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Show that the range of \(\tanh x\) is (-1,1) . What are the ranges of coth, sech, and csch? (Use the fact that they are reciprocal functions.)

Short Answer

Expert verified
The range of \(\tanh x\) is (-1,1), \(\coth x\) is (-∞,-1)∪(1,∞), \(\text{sech} \, x\) is (0,1], and \(\text{csch} \, x\) is (-∞,-1]∪[1,∞).

Step by step solution

01

Understanding Hyperbolic Functions

The hyperbolic tangent function, \(\tanh x\), is defined as \(\tanh x = \frac{\sinh x}{\cosh x}\). It is known that \(\sinh x\) and \(\cosh x\) are the hyperbolic sine and cosine functions, respectively.
02

Derive the Range of \(\tanh x\)

By dividing \(\sinh x = \frac{e^x - e^{-x}}{2}\) by \(\cosh x = \frac{e^x + e^{-x}}{2}\), we get \(\tanh x = \frac{e^x - e^{-x}}{e^x + e^{-x}}\). For very large \(x\), \(\tanh x\) approaches 1 since \(e^x \) dominates both the numerator and the denominator. Similarly, as \(x\) approaches negative infinity, \(\tanh x\) approaches -1. Thus, \(\tanh x\) is asymptotically bound within (-1, 1) as \(x\) ranges over all real numbers.
03

Range of \(\coth x\)

The hyperbolic cotangent function, \(\coth x\), is defined as \(\coth x = \frac{\cosh x}{\sinh x}\). Since \(\sinh x = 0\) at \(x = 0\), \(\coth x\) is undefined at \(x = 0\). For positive \(x\), \(\coth x\) approaches 1 as \(x\) increases, and for negative \(x\), \(\coth x\) approaches -1 as \(x\) decreases. Therefore, except at \(x = 0\), \(\coth x\) ranges over (-∞, -1) ∪ (1, ∞).
04

Range of \(\text{sech}\,x\)

The hyperbolic secant function, \(\text{sech} \, x\), is defined as \(\text{sech} \, x = \frac{1}{\cosh x}\). Since \(\cosh x\) is always positive and its minimum value is 1 at \(x = 0\), the range of \(\text{sech} \, x\) is (0, 1].
05

Range of \(\text{csch}\,x\)

The hyperbolic cosecant function, \(\text{csch} \, x\), is defined as \(\text{csch} \, x = \frac{1}{\sinh x}\). Since \(\sinh x\) is 0 at \(x = 0\) and continuously positive or negative elsewhere, \(\text{csch} \, x\) is undefined at \(x = 0\) and can take values in (-∞, -1] ∪ [1, ∞).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding \( \tanh x \)
The hyperbolic tangent function, commonly written as \( \tanh x \), is a fascinating function of hyperbolic mathematics. It is defined as \( \tanh x = \frac{ \sinh x }{ \cosh x } \). The symbols here represent other hyperbolic functions: \( \sinh x \) is the hyperbolic sine function and \( \cosh x \) is the hyperbolic cosine function. Both of these functions help form the unique characteristics of \( \tanh x \).

In simple terms, \( \tanh x \) can be expressed as \( \frac{ e^x - e^{-x} }{ e^x + e^{-x} } \). This form helps us to understand the behavior of the function as \( x \) increases or decreases. As \( x \) moves to very high values (towards infinity), the exponential part \( e^x \) in both numerator and denominator becomes dominant. Hence, \( \tanh x \) gets closer and closer to 1. Conversely, as \( x \) decreases to very low values (towards negative infinity), \( \tanh x \) approaches -1. Thus, the range of \( \tanh x \) is strictly between -1 and 1, which can be written as (-1, 1). This means \( \tanh x \) never actually reaches these values but can come infinitely close.
Exploring \( \coth x \)
The hyperbolic cotangent, denoted as \( \coth x \), offers another aspect of hyperbolic functions. It is expressed via the formula \( \coth x = \frac{ \cosh x }{ \sinh x } \). This definition makes it clear that \( \coth x \) is a reciprocal function similar to the tangent and cotangent relationship in trigonometry.

There is an important characteristic of \( \coth x \) at zero. Since \( \sinh x = 0 \) when \( x = 0 \), \( \coth x \) becomes undefined at this point. However, as \( x \) moves away from zero, \( \coth x \) starts behaving differently based on the direction of \( x \). For positive \( x \), it approaches 1 as \( x \) increases, and for negative \( x \), it moves toward -1 as \( x \) decreases. The range of \( \coth x \), therefore, is all real numbers except within the interval (-1, 1), specifically (-∞, -1) ∪ (1, ∞). It shows that \( \coth x \) can take values arbitrarily far from zero but never between -1 and 1.
Investigating \( \text{sech} \, x \)
The hyperbolic secant function, written as \( \text{sech} \, x \), is another intriguing hyperbolic function. Its definition is given by \( \text{sech} \, x = \frac{1}{\cosh x} \).

Notably, \( \cosh x \) holds its smallest value of 1 at \( x = 0 \), affecting the behavior of \( \text{sech} \, x \). Because \( \cosh x \) is positive for all real \( x \), \( \text{sech} \, x \) also remains positive. At \( x = 0 \), \( \text{sech} \, x \) achieves its maximum value, which is 1. As \( x \) deviates from zero, whether it increases or decreases, \( \text{sech} \, x \) gets closer to 0 but never quite reaches it. Thus, the range of \( \text{sech} \, x \) can be described as (0, 1]. This interval shows that \( \text{sech} \, x \) can be as close to zero as possible but always remains positive.
Comprehending \( \text{csch} \, x \)
The hyperbolic cosecant function, noted as \( \text{csch} \, x \), is the reciprocal of the hyperbolic sine function, defined by \( \text{csch} \, x = \frac{1}{\sinh x} \).

Much like its trigonometric counterpart, its behavior is dramatically impacted by \( \sinh x \)'s properties. As \( \sinh x = 0 \) at \( x = 0 \), \( \text{csch} \, x \) is undefined at this point. When \( x \) is positive, \( \sinh x \) is also positive, and \( \text{csch} \, x \) thus assumes positive values. Similarly, when \( x \) is negative, \( \sinh x \) takes on negative values, forecasting that \( \text{csch} \, x \) will be negative.

The crucial aspect of \( \text{csch} \, x \) is its range, which is all values away from zero, specifically defined as (-∞, -1] ∪ [1, ∞). Therefore, \( \text{csch} \, x \) can represent incredibly large or incredibly small (but non-zero) numbers in both positive and negative directions.

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