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In Exercises \(25-40\), find the critical number \((s)\), if any, of the function. $$ f(t)=\cos ^{2}(2 t) $$

Short Answer

Expert verified
The critical numbers of the function \(f(t) = \cos^2(2t)\) are \(t = \frac{(2n + 1)\pi}{4}\) and \(t = \frac{n\pi}{2}\), where n is an integer.

Step by step solution

01

Find the derivative of the function with respect to t

To find the derivative of \(f(t) = \cos^2(2t)\), we will use the Chain Rule, which states that if we have a function \(g(h(t))\), then the derivative with respect to t is given by \(g'(h(t))\cdot h'(t)\). Let \(g(u) = u^2\) and \(h(t) = \cos(2t)\). So, our function \(f(t) = g(h(t))\). Now let's find the derivative of g(u) and h(t) with respect to their variables: \(g'(u) = \frac{d(u^2)}{du} = 2u\) \(h'(t)=\frac{d(\cos(2t))}{dt} = -2\sin(2t)\) Now, applying the Chain Rule to find the derivative of f(t): \(f'(t) = g'(h(t)) \cdot h'(t) = 2\cos(2t) \cdot (-2\sin(2t))\)
02

Find the values of t for which the derivative is equal to zero

To find the critical numbers, we need to find when \(f'(t) = 0\). So, let's solve the equation: \(2\cos(2t) \cdot (-2\sin(2t)) = 0\) This product is zero when either factor is equal to zero. So, we solve for t separately in both cases. Case 1: \(\cos(2t) = 0\) \(2t = \frac{(2n + 1)\pi}{2}\), where n is an integer \(t = \frac{(2n + 1)\pi}{4}\) Case 2: \(\sin(2t) = 0\) \(2t = n\pi\), where n is an integer \(t = \frac{n\pi}{2}\)
03

Combine the solutions

The critical numbers are the solutions we found in both cases: \(t = \frac{(2n + 1)\pi}{4}\), where n is an integer and \(t = \frac{n\pi}{2}\), where n is an integer

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
Finding the derivative of a function is essential to understand how the function behaves. The derivative measures how a function changes as its input changes—essentially, it tells us the slope of the function at any point. For the given function, \( f(t) = \cos^2(2t) \), we followed the rule of differentiation to express the snappiness of the curve. By differentiating step-by-step, we illuminate the twisty paths of trigonometric functions to reveal a more straightforward snapshot: the rate of change. If you're struggling with derivatives, remember they give us critical insights into the shape and tendencies of a curve. It's like having a GPS that guides you through the landscape of functions. Just follow the calculus road rules, starting with breaking down complex functions into bite-sized pieces like \( g'(h(t)) \cdot h'(t) \). This is the functional way to do math!
Chain Rule
The Chain Rule is an essential technique when working with composite functions, i.e., functions within functions. This rule allows you to break down complex differentiation problems into simpler parts. It's like peeling an onion one layer at a time. For \( f(t) = \cos^2(2t) \), we see two layers: an outer function \( u^2 \) and an inner function \( \cos(2t) \). To find the derivative, you differentiate the outer layer \( g(u) \) with respect to the inner layer \( h(t) \), and then multiply by the derivative of the inner layer. Mathematically, we express this as:
  • \( g'(u) = 2u \)
  • \( h'(t) = -2\sin(2t) \)
Applying the Chain Rule, we can easily find the rate at which \( f(t) \) changes, paving the way to uncover the critical numbers. It's a fundamental tool that untangles even the most intricate functions, making them solvable and understandable.
Trigonometric Identities
Understanding trigonometric identities is crucial for simplifying the differentiation and solving equations involving trigonometric functions like \( \cos(2t) \) and \( \sin(2t) \). These identities help in rewriting trig functions in ways that make problems more tractable. For instance, knowing that \( \cos(2t) \) becomes zero at specific angles allows us to find when factors involving these functions equal zero. Similarly, for \( \sin(2t) \), using the identity that the sine function is zero at integer multiples of \( \pi \) gives us crucial insights into where a function's slope vanishes. Trig identities are reliable shortcuts in calculus—like secret paths through a dense forest of mathematics.
Function Analysis
Function analysis involves dissecting a function to understand its properties, such as where it increases, decreases, and hits zero slopes—its critical points. With \( f(t) = \cos^2(2t) \), finding critical numbers requires determining where the derivative equals zero. By setting each part of the derivative \( 2\cos(2t) \cdot (-2\sin(2t)) \) to zero, we find points where the function shifts from rising to falling, or vice versa. This step of solving \( \cos(2t) = 0 \) and \( \sin(2t) = 0 \) involves solving a combination of simple equations, and it grants us a clearer picture of the function's behavior. This critical point exploration helps predict function behavior just as a map shows you the highs and lows of a mountain. Function analysis ties together derivative knowledge and trigonometric identities, all essential elements of understanding a function's complete portrait.

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