/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A double ordinate of the parabol... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A double ordinate of the parabola \(y^{2}=8 p x\) is of length \(16 p\). The angie subtended by it at the vertex of the parabola is: (a) \(\pi / 4\) (b) \(\pi / 2\) (c) \(\pi\) (d) \(\pi / 3\)

Short Answer

Expert verified
The angle subtended by the double ordinate of the parabola at its vertex is \(\pi\). So, the correct option is (c).

Step by step solution

01

Understanding the Problem

The equation of the parabola is given as \(y^{2}=8px\). In a parabola, the length of the double ordinate is \(4p\). We are given that this length is \(16p\). Thus, we need to equate these to find the value of the actual 'p'.
02

Find the Actual 'p' Value

Since the length of the double ordinate is given as \(16p\), and we know that this length should be \(4p\) in a parabola, we equate these to find 'p'. So, \(4p=16p\). Solving this, we get 'p' as 0.
03

Substitute 'p' Value in Parabola Equation

Substitute the obtained 'p' value in the given equation of the parabola \(y^{2}=8px\). So, the equation becomes \(y^{2}=8*0*x\). This implies that \(y=0\). Therefore, we can see that, when 'p' is 0, the given equation transforms into the equation of a straight line parallel to x-axis.
04

Determine the Angle Subtended

Since the line is parallel to x-axis which is basically a horizontal straight line, the angle it subtends at the vertex of the parabola is \(\pi\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

double ordinate
A double ordinate in a parabola refers to a line segment that passes through the parabola and is perpendicular to the axis of symmetry. This segment essentially mirrors itself on either side of the axis. In the parabola with the equation \( y^2 = 8px \), the length of a general double ordinate corresponds to \( 4p \). In the given problem, the double ordinate is specified to be \( 16p \) in length. This is a hint to find the relationship of 'p' with the parabola's structure. By comparing this with the standard \( 4p \), the problem intends for us to solve \( 4p = 16p \). From this, we deduce that the length configuration (and effectively the value of 'p') does not realistically hold, signaling a need for typical values, often influencing our understanding in advanced equations of a parabola.
angle subtended
The angle subtended by a line segment at a point is the angle formed by drawing lines from the point to the ends of the segment. For curves like parabolas, this concept applies to angles formed at particular reference points, such as the vertex.For the given problem, once we substitute and simplify within the equation \( y^2 = 8px \), we find that 'p' being zero results in a horizontal line. This line, spanning like an infinite flattening of the parabola graph, still forms an angle, especially visualized at the vertex.In context, since the line becomes parallel to the x-axis, it subtends a maximum angle of \( \pi \), signifying a complete semicircular or straight line angle measurement.
vertex of parabola
A parabola's vertex is a critical point that acts as the "tip" or "point of turning" of the curve. For the parabola equation \( y^2 = 8px \), the vertex is located at the origin point \((0,0)\) in standard coordinate grids.In the problem, understanding the behavior of the vertex is crucial when analyzing the effect of the double ordinate's position. Given 'p' set to zero, theoretically flattens the curve and the vertex still serves as a reference point for assessing angles and structural distinctions within the parabola.This concept is crucial because it aids in visualizing how the line configurations change when intersected perpendicularly, forming various potential angles at these central vertices.
equation of parabola
The equation of a parabola is a mathematical representation that defines its form and extent in a coordinate system. The exercise starts with the equation \( y^2 = 8px \), which implies a horizontal orientation of the parabola.Mathematically, different values of 'p' shape the parabola's width and orientation. When 'p' was solved to be zero in the problem, the equation evolves into \( y^2 = 0 \), simplifying to \( y = 0 \). This adjustment converts the parabola equation into that of a horizontal line. Understanding how 'p', the focal distance, influences this setup is vital for recognizing changes in parabola shape or transition to alternate forms like linear representations in this case. With the transformation, this equation no longer holds the typical parabolic curvature.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the normals at two points \(P\) and \(Q\) of a parabola \(y^{2}=4 a x\) intersect at a third point \(R\) on the curve, then the product of ordinates of \(P\) and \(Q\) is : (a) \(4 a^{2}\) (b) \(2 a^{2}\) \(\begin{array}{ll}\text { (c) }-4 a^{2} & \text { (d) } 8 a^{2}\end{array}\)

Through the vertex \(O\) of the parabola \(y^{2}=4 a x\) two chords \(O A\) and \(O B\) are drawn and the circle on \(O A\) and \(O B\) as diameters intersect in \(C\) if \(m_{1}, m_{2}\) and \(m_{3}\) be the slope of tangents to parabola at \(A\) and \(B\) and line \(O C\) respectively, show that $$ m_{1}+m_{2}+2 m_{1} m_{2} m_{3}=0 $$

A circle is described whose centre is the vertex and whose diameter is three quarters of the larus rectum of a parabola \(y^{2}=4 \alpha x\). Prove that the common chord of the circle and parabola bisects the distance between the vertex and the focus.

A chord \(P P\) ' of a parabola cuts the axis of the parabola at 0 . The feet of the perpendiculars from \(P\) and \(P\) on the axis are \(M\) and \(M^{\prime}\) respectively. If \(V\) is the vertex then \(V M\), VO, \(V M\) ' are in : (a) \(\mathrm{AP}\) (b) \(\mathrm{GP}\) (c) \(\mathrm{HP}\) (d) none of these

\(P C\) is the normal at \(P\) to the parabola \(y^{2}=4 a x, C\) being on the axis. \(C P\) is produced outwards to \(Q\) so that \(P Q=C P\); Show that the locus of \(Q\) is a parabola and that the locus of the intersection of the tangents at \(P\) and \(Q\) to the parabola on which they lie is $$ y^{2}(x+4 a)+16 a^{3}=0 $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.