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Use the definition of the derivative to find the derivative of the function. What is its domain? \(f(x)=2 x+1\)

Short Answer

Expert verified
The derivative of the function \(f(x) = 2x + 1\) is \(f'(x) = 2\), and its domain is \((-\infty, \infty)\).

Step by step solution

01

Write down the function

The given function is: \(f(x) = 2x + 1\)
02

Apply the definition of the derivative

Using the definition of the derivative, we'll find \(f'(x)\) as follows: \(f'(x) = \lim_{h\to 0}\frac{f(x + h) - f(x)}{h}\)
03

Plug in the function in the formula

Replace \(f(x + h)\) and \(f(x)\) with their respective expressions: \(f'(x) = \lim_{h\to 0}\frac{(2(x + h) + 1) - (2x + 1)}{h}\)
04

Simplify the expression

Simplify the expression inside the limit: \(f'(x) = \lim_{h\to 0}\frac{2x + 2h + 1 - 2x - 1}{h}\) \(f'(x) = \lim_{h\to 0}\frac{2h}{h}\)
05

Cancel terms and find the limit

First, cancel out the terms in the numerator and denominator, then evaluate the limit as \(h\) approaches 0: \(f'(x) = \lim_{h\to 0} 2\) The limit is a constant, so the derivative is simply: \(f'(x) = 2\)
06

Find the domain

Now that we have the derivative, let's determine the domain of the function \(f(x) = 2x + 1\). The given function is a linear function, which is defined for all values of \(x\). Therefore, the domain of the function is: Domain: \((-\infty, \infty)\)
07

Final Answer

The derivative of the function \(f(x) = 2x + 1\) is \(f'(x) = 2\), and its domain is \((-\infty, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Function
A linear function is a mathematical expression that creates a straight line when plotted on a graph. It follows a basic format of \(f(x) = mx + b\), where \(m\) represents the slope and \(b\) is the y-intercept. In this specific problem, the given function is \(f(x) = 2x + 1\).
Here:
  • The coefficient of \(x\) is \(2\), which is the slope of the line.
  • The constant \(1\) is where the line crosses the y-axis, known as the y-intercept.
Linear functions are especially simple because they change at a constant rate as \(x\) values change. This constant change gives us a straight line, making calculations like derivatives a breeze.
Function Domain
The domain of a function refers to all the possible input values (or \(x\) values) that will produce an output when plugged into the function. In simpler terms, it's all the \(x\) values that make the function work.

For linear functions, like \(f(x) = 2x + 1\), the domain is all real numbers. This is because you can substitute any real number for \(x\), and it won't cause any mathematical issues like division by zero or square rooting a negative number.

Thus, for the linear function \(f(x) = 2x + 1\), the domain is expressed as \(( -\infty, \infty)\), meaning any real number is valid.
Limit Evaluation
When we are finding the derivative of a function using its definition, we rely on the concept of limits. The limit helps us determine the behavior of a function as it approaches a particular point. In derivative calculation, we are interested in the function's behavior as the change in \(x\) (denoted as \(h\)) becomes infinitely small.

In this problem, the limit definition of the derivative is given by:\[f'(x) = \lim_{h\to 0}\frac{f(x + h) - f(x)}{h}\]Applying it to our function \(f(x) = 2x + 1\), requires us to substitute and simplify the expression within the limit.

After substitution, notice how the terms \(2x + 1\) cancel each other out, leaving us with \(\frac{2h}{h}\), which simplifies further to \(2\). As \(h\) approaches zero, the expression becomes a constant \(2\), revealing that the derivative is a constant value.
Derivative Calculation
Derivative calculation using the definition is a fundamental technique to find how a function changes at any given point. The derivative tells us the instantaneous rate of change or the slope of the function at a specific point.

To calculate the derivative of the function \(f(x) = 2x + 1\) using its definition:
  • Substitute the function into the limit definition \(f'(x) = \lim_{h\to 0}\frac{f(x + h) - f(x)}{h}\).
  • Simplify the result inside the limit. In our example, simplifying gives \(\frac{2h}{h}\).
  • This reduces further to \(2\), as \(h\) cancels out in the fraction.
Finally, since the expression is constant as \(h\) approaches zero, the derivative is \(f'(x) = 2\). This implies our linear function has a consistent slope of \(2\) everywhere on its graph.

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