Chapter 2: Problem 233
Given, two vectors are \(\mathbf{i}-\mathbf{j}\) and \(\mathbf{i}+2 \dot{j}\) the unit vector coplanar with the two vectors and perpendicular to first is \mathrm{\\{} [ A I E E E ~ 2 0 0 2 ] ~ (a) \(\frac{1}{\sqrt{2}}(\hat{i}+\mathrm{j})\) (b) \(\frac{1}{\sqrt{5}}(2 \hat{i}+\mathrm{j})\) (c) \(\pm \frac{1}{\sqrt{2}}(\mathrm{i}+\mathrm{j})\) (d) None of these
Short Answer
Step by step solution
Identify the Perpendicular Requirement
Apply Perpendicular Condition
Use Coplanarity Condition
Determine the Unit Vector
Validate Choice Against Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Vector
In mathematical terms, if a vector is represented as \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} \), then the magnitude \(|\mathbf{v}|\) is calculated as \( \sqrt{a^2 + b^2} \).
- If \( |\mathbf{v}| = 1 \), then \( \mathbf{v} \) is a unit vector.
- If \( |\mathbf{v}| eq 1 \), the vector can be converted to a unit vector by dividing each component by its magnitude.
Perpendicular Vectors
The dot product of two vectors \( \mathbf{a} \) and \( \mathbf{b} \) is given by \( \mathbf{a} \cdot \mathbf{b} = 0 \) if they are perpendicular. This means each component of one vector, when multiplied by the corresponding component of the other vector, sums to zero.
- Example: Vectors \( \mathbf{a} = a\mathbf{i} + b\mathbf{j} \) and \( \mathbf{b} = c\mathbf{i} + d\mathbf{j} \) are perpendicular if \( ac + bd = 0 \).
Coplanarity
For two given vectors, if a third vector lies on the same plane as these vectors, it is coplanar with them. Practically, in 3D, if three vectors \( \mathbf{a} \), \( \mathbf{b} \), and \( \mathbf{c} \) are coplanar, the scalar triple product is zero: \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = 0 \).
- This condition ensures that \( \mathbf{c} \) is a linear combination of \( \mathbf{a} \) and \( \mathbf{b} \).
Dot Product
The formula for the dot product of two vectors \( \mathbf{a} = a_1\mathbf{i} + b_1\mathbf{j} \) and \( \mathbf{b} = a_2\mathbf{i} + b_2\mathbf{j} \) is:
\[\mathbf{a} \cdot \mathbf{b} = a_1a_2 + b_1b_2\]
- If the dot product is zero, the vectors are perpendicular.
- The dot product can help determine the angle between two vectors using the formula \( \mathbf{a} \cdot \mathbf{b} = |\mathbf{a}||\mathbf{b}|\cos\theta \).