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Find the integral using the indicated substitution. $$ \int \frac{\sin x}{\cos ^{2} x} d x, \quad u=\cos x $$

Short Answer

Expert verified
The short answer based on the step-by-step solution is: Using the substitution \(u = \cos x\), we can rewrite the integral as \(\int \frac{\sin x}{\cos^2 x} dx = \int \frac{-1}{u^2} du\). Integrating with respect to \(u\) gives us \(-\frac{1}{u} + C = \frac{1}{\cos x} + C\). Therefore, the integral of the given function is: \[\int \frac{\sin x}{\cos ^{2} x} dx = \frac{1}{\cos x} + C.\]

Step by step solution

01

Find du/dx using the given substitution

Since \(u = \cos x\), we can differentiate both sides with respect to \(x\) to find the value of \(\frac{du}{dx}\). \[\frac{du}{dx} = -\sin x\]
02

Rewrite the integral in terms of u

We know that \(\frac{du}{dx} = -\sin x\). So, we can rewrite \(\sin x dx\) as \(-\,du\). Also, substitute \(u = \cos x\) to get the expression in terms of \(u\): \[\int \frac{\sin x}{\cos^2 x} dx = \int \frac{-1}{u^2} du\]
03

Integrate the expression with respect to u

Now, we will integrate the expression with respect to \(u\): \[- \int \frac{1}{u^2} du = - \int u^{-2} du\] Using the power rule for integration, we have: \[- \int u^{-2} du = -\frac{u^{-1}}{-1} + C = \frac{1}{u} + C \]
04

Replace u with the original function of x

Now that we've integrated with respect to \(u\), we can substitute back \(u = \cos x\) to get the solution in terms of \(x\): \[\frac{1}{u} + C = \frac{1}{\cos x} + C\] So, the integral of the given function with the indicated substitution is: \[\int \frac{\sin x}{\cos ^{2} x} dx = \frac{1}{\cos x} + C\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Calculus
Integral calculus is a branch of mathematics focused on finding the quantities where the rate of change is known. It is essentially the reverse process of differentiation, where you're given the derivative of a function and your task is to find the original function. This process is crucial in various fields, including physics, engineering, and economics, as it helps in determining areas, volumes, and other quantities that are accumulated from infinitesimal contributions.

For example, in the case of acceleration (which is the derivative of velocity), integration can tell us about the velocity function when the initial conditions are known. Without integral calculus, many real-world problems cannot be solved because it provides the link between the rates of change and the functions that describe the quantities in which we're interested.
Power Rule for Integration
The power rule is a fundamental technique in integral calculus applied to integrate polynomials. It operates under a pretty straightforward principle: if you have a function in the form of \(u^n\), where \(n\) is a real number different from -1, its integral will be \(\frac{u^{n+1}}{n+1}\) plus the constant of integration, usually denoted as \(C\).

This rule simplifies the process of finding the antiderivative of a power function. It’s vital to remember that the constant \(C\) signifies that there are infinitely many antiderivatives for a given function, each differing by a constant amount. In the exercise provided, the power rule was applied after substituting and simplifying the integral to intertwine with this rule, allowing the integration process to be smooth and straightforward.
Trigonometric Substitution

When to Use Trigonometric Substitution

Trigonometric substitution is particularly useful when the integral involves square roots or the integrand includes trigonometric functions. The objective is to replace the original variable with a trigonometric function that makes the integral easier to solve. For instance, substituting \(x\) with \(\sin(\theta)\), \(\cos(\theta)\), or \(\tan(\theta)\) can simplify the expression into a more manageable form.

Challenge in Trigonometric Substitution

Often, the challenge with trigonometric substitution isn't just in integrating the new function, but also in reverting back to the initial variable without introducing errors. Making sure the substitution and the eventual back-substitution are done accurately ensures that the solution reflects the original problem's terms, as seen in the exercise.
Indefinite Integrals
Indefinite integrals, also known as antiderivatives, are integrals without specified limits. They represent a family of functions that differ by a constant and are used to determine the general form of a function given its derivative. The notation for an indefinite integral is the integral sign followed by the function to be integrated and the differential of the variable.

For example, the indefinite integral of \(f(x) = x^2\) is \(\frac{1}{3}x^3 + C\), where \(C\) is the constant of integration. In indefinite integrals, we are not looking for the accumulated value over an interval but rather the general function that would differentiate to give the original function. This aspect featured prominently in the provided exercise, where the integration yielded a general form in terms of \(u\), followed by an inclusion of the constant of integration, aptly denoted by \(C\).

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