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Find the indefinite integral, and check your answer by differentiation. $$ \int \frac{3 x^{4}-2 x^{2}+1}{x^{4}} d x $$

Short Answer

Expert verified
The indefinite integral of \(\frac{3 x^{4} - 2 x^{2} + 1}{x^4}\) is given by: \[ \int \frac{3x^4 - 2x^2 + 1}{x^4} dx = 3x - 2x^{-1} - \frac{1}{3x^3} + C \]

Step by step solution

01

Simplify the integrand

Rewrite the given fraction by separating each term in the numerator: \[ \int \frac{3x^4 - 2x^2 + 1}{x^4} dx = \int \left(\frac{3x^4}{x^4} - \frac{2x^2}{x^4} + \frac{1}{x^4}\right) dx \] Now, simplify the integrand by dividing like terms: \[ \int \left(3 - \frac{2}{x^2} + \frac{1}{x^4}\right) dx \]
02

Integrate each term

Integrate each term separately: \[ \int \left(3 - \frac{2}{x^2} + \frac{1}{x^4}\right) dx = \int 3 dx - \int \frac{2}{x^2} dx + \int \frac{1}{x^4} dx \] Recall the general formula for integral expressions of the form \(\int x^n dx = \frac{x^{n+1}}{n+1} + C\), where n is not equal to -1. Using this formula, we can integrate each term.
03

Calculate the integrals

Calculate the integrals of each term: \[ \int 3 dx = 3x + C_1 \] \[ \int \frac{2}{x^2} dx = 2 \int x^{-2} dx = -2x^{-1} + C_2 \] \[ \int \frac{1}{x^4} dx = \int x^{-4} dx = \frac{x^{-3}}{-3} + C_3 \]
04

Combine the results

Place all the individual integrals back together: \[ \int \left(3 - \frac{2}{x^2} + \frac{1}{x^4}\right) dx = 3x - 2x^{-1} - \frac{1}{3x^3} + C \] So the indefinite integral of the given function is: \[ \int \frac{3x^4 - 2x^2 + 1}{x^4} dx = 3x - 2x^{-1} - \frac{1}{3x^3} + C \]
05

Differentiate the result to verify

Differentiate the obtained integral: \[ \frac{d}{dx}(3x - 2x^{-1} - \frac{1}{3x^3} + C) = 3 + 2x^{-2} - \frac{1}{x^4} \] This matches the original function, verifying that the indefinite integral is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Partial Fractions
Integration by partial fractions is a method used to integrate rational functions, which are quotients of polynomials. The key idea is to decompose a complex fraction into simpler fractions that can be more easily integrated.

This technique begins with expressing the integrand as a sum of fractions with linear or quadratic denominators and constant numerators. However, in the given exercise, we find that the integrand is already separated into parts that do not require further decomposition.

In situations where partial fractions would apply, each decomposed fraction corresponds to a term with a unique antiderivative. Overall, this method streamlines tricky integrations, simplifying calculations and making the integration process more manageable.
Power Rule in Integration
The power rule in integration is a fundamental concept for evaluating the integral of power functions of the form \( x^n \). The rule states that the integral of \( x^n \) with respect to \( x \) is \( \frac{x^{n+1}}{n+1} + C \), where \( C \) represents the constant of integration.

Importantly, the power rule applies when \( n \) is not equal to -1. This technique was employed in the exercise for terms like \( -\frac{2}{x^2} \) and \( \frac{1}{x^4} \), after rewriting them as \( x^{-2} \) and \( x^{-4} \) respectively.

Correct application of the power rule is vital for the success of integration tasks, and it is a technique often utilized in conjunction with other methods to find antiderivatives of more complex functions.
Antiderivatives
An antiderivative of a function is another function whose derivative is the original function. The process of finding antiderivatives is known as integration. Each term in the exercise's integrand yields an antiderivative, contributing to the overall integral.

The concept of antiderivatives is crucial in calculus as it's related to the area under a curve and is essential for solving differential equations. For example, the antiderivative of \( 3 \) was determined to be \( 3x + C_1 \) in the provided solution, applying the constant multiple rule in conjunction with the power rule.

The role of antiderivatives isn't limited to finding integrals; they also have practical applications in physics and engineering, such as computing displacement from velocity.
Verification by Differentiation
Verification by differentiation is a method used to check the correctness of an antiderivative. In this approach, one must take the derivative of the proposed antiderivative and ensure it matches the original function to be integrated.

In our exercise, the computed indefinite integral \( 3x - 2x^{-1} - \frac{1}{3x^3} + C \) was differentiated, resulting in the original integrand. This step is an essential part of the process as it confirms the accuracy of the antiderivative.

It's a standard practice in calculus to verify solutions. Such back-checking not only provides confirmation but also helps students understand the interplay of differentiation and integration, underpinning much of integral calculus.

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