Chapter 8: Problem 3
Write the first five terms of the sequence \(\left\\{a_{n}\right\\}\) whose \(n\) th term is given. \(a_{n}=\sin \frac{n \pi}{2}\)
Short Answer
Expert verified
The first five terms of the sequence \(\left\\{a_{n}\right\\}\) with \(a_n=\sin \frac{n \pi}{2}\) are \(1, 0, -1, 0, 1\).
Step by step solution
01
Substitute n = 1
To find the first term, substitute \(n = 1\) in the formula:
\(a_1 = \sin \frac{1 \pi}{2} = \sin \frac{\pi}{2}\)
\(\sin \frac{\pi}{2} = 1\)
So, the first term is \(a_1=1\).
02
Substitute n = 2
To find the second term, substitute \(n = 2\) in the formula:
\(a_2 = \sin \frac{2 \pi}{2} = \sin \pi\)
\(\sin \pi = 0\)
So, the second term is \(a_2=0\).
03
Substitute n = 3
To find the third term, substitute \(n = 3\) in the formula:
\(a_3 = \sin \frac{3 \pi}{2} = \sin \frac{3\pi}{2}\)
\(\sin \frac{3\pi}{2} = -1\)
So, the third term is \(a_3=-1\).
04
Substitute n = 4
To find the fourth term, substitute \(n = 4\) in the formula:
\(a_4 = \sin \frac{4 \pi}{2} = \sin 2\pi\)
\(\sin 2\pi = 0\)
So, the fourth term is \(a_4=0\).
05
Substitute n = 5
To find the fifth term, substitute \(n = 5\) in the formula:
\(a_5 = \sin \frac{5 \pi}{2} = \sin \frac{5\pi}{2}\)
\(\sin \frac{5\pi}{2} = 1\)
So, the fifth term is \(a_5=1\).
The first five terms of the sequence are \(1, 0, -1, 0, 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sequence Terms
A sequence is a list of numbers arranged in a specific order. In mathematical terms, when we talk about the 'terms' of a sequence, we're referring to the elements that make up this list. For example, in the sequence given by the formula \( a_n = \sin \frac{n\pi}{2} \), each \( a_n \) corresponds to a number in our sequence defined by plugging in different values of \( n \).
- First Term: Input \( n = 1 \) into the formula to get \( a_1 \).
- Second Term: Input \( n = 2 \) into the formula for \( a_2 \).
- Third Term: Continue this process with \( n = 3 \), 4, and so on, to find the subsequent terms \( a_3 \), \( a_4 \), etc.
Sine Function
The sine function, denoted as \( \sin \theta \), is a fundamental concept in trigonometry. It is a periodic function that maps angles to the y-coordinate in the unit circle. In simple terms, it tells you how high a point is on the unit circle when you rotate an angle \( \theta \) from the positive x-axis.
- For \( \theta = \frac{\pi}{2} \), \( \sin \theta = 1 \)
- For \( \theta = \pi \), \( \sin \theta = 0 \)
- For \( \theta = \frac{3\pi}{2} \), \( \sin \theta = -1 \)
Periodicity of Sine
The periodicity of a function is the tendency for it to repeat values at regular intervals. The sine function is a great example of a periodic function with a period of \( 2\pi \). This means that every \( 2\pi \) radians (or 360 degrees), the sine function returns to its original spot.
For our sequence \( a_n = \sin \frac{n\pi}{2} \), we're particularly interested in how the function repeats over smaller intervals to form the terms of our sequence.
For our sequence \( a_n = \sin \frac{n\pi}{2} \), we're particularly interested in how the function repeats over smaller intervals to form the terms of our sequence.
- At \( n = 1 \), \( \sin \frac{\pi}{2} = 1 \)
- At \( n = 3 \), \( \sin \frac{3\pi}{2} = -1 \)
- At \( n = 5 \), \( \sin \frac{5\pi}{2} = 1 \)