Chapter 8: Problem 34
Use the binomial series to find the power series representation of the function. Then find the radius of convergence of the series. \(f(x)=\frac{x}{(1+x)^{2}}\)
Short Answer
Expert verified
The power series representation of the given function, \(f(x)=\frac{x}{(1+x)^{2}}\), is:
\[f(x) = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\]
The radius of convergence for this series is \(R = \frac{1}{|x|}\).
Step by step solution
01
Apply the Binomial Series Formula
For our given function, we want to find the power series representation of \((1+x)^{-2}\). Using the binomial series formula, we have:
\[(1 + x)^{-2} = \sum_{k=0}^{\infty}{\binom{-2}{k} x^{k}}\]
Now we have to find \(\binom{-2}{k}\) in terms of factorials.
02
Simplify the binomial coefficient
Recall that the binomial coefficient is given by:
\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]
So, our binomial coefficient for this problem is:
\[\binom{-2}{k} = \frac{(-2)!}{k!( -2 - k)!}\]
However, we need to use the formula for negative factorials:
\[\binom{-n}{k} = (-1)^k \binom{n + k - 1}{k}\]
So, our binomial coefficient becomes:
\[\binom{-2}{k} = (-1)^k \binom{2 + k - 1}{k} = (-1)^k \binom{k+1}{k}\]
03
Power series representation of \((1 + x)^{-2}\)
Now we can plug in the simplified binomial coefficient into our binomial series formula:
\[(1 + x)^{-2} = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k}}\]
04
Power series representation of \(f(x)\)
Since our function is given by \(f(x) = \frac{x}{(1 + x)^2}\), we can multiply the power series representation of \((1 + x)^{-2}\) by \(x\):
\[f(x) = x \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k}} = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\]
So, the power series representation of \(f(x)\) is:
\[f(x) = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\]
05
Determine the radius of convergence
To find the radius of convergence, we can use the Ratio Test:
\[\lim_{k\to\infty} \left| \frac{a_{k+1}}{a_k} \right| = R^{-1}\]
Our sequence \(a_k\) is defined as:
\[a_k=(-1)^k\binom{k+1}{k}x^{k+1}\]
Therefore, the ratio is:
\[\frac{a_{k+1}}{a_k} = \frac{(-1)^{k+1}\binom{k+2}{k+1}x^{k+2}}{(-1)^k\binom{k+1}{k}x^{k+1}}\]
Simplifying, we get:
\[\frac{a_{k+1}}{a_k} = \frac{-1\binom{k+2}{k+1}}{\binom{k+1}{k}}x\]
Taking the limit, we get:
\[\lim_{k\to\infty} \left| \frac{-1\binom{k+2}{k+1}}{\binom{k+1}{k}}x \right| = |x|\]
So, we have \(R^{-1} = |x|\). Therefore, the radius of convergence, \(R\), is:
\[R = \frac{1}{|x|}\]
In conclusion, the power series representation of the given function is:
\[f(x) = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\]
with a radius of convergence, \(R = \frac{1}{|x|}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series Representation
The power series representation of a function is an essential tool in calculus and analysis. It involves expressing a function as a sum of terms in the form of a series, typically infinite and written as \(a_0 + a_1x + a_2x^2 + \ldots\). For a function like \(f(x) = \frac{x}{(1+x)^{2}}\), the objective is to find such a representation using the binomial series formula.
To begin, you find the power series for \((1 + x)^{-2}\) using this formula:
To begin, you find the power series for \((1 + x)^{-2}\) using this formula:
- Start by considering the expression \(\sum_{k=0}^{\infty}{\binom{-2}{k} x^{k}}\).
- This is derived from the binomial series formula \((1 + x)^{n} = \sum_{k=0}^{\infty}{\binom{n}{k}x^{k}}\) for any real number \(n\), and can handle negative exponents through special adaptations.
- Finding the binomial coefficient for negative exponents can be tricky, so you utilize the formula \(\binom{-n}{k} = (-1)^k \binom{n + k - 1}{k}\) to simplify further.
Radius of Convergence
The radius of convergence tells us the interval within which a power series converges to a function. It's a measure of how far from the center of expansion you can extend the series and still have it provide accurate values of the original function.
For our function \(f(x) = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\), determining this radius is crucial:
For our function \(f(x) = \sum_{k=0}^{\infty}{(-1)^k \binom{k+1}{k} x^{k+1}}\), determining this radius is crucial:
- The series will only represent the function correctly within this range.
- Outside this radius, the series might diverge, failing to correspond to the original function.
Ratio Test
The Ratio Test is a common tool used to find the radius of convergence for a given power series. It's particularly useful in our context as it offers a systematic approach to determine where a series holds valid results.
Here's how the Ratio Test works:
Here's how the Ratio Test works:
- Take the terms of your series \(a_k\), such as \(a_k=(-1)^k\binom{k+1}{k}x^{k+1}\) in our power series.
- Compute the limit of the absolute value of the ratio of successive terms: \(\lim_{k\to\infty} \left| \frac{a_{k+1}}{a_k} \right|\).
- With this limit equating to \(R^{-1}\), it effectively tells you about convergence when \(|x| < R\).
- In our example, we evaluate the ratio to get \(|x|\), indicating the series converges when \(|x| < 1\).
- The result \(R = 1\) indicates the power series holds within this radius.