/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 Complete the following table to ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Complete the following table to show that Equation (4). $$ e=\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n} $$ appears to be valid. $$ \begin{array}{|l|l|l|l|l|l|l|l|} \hline n & 1 & 10 & 10^{2} & 10^{3} & 10^{4} & 10^{5} & 10^{6} \\ \hline\left(1+\frac{1}{n}\right)^{n} & & & & & & & \\ \hline \end{array} $$

Short Answer

Expert verified
The completed table shows the values of \(\left(1+\frac{1}{n}\right)^{n}\) for different n: $$ \begin{array}{|l|l|l|l|l|l|l|l|} \hline n & 1 & 10 & 10^{2} & 10^{3} & 10^{4} & 10^{5} & 10^{6} \\ \hline\left(1+\frac{1}{n}\right)^{n} & 2 & 2.5937 & 2.7048 & 2.7169 & 2.7181 & 2.71827 & 2.71828 \\ \hline \end{array} $$ As n increases, the value of \(\left(1+\frac{1}{n}\right)^{n}\) converges towards e (approximately 2.71828), supporting the validity of the equation \(e=\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n}\).

Step by step solution

01

Plug in n = 1 into the expression to find the value for the first column: \[ \left(1+\frac{1}{1}\right)^{1} = (1+1)^{1} = 2 \] #Step 2: Evaluate the expression for n=10#

Plug in n = 10 into the expression to find the value for the second column: \[ \left(1+\frac{1}{10}\right)^{10} \approx 2.5937 \] #Step 3: Evaluate the expression for n=\(10^2\)#
02

Plug in n = \(10^2\) (100) into the expression to find the value for the third column: \[ \left(1+\frac{1}{100}\right)^{100} \approx 2.7048 \] #Step 4: Evaluate the expression for n=\(10^3\)#

Plug in n = \(10^3\) (1000) into the expression to find the value for the fourth column: \[ \left(1+\frac{1}{1000}\right)^{1000} \approx 2.7169 \] #Step 5: Evaluate the expression for n=\(10^4\)#
03

Plug in n = \(10^4\) (10000) into the expression to find the value for the fifth column: \[ \left(1+\frac{1}{10000}\right)^{10000} \approx 2.7181 \] #Step 6: Evaluate the expression for n=\(10^5\)#

Plug in n = \(10^5\) (100000) into the expression to find the value for the sixth column: \[ \left(1+\frac{1}{100000}\right)^{100000} \approx 2.71827 \] #Step 7: Evaluate the expression for n=\(10^6\)#
04

Plug in n = \(10^6\) (1000000) into the expression to find the value for the seventh column: \[ \left(1+\frac{1}{1000000}\right)^{1000000} \approx 2.71828 \] #Step 8: Complete the table with the calculated values#

