/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Find the horizontal and vertical... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the horizontal and vertical asymptotes of the graph of the function. Do not sketch the graph. $$ f(x)=\frac{2 x}{x^{2}-x-6} $$

Short Answer

Expert verified
The function \(f(x)=\frac{2x}{x^2-x-6}\) has two vertical asymptotes at \(x=-2\) and \(x=3\) and one horizontal asymptote at \(y=0\).

Step by step solution

01

Identify the function type

The given function is a rational function with both numerator and denominator being polynomials. $$ f(x)=\frac{2x}{x^2-x-6} $$
02

Find the vertical asymptotes

The vertical asymptotes occur when the denominator is equal to zero, and the numerator is not equal to zero at the same time. First, let's find the roots of the denominator. We can find the roots by factoring or using the quadratic formula, but for simplicity, we will use factoring. $$ x^2-x-6 = (x-3)(x+2) $$ The denominator is zero when \(x=3\) and \(x=-2\). These are the equations of the vertical asymptotes: $$ x=3 \\ x=-2 $$
03

Find the horizontal asymptotes

Horizontal asymptotes depend on the degree (highest power) of the numerator and denominator. Three cases can arise while finding horizontal asymptotes: 1. The degree of numerator < degree of denominator 2. The degree of numerator = degree of denominator 3. The degree of numerator > degree of denominator In the given function, the degree of the numerator is 1, and the degree of the denominator is 2. We see that the degree of the numerator is less than the degree of the denominator (case 1). When the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \(y=0\). Therefore, there is a horizontal asymptote at \(y=0\).
04

Summary

The function \(f(x)=\frac{2x}{x^2-x-6}\) has two vertical asymptotes at \(x=-2\) and \(x=3\) and one horizontal asymptote at \(y=0\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
Rational functions are an important class of functions in mathematics. They are defined as the ratio between two polynomials. In simpler terms, a rational function looks something like this: \( f(x) = \frac{P(x)}{Q(x)} \) where both \( P(x) \) and \( Q(x) \) are polynomials. These functions are frequently used because they can model relationships in various fields, such as economics or engineering.
One key feature of rational functions is that they are only defined when the denominator is not equal to zero. This is because a division by zero is undefined in mathematics. Therefore, the values of \( x \) which make \( Q(x) = 0 \) are excluded from the domain of the function.
Vertical Asymptotes
Vertical asymptotes are lines that the graph of a function approaches but never actually touches or crosses as it heads towards infinity. For rational functions specifically, vertical asymptotes occur at values where the denominator is equal to zero but the numerator is not zero. These values make the function undefined and often cause the graph to spike upwards or downwards indefinitely.
To find these vertical asymptotes, you resolve the equation \( Q(x) = 0 \). For the function \( f(x) = \frac{2x}{x^2-x-6} \), the denominator \( x^2-x-6 \) factors into \((x-3)(x+2)\). Hence, the vertical asymptotes are at \( x = 3 \) and \( x = -2 \), because those are the points where the denominator becomes zero.
Horizontal Asymptotes
Horizontal asymptotes describe the behavior of a graph as \( x \) approaches infinity. Unlike vertical asymptotes, the graph of a function can intersect horizontal asymptotes in its finite range but will eventually approach them infinitely. In rational functions, horizontal asymptotes depend on the degrees of the numerator and the denominator.
There are three key cases to consider:
  • If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \( y=0 \).
  • If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is the ratio of the leading coefficients.
  • If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote, but there might be an oblique asymptote instead.
For \( f(x) = \frac{2x}{x^2-x-6} \), the degree of the numerator is \( 1 \) and the degree of the denominator is \( 2 \). Since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \( y=0 \).
Polynomials
Understanding polynomials is crucial for mastering rational functions. Polynomials are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients. For example, \( x^2 - x - 6 \) is a polynomial with a degree of 2, since the highest power of \( x \) is 2. Each individual term in a polynomial is called a monomial, and they can include constants, variables, and exponents.
Polynomials can be classified by their degree, which is the highest exponent of the variable. The degree plays a significant role in determining the behavior of rational functions, including vertical and horizontal asymptotes. Moreover, when dealing with rational functions, working with polynomials involves performing operations such as addition, subtraction, multiplication, and factoring. Factoring is particularly useful for finding the roots of a polynomial, which are the values of \( x \) that make the polynomial equal to zero.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the given statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false. If the denominator of a rational function \(f\) is equal to zero at \(a\), then \(x=a\) is a vertical asymptote of the graph of \(f\).

What can you say about the sequence of approximations obtained using Newton's method if your initial estimate, through a stroke of luck, happens to be the root you are seeking?

Find the accumulated amount after 5 years on an investment of \(\$ 5000\) earning interest at the rate of \(10 \%\) per year compounded continuously.

Use Newton's method to approximate the indicated zero of the function. Continue with the iteration until two successive approximations differ by less than \(0.0001\). The zero of \(f(x)=x^{3}+x-4\) between \(x=0\) and \(x=2\). Take \(x_{0}=1\).

Cells of a Honeycomb The accompanying figure depicts a single prism-shaped cell in a honeycomb. The front end of the prism is a regular hexagon, and the back is formed by the sides of the cell coming together at a point. It can be shown that the surface area of a cell is given by $$ S(\theta)=6 a b+\frac{3}{2} b^{2}\left(\frac{\sqrt{3}-\cos \theta}{\sin \theta}\right) \quad 0<\theta<\frac{\pi}{2} $$ where \(\theta\) is the angle between one of the (three) upper surfaces and the altitude. The lengths of the sides of the hexagon, \(b\), and the altitude, \(a\), are both constants. a. Show that the surface area is minimized if \(\cos \theta=1 / \sqrt{3}\), or \(\theta \approx 54.7^{\circ} .\) (Measurements of actual honeycombs have confirmed that this is, in fact, the angle found in beehives.)b. Using a graphing utility, verify the result of part (a) by finding the absolute minimum of $$ f(\theta)=\frac{\sqrt{3}-\cos \theta}{\sin \theta} \quad 0<\theta<\frac{\pi}{2} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.