Chapter 2: Problem 35
Given the vectors $$ \begin{aligned} &\mathbf{u}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}-\hat{\mathbf{k}} \\ &\mathbf{v}=\mathbf{i}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}} \\ &\mathbf{w}=\mathbf{i}-\hat{\mathbf{k}} \end{aligned} $$ If the volume of the parallelopiped having \(-\mathrm{cu}, \mathbf{v}\) and \(\mathrm{cw}\) as concurrent edges, is 8 , then \(c\) is equal to (a) \(\pm 2\) (b) 4 (c) 8 (d) Cannot be determined
Short Answer
Step by step solution
Understand the Volume of a Parallelepiped
Compute \( \mathbf{b} \times \mathbf{c} \)
Compute the Scalar Triple Product
Solve for \( c \)
Conclude the Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Scalar Triple Product
- It results in a scalar value: As opposed to a vector, the result is a single numerical expression.
- Geometrical interpretation: The absolute value of this scalar gives the volume of the parallelepiped.
Cross Product
- Magnitude: The magnitude of the cross product equals the area of the parallelogram that the vectors span. It is given by \( |\mathbf{a}||\mathbf{b}|\sin(\theta) \), where \(\theta\) is the angle between \(\mathbf{a}\) and \(\mathbf{b}\).
- Direction: The result is a vector perpendicular to both \(\mathbf{a}\) and \(\mathbf{b}\), determined by the right-hand rule.
Parallelepiped Volume
- Volume formula: The volume \( V \) is given by \( |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| \).
- Application in the exercise: In the current problem, the calculated scalar triple product equates to \( 2c^2 \), which when set equal to the known volume, results in solving for the constant \(c\).
Vectors in 3D
- Representation: A vector \( \mathbf{a} \) can be written as \( a_x \hat{\mathbf{i}} + a_y \hat{\mathbf{j}} + a_z \hat{\mathbf{k}} \).
- Operations: Key operations in 3D vectors, such as addition, subtraction, dot product, and cross product, form the basis for analyzing spatial relationships and physical phenomena.