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Find the derivative of the function. $$ G(x)=\int_{-1}^{x} t \sqrt{t^{2}+1} d t $$

Short Answer

Expert verified
The derivative of the function G(x) is: \[ \frac{d}{dx} G(x) = x \sqrt{x^{2}+1} \]

Step by step solution

01

Fundamental Theorem of Calculus (Part 1)

According to the first part of the Fundamental Theorem of Calculus, if F(x) is a continuous function on the interval [a, b] and G(x) is an antiderivative of F(x), then the derivative of the integral of F(t) from a to x is given by: \[ \frac{d}{dx} \int_a^x F(t) dt = F(x) \] Step 2: Apply the Fundamental Theorem of Calculus on G(x)
02

Applying Fundamental Theorem of Calculus

For our function G(x): \[ G(x)=\int_{-1}^{x} t \sqrt{t^{2}+1} dt \] We want to find the derivative of G(x) with respect to x: \[ \frac{d}{dx} G(x) = \frac{d}{dx} \int_{-1}^{x} t \sqrt{t^{2}+1} dt \] Using the Fundamental Theorem of Calculus (Part 1), the derivative of G(x) is given by: \[ \frac{d}{dx} G(x) = x \sqrt{x^{2}+1} \] Step 3: Write the final answer
03

Derivative of G(x)

The derivative of the function G(x) is: \[ \frac{d}{dx} G(x) = x \sqrt{x^{2}+1} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a crucial principle in calculus that establishes a connection between differentiation and integration, two of the main concepts in the field.

Simply put, it tells us that if we have a continuous function, which means that there are no breaks, jumps, or holes in its graph, then we can find its antiderivative. An antiderivative is a function whose derivative gives us the original function. But more importantly, this theorem assures us that we can evaluate the definite integral of a function over an interval by just using one of its antiderivatives.

The theorem comes in two parts:
  • The first part, sometimes referred to as the first fundamental theorem of calculus, says that if a function is continuous over an interval, then it has an antiderivative over that interval, and we can evaluate the definite integral of the function by finding the difference between the values of the antiderivative at the endpoints of the interval.
  • The second part gives a formula for differentiation of an integral with respect to its upper limit. If we have a function defined by an integral of another function, then the derivative of this function is simply the integrand evaluated at the upper limit of the integral.
Using the first part of the theorem, we can solve many problems involving areas under curves, and it's vital for calculating what we call the 'accumulated' value of a function.
Antiderivative
The concept of an antiderivative is fundamental in the study of integration. An antiderivative of a function is simply another function that, when differentiated, gives back the original function. For instance, if we have a function F(x), and we know that when we take the derivative of another function G(x) we get F(x), then G(x) is an antiderivative of F(x).

Here's an analogy: if you consider a derivative as looking at the speed of a car at a specific moment in time, then an antiderivative is like retracing the car's path to know where it started its journey. It's all about reverse engineering the process of differentiation.

There can be an infinite number of antiderivatives for any given function because when you differentiate a constant, you get zero. This means any constant can be added to an antiderivative without affecting its validity. For this reason, when we express an antiderivative, we often add a '+ C' term at the end to indicate that there could be any constant value added to the function.
Continuous Function
A continuous function is a type of function that does not have any abrupt changes in value—no discontinuities such as holes, jumps, or vertical asymptotes—within its domain. In simpler terms, you can draw the graph of a continuous function without lifting your pencil from the paper.

Continuity is an essential condition for many calculus concepts and operations, especially for the two branches of calculus, differentiation, and integration. For instance, for the Fundamental Theorem of Calculus to be applicable, the function being integrated must be continuous over the integration interval.

A continuous function has many properties that make working with it easier; it's predictable in its behavior and its limits at any point within its domain are equal to the function's value at that point. Understanding continuity is vital when solving calculus problems because knowing that a function is continuous allows us to use a wide array of tools and theorems to analyze and work with the function.

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Most popular questions from this chapter

Population Growth The population of a certain city is projected to grow at the rate of $$ r(t)=400\left(1+\frac{2 t}{\sqrt{24+t^{2}}}\right) \quad 0 \leq t \leq 5 $$ people per year \(t\) years from now. The current population is 60,000 . What will be the population 5 years from now?

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false. $$ \begin{array}{l} \sum_{k=1}^{n}\left(c a_{k}-d b_{k}\right)=c \sum_{k=1}^{n} a_{k}-d \sum_{k=1}^{n} b_{k}\\\ \text { where } c \text { and } d \text { are constants } \end{array} $$

a. If \(f\) is even, what can you say about \(\int_{-\pi}^{\pi} f(x) \cos n x d x\) and \(\int_{-\pi}^{\pi} f(x) \sin n x d x\) if \(n\) is an integer? Explain. b. If \(f\) is odd, what can you say about \(\int_{-\pi}^{\pi} f(x) \cos n x d x\) and \(\int_{-\pi}^{\pi} f(x) \sin n x d x ?\) Explain.

A submersible moving in a straight line through water is subjected to a resistance \(R\) that is proportional to its velocity. Suppose that the submersible travels with its engine shut off. Then the time it takes for the submersible to slow down from a velocity of \(v_{1}\) to a velocity of \(v_{2}\) is $$T=-\int_{v_{1}}^{v_{2}} \frac{m}{k v} d v$$ where \(m\) is the mass of the submersible and \(k\) is a constant. Find the time it takes the submersible to slow down from a velocity of \(16 \mathrm{ft} / \mathrm{sec}\) to \(8 \mathrm{ft} / \mathrm{sec}\) if its mass is 1250 slugs and \(k=20(\) slug \(/ \mathrm{sec})\).

Evaluate the limit by interpreting it as the limit of a Riemann sum of a function on the interval \([a, b]\). $$ \lim _{n \rightarrow \infty} \frac{1}{n^{5}} \sum_{k=1}^{n} k^{4} ; \quad[0,1] $$

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