Chapter 6: Problem 97
Find or evaluate the integral. $$ \int \frac{d x}{x^{4}+x^{2}+1} $$
Short Answer
Expert verified
The short answer is:
$$
\int \frac{d x}{x^{4}+x^{2}+1} = \frac{\sqrt{3}}{6}\tan^{-1}(\frac{2(x^2 + \frac{1}{2})}{\sqrt{3}}) + C
$$
Step by step solution
01
Identify a substitution to simplify the integral
Notice that the denominator is a quadratic which can be written as a sum of squares. Let's use the substitution \(u = x^2\). When we differentiate both sides with respect to x, we get:
$$
\frac{d u}{dx} = 2x \\
$$
Now let's find the differential of u, du, in terms of dx:
$$
d u = 2x dx \\
\frac{d u}{2} = x dx \\
$$
Now we can substitute \(u = x^2\) and \(\frac{d u}{2} = x dx\) in the given integral:
$$
\int \frac{d x}{x^{4}+x^{2}+1} = \int\frac{\frac{d u}{2}}{u^2 + u + 1} \\
$$
We can pull the constant factor 1/2 out of the integral:
$$
\frac{1}{2}\int \frac{d u}{u^2 + u + 1} \\
$$
02
Complete the square in the denominator
Let's rewrite the denominator as a completed square:
$$
u^2 + u + 1 = (u + \frac{1}{2})^2 + \frac{3}{4} \\
$$
Now, we rewrite the integral:
$$
\frac{1}{2}\int \frac{d u}{(u + \frac{1}{2})^2 + \frac{3}{4}} \\
$$
03
Use the trigonometric substitution
Observe that the denominator is of the form \(a^2 + u^2\), where \(a^2 = \frac{3}{4}\). We can use the trigonometric substitution \(u + \frac{1}{2} = \frac{\sqrt{3}}{2} \tan(\theta)\):
$$
d u = \frac{\sqrt{3}}{2} \sec^2(\theta)d\theta \\
$$
Now substitute \(u + \frac{1}{2} = \frac{\sqrt{3}}{2} \tan(\theta)\) and \( d u = \frac{\sqrt{3}}{2} \sec^2(\theta)d\theta \) in the integral:
$$
\frac{1}{2}\int \frac{\frac{\sqrt{3}}{2}\sec^2(\theta)d\theta}{( \frac{\sqrt{3}}{2} \tan(\theta))^2 + \frac{3}{4}} \\
$$
Simplify the integral:
$$
\frac{\sqrt{3}}{6}\int \frac{\sec^2(\theta)d\theta}{( \tan^2(\theta) + 1)} \\
$$
Since \(\sec^2(\theta) = 1 + \tan^2(\theta)\), the integral simplifies to
$$
\frac{\sqrt{3}}{6}\int d\theta \\
$$
04
Evaluate the integral
Now we can integrate:
$$
\frac{\sqrt{3}}{6}(\theta) + C \\
$$
05
Reverse the substitution
We need to reverse the substitution step by step:
We know that:
$$
u + \frac{1}{2} = \frac{\sqrt{3}}{2} \tan(\theta) \\
$$
Thus,
$$
\theta = \tan^{-1}(\frac{2(u + \frac{1}{2})}{\sqrt{3}}) \\
$$
Now, we will reverse the first substitution:
$$
u = x^2 \\
x^2 = u \\
$$
So the final solution is:
$$
\int \frac{d x}{x^{4}+x^{2}+1} = \frac{\sqrt{3}}{6}\tan^{-1}(\frac{2(x^2 + \frac{1}{2})}{\sqrt{3}}) + C \\
$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution method
The substitution method is a technique used in integration to simplify complex integrals by changing variables. In this process, we replace a variable with another that simplifies the integral, making it easier to solve.
In this exercise, we began with the integral \( \int \frac{d x}{x^{4}+x^{2}+1} \). The substitution \( u = x^2 \) was proposed because the denominator could be expressed simply in terms of \( u \). This helped in transforming the integrand from a function of \( x \) to a function of \( u \).
To carry out the substitution, we calculated the differential \( du \) in terms of \( dx \). This allowed us to express the entire integral in terms of \( u \), leading to the simpler integral \( \frac{1}{2} \int \frac{d u}{u^2 + u + 1} \).
Key points when using the substitution method:
In this exercise, we began with the integral \( \int \frac{d x}{x^{4}+x^{2}+1} \). The substitution \( u = x^2 \) was proposed because the denominator could be expressed simply in terms of \( u \). This helped in transforming the integrand from a function of \( x \) to a function of \( u \).
To carry out the substitution, we calculated the differential \( du \) in terms of \( dx \). This allowed us to express the entire integral in terms of \( u \), leading to the simpler integral \( \frac{1}{2} \int \frac{d u}{u^2 + u + 1} \).
Key points when using the substitution method:
- Select a substitution that simplifies the integral significantly.
- Find the differential of the new variable relative to the old variable.
- Convert all expressions, including boundaries if they exist, in terms of the new variable.
- Don't forget to reverse the substitution at the end to express the solution in terms of the original variable.
Trigonometric substitution
Trigonometric substitution is a technique particularly useful when an integrand involves expressions like \( \sqrt{a^2 + x^2} \), \( \sqrt{a^2 - x^2} \), or \( \sqrt{x^2 - a^2} \). By substituting a trigonometric function of a new variable, the integral simplifies into a form often involving basic trigonometric identities.
In the presented solution, the expression inside the integral assumes the form \( (u + \frac{1}{2})^2 + \frac{3}{4} \), equivalent to \( a^2 + x^2 \). Hence, trigonometric substitution was used with \( u + \frac{1}{2} = \frac{\sqrt{3}}{2} \tan(\theta) \) and \( a^2 = \frac{3}{4} \).
Here are the steps involved:
In the presented solution, the expression inside the integral assumes the form \( (u + \frac{1}{2})^2 + \frac{3}{4} \), equivalent to \( a^2 + x^2 \). Hence, trigonometric substitution was used with \( u + \frac{1}{2} = \frac{\sqrt{3}}{2} \tan(\theta) \) and \( a^2 = \frac{3}{4} \).
Here are the steps involved:
- Identify the substitution based on the format related to the trigonometric identity.
- Express \( du \) in terms of \( \theta \) variable substitutions, like \( du = \frac{\sqrt{3}}{2} \sec^2(\theta)d\theta \) in this case.
- Simplify the integral using trigonometric identities, for instance, \( 1 + \tan^2(\theta) = \sec^2(\theta) \).
- Once simplified to a basic trigonometric form, integrating becomes straightforward, often resulting in \( \theta \) form solutions.
Completing the square
Completing the square is a method used to express a quadratic expression as a perfect square plus or minus a constant. This technique is highly useful for recollecting patterns in integrals or for solving quadratic equations.
In this integral, we started by expressing \( u^2 + u + 1 \) in a transformed form. By completing the square, it was rewritten as \( (u + \frac{1}{2})^2 + \frac{3}{4} \).
The steps to complete the square are as follows:
In this integral, we started by expressing \( u^2 + u + 1 \) in a transformed form. By completing the square, it was rewritten as \( (u + \frac{1}{2})^2 + \frac{3}{4} \).
The steps to complete the square are as follows:
- Take the coefficient of the linear term, \( u \) in this case, divide it by 2, and then square it. Here, \( \frac{1}{2} \) is squared to get \( \frac{1}{4} \).
- Add and subtract this squared number inside the expression \( u^2 + u + 1 \).
- Factor the perfect square trinomial. Convert the expression into \( (u + \frac{1}{2})^2 + \frac{3}{4} \).