Chapter 10: Problem 13
Sketch the curves over the interval \([0,2 \pi]\) unless otherwise stated. $$ r=\sin (\theta / 3), 0 \leq \theta \leq 6 \pi $$
Short Answer
Expert verified
The curve forms a three-lobed rose pattern ending at the origin between \(0\) and \(6\pi\).
Step by step solution
01
Understanding Polar Coordinates
The problem requires sketching a curve given in polar coordinates: \(r = \sin(\theta / 3)\). Recognize that \(r\) (radius) is expressed as a function of \(\theta\), the angle in radians. We first need to understand how such functions are represented in a polar plane. Here, \( \theta \) ranges from \( 0 \) to \( 6\pi \), which is twice as much as the interval where \(\sin(x)\) typically completes one full cycle (\( 0 \) to \( 2\pi \)). This affects how we anticipate the curve's path.
02
Analyzing the Sinusoidal Function
First, recognize that the function \(\sin(x)\) has a period of \(2\pi\). For \(\sin(\theta/3)\), the period becomes \(6\pi\), since scaling the input by 3 compresses the sine's cycle by a factor of 3, allowing it to complete one full cycle from 0 to \(6\pi\). This tells us the curve will have a complete cycle within the given range for \(\theta\). Contrast this with a cartesian graph where you would expect multiple cycles for small compression factors.
03
Key Points in the Plot
Determine values for key angles: When \(\theta = 0\), \(r = \sin(0) = 0\); when \(\theta = 3\pi\), \(r = \sin(\pi) = 0\); when \(\theta = 6\pi\), \(r = \sin(2\pi) = 0\). The function \(\sin(\theta/3)\) reaches its maximum at \(\theta = 3\pi/2\) (since \(\theta\) is \(3\pi\) times \(1/2\)), where \(r = 1\), and its minimum at \(\theta = 9\pi/2\) (as \(3\pi \times 3/2\)), where \(r = -1\). These represent the peaks and troughs of our plot.
04
Plotting the Curve
Sketch the curve by marking the points: start at the origin \((\theta = 0, r = 0)\), moving towards the peak at \((\theta = 3\pi/2, r = 1)\). The curve returns to the origin at \((\theta = 3\pi, r = 0)\). Continue to the trough at \((\theta = 9\pi/2, r = -1)\), and finally back to the origin at \((\theta = 6\pi, r = 0)\). Since \(r\) starts positive, rotates through maximum, back to zero, then negative for a similar path, retrace these values around the polar axis.
05
Completing the Sketch
The sinusoidal nature means the curve will appear as a series of loops or petal-like shapes, reflecting how r fluctuates from 0 to 1 to -1 before returning to 0. Repeat this looping process through the succession of extrema between 0 and 6Ï€ to visualize the full cycle. The sketch has three complete loops, each representing a cycle of the sinusoidal function from its maximum to minimum.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sinusoidal Function
A sinusoidal function, like the sine function, is a type of periodic function which oscillates between a maximum and minimum value in a smooth, wave-like motion. The general form of a sinusoidal function is given by
- \[f(x) = a imes ext{sin}(b(x-c)) + d\]
- \(a\) represents the amplitude, or the height of the peaks from the central axis, determining how far the function oscillates from its mean value.
- \(b\) affects the period of the function, as it compresses or stretches the wave horizontally.
- \(c\) causes a horizontal shift, or phase shift, moving the wave left or right along the x-axis.
- \(d\) moves the wave vertically, adjusting the mean value of oscillation.
Period of Sinusoidal Function
The period of a sinusoidal function determines the length of one complete cycle of the wave, from start to finish. For the standard sine function \(\text{sin}(x)\),
- the period is \(2\pi\), meaning it takes \(2\pi\) radians for the function to complete one full wave cycle.
- Thus, the period becomes \(6\pi\), as \(b=\frac{1}{3}\) applies a factor which expands the cycle over the \([0, 6\pi]\) range.
Plotting in Polar Coordinates
Polar coordinates plot points on a plane using a distance from a central point (the radius \(r\)) and an angle (\(\theta\)) measured from a given direction, typically the positive x-axis. This differs from Cartesian coordinates, which rely on x and y axes to locate points.For this particular exercise, with the function \(r = \sin(\theta / 3)\), plotting in polar coordinates involves mapping how the varying radius \(r\) behaves relative to the angle \(\theta\).
- First, recognize that \(r\) changes according to the sinusoidal pattern, starting from \(0\) at \(\theta = 0\), reaching its maximum at \(\theta = 3\pi/2\) (\(r=1\)), and back to \(0\) at \(\theta = 3\pi\).
- After reaching \(0\), it continues, this time reaching a negative minimum at \(\theta = 9\pi/2\) (\(r=-1\)), before returning once more to \(0\) at \(\theta = 6\pi\).