Now that we have calculated the values of \(\left(1+\frac{1}{n}\right)^{n}\) for each value of n listed in the table, we can fill in the table: $$ \begin{array}{|l|l|l|l|l|l|l|l|} \hline n & 1 & 10 & 10^{2} & 10^{3} & 10^{4} & 10^{5} & 10^{6} \\ \hline\left(1+\frac{1}{n}\right)^{n} & 2 & 2.5937 & 2.7048 & 2.7169 & 2.7181 & 2.71827 & 2.71828 \\ \hline \end{array} $$ The table demonstrates that as n increases, the value of \(\left(1+\frac{1}{n}\right)^{n}\) appears to converge to e (approximately 2.71828), supporting the validity of the given equation: $$ e=\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n} $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Sequences
Understanding the convergence of sequences is a fundamental concept in calculus, as it relates to the behavior of sequences as their index approaches infinity. A sequence converges when its terms draw closer to a specific value as the index grows without bound. This is precisely what we observe with the sequence \( \left(1+\frac{1}{n}\right)^n \) as \( n \) approaches infinity—it approaches a specific number e, known as Euler's number. The exercise provided illustrates this by incrementally increasing the value of \( n \) and calculating the sequence's terms, which demonstrate steadily less deviation from \( e \).
Exponential Functions
The concept of exponential functions revolves around an equation where a constant base is raised to a variable exponent. These functions are crucial for modeling growth and decay processes in science and finance. The expression \( \left(1+\frac{1}{n}\right)^n \) from the exercise resembles the form of an exponential function, where the base \( \left(1+\frac{1}{n}\right) \) gets closer to 1 as \( n \) increases, but the exponent grows without limit. Despite its unconventional appearance, this sequence is a vital example of an exponential function's behavior at infinity and gives rise to the number \( e \), which is the base of natural logarithms and a cornerstone of continuous growth.
Limits in Calculus
The concept of limits in calculus is essential for analyzing functions' behaviors near specific points or at infinity. Limits help in understanding instantaneous rates of change (derivatives) and accumulated quantities (integrals). The expression \( e=\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n} \) encapsulates the limit definition of e and shows how it can be determined through the infinite process of taking higher and higher powers of sequences close to 1. This limit is not straightforward to evaluate by substitution since infinity is not a number, but a concept. Calculus tools such as L'Hôpital's rule or series expansion are often required for a rigorous proof, whereas the textbook exercise provides an intuitive numerical approach.
Infinite Series
While not directly illustrated by the exercise, the topic of infinite series is inherently linked to the limit definition of e. An infinite series is the sum of the terms of an infinite sequence. For example, the number \( e \) can also be represented as the sum of an infinite series: \( e = \sum_{n=0}^{\infty} \frac{1}{n!} \). This series, like the sequence in the table, converges to the numerical value of e as more terms are added. Understanding this and other series is significant for not only computing limits but also for developing deeper insights into functions and their behaviors in calculus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Optimal Inventory Control The equation $$ A(q)=\frac{k m}{q}+c m+\frac{h q}{2} $$ gives the annual cost of ordering and storing (as yet unsold) merchandise. Here, \(q\) is the size of each order, \(k\) is the cost of placing each order, \(c\) is the unit cost of the product, \(m\) is the number of units of the product sold per year, and \(h\) is the annual cost for storing each unit. Determine the size of each order such that the annual cost \(A(q)\) is as small as possible.

Resonance A spring system comprising a weight attached to a spring and a dashpot damping device (see the accompanying figure) is acted on by an oscillating external force. Its motion for large values of \(t\) is described by the equation $$ x(t)=\frac{F}{\left(\omega^{2}-\gamma\right)^{2}+4 \lambda^{2} \gamma^{2}} \sin (\gamma t+\theta) $$ where \(F, \omega, \lambda\), and \(\theta\) are constants. \((F\) is the amplitude of the external force, \(\theta\) is a phase angle, \(\gamma\) is associated with the frequency of the external force, and \(\omega\) and \(\lambda\) are associated with the stiffness of the spring and the degree of resistance of the dashpot damping device, respectively.) Show that the amplitude of the motion of the system $$ g(\gamma)=\frac{F}{\sqrt{\left(\omega^{2}-\gamma^{2}\right)^{2}+4 \lambda^{2} \gamma^{2}}} $$ has a maximum value at \(\gamma_{1}=\sqrt{\omega^{2}-2 \lambda^{2}}\). When the frequency of the external force is \(\sqrt{\omega^{2}-2 \lambda^{2}} / 2 \pi\), the system is said to be in resonance. The figure below shows a typical resonance curve. The external force imparts an oscillatory vertical motion on the support.

In Exercises \(55-58\), plot the graph of the function. $$ f(x)=\frac{x^{2}+x}{3 x^{2}+x-1} $$

Energy Expended by a Fish It has been conjectured that the total energy expended by a fish swimming a distance of \(L \mathrm{ft}\) at a speed of \(v \mathrm{ft} / \mathrm{sec}\) relative to the water and against a current flowing at the rate of \(u \mathrm{ft} / \mathrm{sec}(u

In Exercises 39-42, find the slant asymptotes of the graphs of the function. Then sketch the graph of the function. $$ f(x)=\frac{x^{2}-2 x-3}{2 x-2} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.