Chapter 3: Problem 40
$$ \text { Let } g(x)=\frac{\cos x}{\sqrt{x}} . \text { Find } \lim _{x \rightarrow \infty} g(x) \text { . } $$
Short Answer
Expert verified
The limit of g(x) as x approaches infinity is 0, expressed mathematically as: \[\lim_{x\rightarrow \infty} \frac{\cos x}{\sqrt{x}} = 0\]
Step by step solution
01
Analyze the behavior of \(\cos x\) as \(x \rightarrow \infty\)
As x approaches infinity, the value of the cosine function oscillates between -1 and 1. Thus, we cannot make any definitive conclusions about the behavior of \( \cos x\) as \(x \rightarrow \infty\).
02
Analyze the behavior of \(\sqrt{x}\) as \(x \rightarrow \infty\)
As x approaches infinity, the value of \(\sqrt{x}\) also approaches infinity. This indicates that the denominator of our function will become larger and larger as x increases.
03
Determine the limit of g(x) as \(x \rightarrow \infty\)
As we found out earlier, the cosine function oscillates between -1 and 1, while the denominator \(\sqrt{x}\) approaches infinity. Since the numerator is always between -1 to 1 and the denominator is increasing indefinitely, we can conclude that the limit of \(\frac{\cos x}{\sqrt{x}}\) as \(x \rightarrow \infty\) is 0.
Mathematically, we express this as: \[\lim_{x\rightarrow \infty} g(x) = \lim_{x\rightarrow \infty} \frac{\cos x}{\sqrt{x}} = 0\]
So, the limit of g(x) as x approaches infinity is 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine function
The cosine function, denoted as \( \cos x \), is a periodic trigonometric function. It is known for its wave-like behavior due to its constant oscillation between the values of -1 and 1. This oscillation occurs because cosine is defined based on the unit circle, where it represents the horizontal coordinate of a point moving around the circle. The frequency of this oscillation is consistent, with a complete cycle repeating every
- \(2\pi\): a full rotation around the circle translates to 360 degrees.
Square root function
The square root function, expressed as \( \sqrt{x} \), operates by taking the non-negative square root of the variable \( x \). In mathematical terms, for a non-negative input \( x \), the square root function returns a value \( y \) such that \( y^2 = x \). At first glance, this function might seem simple, but its properties play a significant role when considering limits approaching infinity.
- As \( x \) increases without bound, \( \sqrt{x} \) also increases.
- However, the growth rate of \( \sqrt{x} \) is slower than that of \( x \) itself.
Behavior of functions at infinity
When analyzing functions as their inputs approach infinity, we are interested in understanding what the output does as the input grows larger and larger. For a function such as \( g(x) = \frac{\cos x}{\sqrt{x}} \), this process involves considering both the numerator and denominator separately:
- The numerator, \( \cos x \), remains bounded between -1 and 1 because it oscillates.
- The denominator, \( \sqrt{x} \), approaches infinity since it continuously increases with increasing \( x \).