/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 You are given a function \(f\), ... [FREE SOLUTION] | 91Ó°ÊÓ

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You are given a function \(f\), an interval \([a, b]\), the number \(n\) of subintervals into which \([a, b]\) is divided \((\) each of length \(\Delta x=(b-a) / n)\), and the point \(c_{k}\) in \(\left[x_{k-1}, x_{k}\right]\), where \(1 \leq k \leq n .\) (a) Sketch the graph of f and the rectangles with base on \(\left[x_{k-1}, x_{k}\right]\) and height \(f\left(c_{k}\right)\), and (b) find the approximation \(\sum_{k=1}^{n} f\left(c_{k}\right) \Delta x\) of the area of the region \(S\) under the graph of \(f\) on \([a, b] .\) $$ f(x)=\cos x,\left[0, \frac{\pi}{2}\right], \quad n=4, \quad c_{k} \text { is the midpoint } $$

Short Answer

Expert verified
The approximate area under the curve for the function \(f(x) = \cos x\) on the interval \(\left[0, \frac{\pi}{2}\right]\) using 4 rectangles with heights given by the midpoint of each subinterval is: \[ A \approx \frac{\pi}{8} (\cos(\frac{\pi}{16})+\cos(\frac{3\pi}{16})+\cos(\frac{5\pi}{16})+\cos(\frac{7\pi}{16})) \]

Step by step solution

01

Divide the interval

First, divide the interval \([0, \frac{\pi}{2}]\) into \(n=4\) equal subintervals. To find the length of each subinterval, compute the value of \(\Delta x\) by dividing the length of the whole interval by the number of subintervals: \[\Delta x = \frac{b-a}{n} = \frac{\frac{\pi}{2} - 0}{4} = \frac{\pi}{8} \]
02

Find the midpoints of each subinterval

Now, we need to find the midpoints of each subinterval (\(c_{k}\)). These are given by: \[c_{k} = x_{k-1} + \frac{\Delta x}{2} \] We know that the first point of the interval is 0, and the second point is \(x_1 = 0 + \frac{\pi}{8}\), therefore the midpoint for the first subinterval is: \[ c_1 = x_0 + \frac{\Delta x}{2} = 0 + \frac{\frac{\pi}{8}}{2} = \frac{\pi}{16} \] Proceed to find the midpoints for each of the 4 subintervals: \[c_2 = x_1 + \frac{\Delta x}{2} = \frac{\pi}{8} + \frac{\frac{\pi}{8}}{2} = \frac{3 \pi}{16} \] \[c_3 = x_2 + \frac{\Delta x}{2} = \frac{2\pi}{8} + \frac{\frac{\pi}{8}}{2} = \frac{5\pi}{16} \] \[c_4 = x_3 + \frac{\Delta x}{2} = \frac{3\pi}{8} + \frac{\frac{\pi}{8}}{2} = \frac{7\pi}{16} \]
03

Find the height of each rectangle

Next, we need to find the height of each rectangle. This is given by the value of \(f(x)=\cos x\) at each \(c_k\). Compute the values of \(f(c_k)\) for all k: \[f(c_1) = \cos(\frac{\pi}{16})\] \[f(c_2) = \cos(\frac{3\pi}{16})\] \[f(c_3) = \cos(\frac{5\pi}{16})\] \[f(c_4) = \cos(\frac{7\pi}{16})\]
04

Approximate the area under the curve

Finally, we can approximate the area under the curve by adding the area of each of the 4 rectangles. The area of each rectangle is given by its height multiplied by its width: \[ A_k = f(c_k) \Delta x\] Then, the approximate area under the curve is given by the sum of the areas \[ A \approx \sum_{k=1}^{4} A_k = \sum_{k=1}^{4} f(c_k) \Delta x\] \[ A \approx f(c_1)\Delta x + f(c_2)\Delta x + f(c_3)\Delta x + f(c_4)\Delta x \] \[ A \approx \frac{\pi}{8} (\cos(\frac{\pi}{16})+\cos(\frac{3\pi}{16})+\cos(\frac{5\pi}{16})+\cos(\frac{7\pi}{16})) \] Now we have the approximate area under the curve for the function \(f(x) = \cos x\) on the interval \(\left[0, \frac{\pi}{2}\right]\) using 4 rectangles with heights given by the midpoint of each subinterval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral Approximation
When we talk about definite integral approximation, we refer to finding an estimated value of the area under a curve over a specific interval. In calculus, the definite integral represents the exact area under a curve between two points, but exact calculations can be complex or, sometimes, impossible. This is where approximation methods like the Riemann Sum come into play. These methods partition the interval into simpler geometric shapes, such as rectangles or trapezoids, and sum their areas to approximate the integral. It may not be perfect, but with a sufficient number of partitions, the approximation can be very close to the actual area.
Midpoint Rule
The Midpoint Rule is a specific type of Riemann Sum that improves the accuracy of our approximation for a definite integral. Rather than using the left or right endpoints of subintervals to determine the height of the rectangles, the Midpoint Rule takes the value of the function at the midpoint of each subinterval. This tends to give a better estimate because it often balances the overestimate and underestimate that occur with left and right endpoint methods, especially when the function is fairly smooth over the interval. To apply the Midpoint Rule, we divide the total interval into a number of equal parts, find the midpoints for these subintervals, calculate the function value at these midpoints, and then sum up all the areas of rectangles formed by these heights and the uniform width \( \Delta x \).
Rectangular Approximation Method
The Rectangular Approximation Method (RAM) refers to a variety of techniques that use rectangles to approximate the area under a curve. This could involve taking the function's value at the left endpoints (Left Riemann Sum), right endpoints (Right Riemann Sum), or the midpoints (Midpoint Rule), of the subintervals as the height of these rectangles. Each rectangle's area is then the product of its height and its width \( \Delta x \) – which is the length of the subinterval. Summing up all these rectangles' areas provides an approximation of the integral. The more subintervals we use, the thinner the rectangles become, and the closer our approximation gets to the true value of the integral.
Cosine Function Integration
The integration of the cosine function over an interval can be visualized as the area under the curve of \( y = \cos x\) from one point to another on the x-axis. The cosine function oscillates between -1 and 1, and its integral represents accumulated areas with positive and negative values, corresponding to the parts of the curve above and below the x-axis, respectively. Approximating the integral of the cosine function over an interval with Riemann Sums involves summing the areas of rectangles based on the cosine values at chosen points within the subintervals. For functions like cosine that have regular oscillations, methods like the Midpoint Rule often provide a good estimate for the definite integral, as seen in the example provided with \( f(x) = \cos x \) approximated over \( \left[0, \frac{\pi}{2}\right]\) using midpoints.

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