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Compute the limits. If a limit does not exist, explain why. $$ \lim _{x \rightarrow 0^{+}} \sqrt{\frac{1}{x}+2}-\sqrt{\frac{1}{x}} \cdot \Rightarrow $$

Short Answer

Expert verified
The limit as \( x \to 0^+ \) is 0.

Step by step solution

01

Identify and Reevaluate the Expression

We need to find \( \lim_{x \to 0^+} \left( \sqrt{\frac{1}{x} + 2} - \sqrt{\frac{1}{x}} \right) \). As direct substitution leads to an indeterminate form of \( \infty - \infty \), we'll need to simplify or transform the expression.
02

Rationalize the Expression

To eliminate the indeterminate form, we rationalize by multiplying and dividing by the conjugate: \( \frac{\left( \sqrt{\frac{1}{x} + 2} - \sqrt{\frac{1}{x}} \right)}{1} \times \frac{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} \). This gives: \[ \frac{\left( \frac{1}{x} + 2 - \frac{1}{x} \right)}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} = \frac{2}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} \]
03

Simplify the Expression

The expression can now be simplified to \( \lim_{x \rightarrow 0^{+}} \frac{2}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} \). As \( x \to 0^+ \), the term \( \frac{1}{x} \to +\infty \), so the dominator \( \sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}} \to \infty \).
04

Evaluate the Limit

Since the denominator goes to infinity, the fraction \( \frac{2}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} \) approaches zero. Therefore, \( \lim_{x \rightarrow 0^{+}} \frac{2}{\sqrt{\frac{1}{x} + 2} + \sqrt{\frac{1}{x}}} = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
In calculus, an **indeterminate form** occurs when the evaluation of a limit does not lead to a clear result. This typically happens because the expression involves terms that tend towards infinity or zero in such a way that their relationship to each other becomes unclear. One of the most commonly encountered indeterminate forms is \( \infty - \infty \), which arises when each term within the limit approaches infinity, creating uncertainty about the overall value.
  • Understanding **indeterminate forms** is crucial, as it signals that straightforward limit evaluation may not work.
  • To resolve these forms, mathematicians often use algebraic manipulation, such as rationalization, to transform the expression into a determinable form.
In the provided exercise, when substituting \( x \rightarrow 0^{+} \), we notice that both square root terms grow infinitely large, leading to the indeterminate form \( \infty - \infty \). This requires further manipulation to simplify and solve the limit.
Rationalization Technique
The **rationalization technique** is a useful method for simplifying expressions, especially when dealing with limits that result in indeterminate forms like \( \infty - \infty \). Its core idea is to eliminate irrational numbers in the numerator or denominator by employing a mathematical conjugate.For instance, if faced with an expression like \( \sqrt{a} - \sqrt{b} \), you can multiply by its conjugate, \( \sqrt{a} + \sqrt{b} \), which leverages the identity:\[ (\sqrt{a} - \sqrt{b})(\sqrt{a} + \sqrt{b}) = a - b \]The key benefit of using the **rationalization technique** is that it avoids undefined operations or indeterminate forms by converting the problem into a simpler one:
  • This method breaks down complex terms and eliminates square roots, providing a more approachable form for limit evaluation.
  • It leads the expression to a form where the limit can be evaluated easily, as seen in the original exercise solution.
In our case, we multiplied the original expression by its conjugate, transforming the limit problem into a solvable fraction.
Limit Evaluation Steps
When tackling limits, it's important to follow a series of **limit evaluation steps** to ensure proper understanding and solution:1. **Identify the Indeterminate Form**: First, substitute the limit value into the expression to see if it results in an indeterminate form.2. **Apply Algebraic Techniques**: Use approaches like simplification, rationalization, or L'Hôpital's Rule to resolve indeterminacy.3. **Transform the Expression**: Like in the given exercise, multiply by a conjugate to form a new expression that removes the indeterminate nature. 4. **Simplify the New Expression**: This typically involves canceling out terms, factoring, or distributing terms across the fractions.5. **Evaluate the Limit**: After resolving the indeterminate form, substitute the limit value again, concluding if the expression approaches a finite number.In the textbook solution, we start by acknowledging the indeterminate form \( \infty - \infty \), apply rationalization, simplify the fraction, and finally evaluate the limit, concluding it approaches 0. This systematic approach guarantees a clear path to the correct answer.

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Most popular questions from this chapter

Find an algebraic expression for the difference quotient \((f(x+\Delta x)-f(x)) / \Delta x\) when \(f(x)=\) \(m x+b\). Simplify the expression as much as possible. Then determine what happens as \(\Delta x\) approaches \(0 .\) That value is \(f^{\prime}(x) . \Rightarrow\)

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