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A Recall that for Stanford-Binet IQ scores the mean is 100 and the standard deviation is 15 . a. Use the Empirical Rule to specify the ranges into which \(68 \%, 95 \%,\) and \(99.7 \%\) of Stanford- Binet IQ scores fall. b. Draw a picture similar to Figure 8.6 for Stanford-Binet scores, illustrating the ranges from part (a).

Short Answer

Expert verified
68%: 85-115, 95%: 70-130, 99.7%: 55-145.

Step by step solution

01

Understand the Empirical Rule

The Empirical Rule, also known as the 68-95-99.7 rule, helps us understand the distribution of data in a normal distribution. It states that approximately 68% of the data falls within one standard deviation (SD) of the mean, 95% within two standard deviations, and 99.7% within three standard deviations.
02

Apply the Empirical Rule for 68% of Data

To find the range for 68% of IQ scores: Calculate one standard deviation from the mean. \(Mean = 100\), \(SD = 15\). One standard deviation below and above the mean is: \[ 100 - 15 = 85 \] \[ 100 + 15 = 115 \] Thus, 68% of the scores fall between 85 and 115.
03

Calculate the Range for 95% of Data

For the range where 95% of IQ scores fall, calculate two standard deviations from the mean:\[ 100 - 2\times15 = 70 \] \[ 100 + 2\times15 = 130 \]Therefore, 95% of the scores fall between 70 and 130.
04

Determine the Range for 99.7% of Data

For the range where 99.7% of IQ scores fall, calculate three standard deviations from the mean:\[ 100 - 3\times15 = 55 \] \[ 100 + 3\times15 = 145 \]Hence, 99.7% of the scores fall between 55 and 145.
05

Illustrate the Distribution with a Picture

To visualize the distribution, draw a normal curve centered at the mean (100). Mark intervals at one (85 to 115), two (70 to 130), and three (55 to 145) standard deviations from the mean. Shade the areas under the curve up to these points to illustrate the percentages of 68%, 95%, and 99.7% respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
A normal distribution is a fundamental concept in statistics that describes how data points are spread around a central value. When graphed, it forms a bell-shaped curve which is symmetric around the mean. This curve is crucial because many naturally occurring phenomena tend to follow this distribution. For instance, IQ scores of a large group of people usually exhibit traits of a normal distribution.

The Empirical Rule aids in understanding this concept by providing insights into how data is distributed. It tells us that
  • 68% of the data lies within one standard deviation from the mean.
  • 95% falls within two standard deviations.
  • 99.7% fits within three standard deviations.
This means most data points cluster around the mean, creating the characteristic shape of the normal distribution curve.

Understanding normal distribution is crucial as it helps in making predictions about a dataset and in calculating probabilities. It's the foundation for many statistical methods used in research and data analysis.
Standard Deviation
Standard deviation is a key measure in statistics that quantifies the amount of variation or spread in a set of data values. It tells us, on average, how far each data point is from the mean. A smaller standard deviation indicates that the data points tend to be close to the mean, while a larger standard deviation indicates more spread out data.

For IQ scores, if the mean is 100 and the standard deviation is 15, it means that most people's IQs are within 15 points of the mean. This is significant because it enables us to apply the Empirical Rule to determine what percentage of the data falls within certain ranges. Using the standard deviation, we can pinpoint:
  • 68% of the scores will fall between 85 and 115.
  • 95% between 70 and 130.
  • 99.7% between 55 and 145.
This calculation is essential for understanding the spread of IQ scores and predicting outcomes within this context.

The importance of standard deviation goes beyond IQ scores. It is widely used in various fields, such as finance, to assess risk, and in quality control, to monitor process variability.
Mean
In any set of data, the mean is the average value which acts as a central point. It is calculated by adding up all the numbers and then dividing by the total count of numbers. For IQ scores, the mean is 100, providing a benchmark to understand where most scores fall.

An important aspect of the mean in a normal distribution is that it acts as the peak of the bell curve. It splits the curve into two equal halves, underscoring its centrality. The mean gives a quick snapshot of the data set, making it easier to grasp the general trend.

In combination with standard deviation, the mean helps apply the Empirical Rule, providing detailed insights into the distribution of scores. For instance, knowing the mean is part of calculating specific ranges of scores, such as knowing that few people will have an IQ significantly lower or higher than 100.

The mean is a simple yet powerful statistic that is applied in many real-world scenarios, from determining average temperatures to summarizing financial reports, making it a critical concept to understand fully.

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Most popular questions from this chapter

For every 100 births in the United States, the number of boys follows, approximately, a normal curve with a mean of 51 boys and standard deviation of 5 boys. If the next 100 births in your local hospital resulted in 36 boys (and thus 64 girls), would that be unusual? Explain.

Find the percentile for the observed value in the following situations: a. Quantitative reasoning GRE score of 146 (mean \(=151.3\), s.d. \(=8.7\) ). b. Stanford-Binet IQ score of 97 (mean \(=100,\) s.d. \(=15\) ). c. Woman's height of 68 inches (mean \(=65\) inches, s.d. \(=2.5\) inches) d. Man's height of \(68 \text { inches (mean }=70 \text { inches, s.d. }=3 \text { inches })\)

Over many years, rainfall totals for Sacramento, CA, in January ranged from a low of about 0.05 inch to a high of about 19.5 inches. The median was about 3.1 inches. Based on this information, explain how you can tell that the distribution of rainfall values in Sacramento in January cannot be bell-shaped.

The 84 th percentile for the Stanford-Binet IQ test is 115 . (Recall that the mean is 100 and the standard deviation is 15.) a. Verify that this is true by computing the standardized score and using Table 8.1 b. Draw pictures of the original and standardized scores to illustrate this situation, similar to the pictures in Eigure \(8.4 .\)

Every time you have your cholesterol measured, the measurement may be slightly different due to random fluctuations and measurement error. Suppose that for you, the population of possible cholesterol measurements if you are healthy has a mean of 190 and a standard deviation of 10 . Further, suppose you know you should get concerned if your measurement ever gets up to the 97th percentile. What level of cholesterol does that represent?

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