for \(\psi\). Do you find it plausible that \(\sigma=25\) ? If not, give an appropriate interval for \(\psi\).

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