Chapter 5: Problem 73
Prove that \(\frac{d}{d x} \cosh u=(\sinh u) \frac{d u}{d x} .\)
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Chapter 5: Problem 73
Prove that \(\frac{d}{d x} \cosh u=(\sinh u) \frac{d u}{d x} .\)
These are the key concepts you need to understand to accurately answer the question.
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Prove the identity. \(\cosh ^{2} x=\frac{1+\cosh 2 x}{2}\)
a. Plot the graph of \(f(x)=\tan ^{-1} x\) and the graph of the secant line passing through \((0,0)\) and \(\left(1, \frac{\pi}{4}\right)\). b. Use the Pythagorean Theorem to estimate the arc length of the graph of \(f\) on the interval \([0,1]\). c, Use a calculator or a computer to find the arc length of the graph of \(f(x)=\tan ^{-1} x\)
find the given integral. \(\int \tanh x d x\)
If \(\cosh x=\frac{5}{4}\), find the values of the other hyperbolic functions at \(x\).
Find the area of the surface obtained by revolving the given curve about the indicated axis. $$ y=x^{1 / 3} \text { on }[1,8] ; \quad y \text { -axis } $$
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