/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Find the equation of the line th... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the equation of the line through (-1,1) and (5,-3) in the form \(y=m x+b . \Rightarrow\)

Short Answer

Expert verified
The equation is \(y = -\frac{2}{3}x + \frac{1}{3}\).

Step by step solution

01

Determine the Slope (m)

To find the slope of the line passing through the points \((-1, 1)\) and \((5, -3)\), use the formula for slope, \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Substituting the given points into the formula, we get \(m = \frac{-3 - 1}{5 - (-1)} = \frac{-4}{6} = -\frac{2}{3}\).
02

Use Point-Slope Form

Having the slope \(m = -\frac{2}{3}\), use the point-slope form of the equation, \(y - y_1 = m(x - x_1)\), with one of the given points, say \((-1, 1)\). Substitute these values into the equation: \(y - 1 = -\frac{2}{3}(x + 1)\).
03

Simplify to Slope-Intercept Form

Distribute the slope on the right side of the equation: \(y - 1 = -\frac{2}{3}x - \frac{2}{3}\). Add 1 to both sides to isolate \(y\): \(y = -\frac{2}{3}x - \frac{2}{3} + 1\). Convert the constant into a single fraction: \(-\frac{2}{3} + 1 = -\frac{2}{3} + \frac{3}{3} = \frac{1}{3}\). Thus, \(y = -\frac{2}{3}x + \frac{1}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Calculation
To determine the equation of a line, one of the first steps involves calculating its slope. The slope indicates how steep the line is and the direction it moves. It is calculated using two points on the line. In this exercise, the points (-1, 1) and (5, -3) are used. The formula for finding the slope \( m \) is given by:
  • \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Here, \( (x_1, y_1) = (-1, 1) \) and \( (x_2, y_2) = (5, -3) \). Substituting these points into the formula gives:
  • \( m = \frac{-3 - 1}{5 - (-1)} = \frac{-4}{6} = -\frac{2}{3} \).
This result indicates that for every 3 units the line moves horizontally, it moves 2 units downward. Understanding slope helps in predicting the direction and steepness of the line for any use, from graphing to real-world applications.
Point-Slope Form
Once the slope \( m \) is known, we can proceed to write the equation of the line using the point-slope form. This form is particularly useful for building the equation incrementally, especially when we have one point on the line and the slope. The point-slope form is defined as:
  • \( y - y_1 = m(x - x_1) \)
For our exercise, using the slope \( m = -\frac{2}{3} \) and one of the points, say \((-1, 1)\), we substitute
  • \( y - 1 = -\frac{2}{3}(x + 1) \)
This equation reflects how the line changes based on its slope from the point \((-1, 1)\). Transforming equations using the point-slope form is straightforward and lays the groundwork for further simplifications to other forms of line equations, making it a powerful tool in algebra.
Slope-Intercept Form
The slope-intercept form is an efficient way to express a linear equation, providing a clear image of the line's behavior at a glance. Once you have your equation in the point-slope form, the next step is to simplify it into slope-intercept form. This form is represented as \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. We simplify the point-slope form equation:
  • \( y - 1 = -\frac{2}{3}x - \frac{2}{3} \)
Adding 1 to both sides to isolate \( y \) gives:
  • \( y = -\frac{2}{3}x - \frac{2}{3} + 1 \)
Converting \( -\frac{2}{3} + 1 \) to a single fraction results in \( \frac{1}{3} \), so the equation becomes:
  • \( y = -\frac{2}{3}x + \frac{1}{3} \)
This form clearly shows the slope \(-\frac{2}{3}\) and the y-intercept \(\frac{1}{3}\), making it ideal for graphing and analyzing linear relationships in a visually intuitive way.

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Most popular questions from this chapter

Suppose that you are driving to Seattle at constant speed. After you have been traveling for an hour you pass a sign saying it is 130 miles to Seattle, and after driving another 20 minutes you pass a sign saying it is 105 miles to Seattle. Using the horizontal axis for the time \(t\) and the vertical axis for the distance \(y\) from your starting point, graph and find the equation \(y=m t+b\) for your distance from your starting point. How long does the trip to Seattle take? \(\Rightarrow\)

For each pair of points \(A\left(x_{1}, y_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\) find (i) \(\Delta x\) and \(\Delta y\) in going from \(A\) to \(B\), (ii) the slope of the line joining \(A\) and \(B,\) (iii) the equation of the line joining \(A\) and \(B\) in the form \(y=m x+b\), (iv) the distance from \(A\) to \(B\), and (v) an equation of the circle with center at \(A\) that goes through \(B\). a) \(A(2,0), B(4,3)\) b) \(A(1,-1), B(0,2)\) c) \(A(0,0), B(-2,-2)\) d) \(A(-2,3), B(4,3)\) e) \(A(-3,-2), B(0,0)\) f) \(A(0.01,-0.01), B(-0.01,0.05)\)

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