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Mensa is an organization that allows people to join only if their IQs are in the top \(2 \%\) of the population. a. What is the lowest Stanford-Binet IQ you could have and still be eligible to join Mensa? (Remember that the mean is 100 and the standard deviation is \(15 .\) ) b. Mensa also allows members to qualify on the basis of certain standard tests. If you were to try to qualify on the basis of the quantitative reasoning part of the GRE exam, what score would you need on the exam? (Remember that the mean is 151.3 and the standard deviation is \(8.7,\) and round your answer to the closest whole number.)

Short Answer

Expert verified
IQ requirement: 131; GRE score requirement: 169.

Step by step solution

01

Identify percentile for Mensa eligibility

Mensa requires an IQ within the top \(2\%\) of the population. Thus, we look for the \(98\)th percentile of the IQ distribution since being within the top \(2\%\) means scoring higher than \(98\%\) of the population.
02

Use Z-score to find IQ threshold

For a normal distribution, the Z-score corresponding to the \(98\)th percentile is approximately \(2.05\). We use the formula for a Z-score: \[Z = \frac{X - \mu}{\sigma}\]where \(X\) is the IQ score, \(\mu\) is the mean IQ of \(100\), and \(\sigma\) is the standard deviation of \(15\). Solving for \(X\):\[\begin{align*}2.05 & = \frac{X - 100}{15} \X - 100 & = 2.05 \times 15\X & = 30.75 + 100\X & = 130.75\end{align*}\]Since IQ scores are usually reported as whole numbers, we round up to the nearest whole number: \(131\).
03

Identify percentile for GRE score

Similar to the IQ scenario, Mensa requires a GRE quantitative reasoning score in the top \(2\%\) of the population. Thus, we again look for the \(98\)th percentile.
04

Use Z-score to find GRE threshold

Using the standard GRE mean and standard deviation, the formula becomes:\[Z = \frac{Y - \mu_{GRE}}{\sigma_{GRE}}\]where \(Y\) is the GRE score, \(\mu_{GRE}\) is \(151.3\), and \(\sigma_{GRE}\) is \(8.7\). Plugging in the Z-score:\[\begin{align*}2.05 & = \frac{Y - 151.3}{8.7} \Y - 151.3 & = 17.835\Y & = 169.135\end{align*}\]We round \(Y\) to the nearest whole number, giving us a score of \(169\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentile
In the world of statistics and probability, a percentile is a measure that indicates the value below which a given percentage of observations fall. For example, if you're working with IQ scores and you find someone in the 98th percentile, it means that their score is higher than 98% of the people.
This concept is crucial when determining eligibility for organizations like Mensa, which only admits individuals scoring within the top 2% or, equivalently, at the 98th percentile.
To find such a percentile in a normal distribution, you typically use a Z-score table or a statistical software to match the Z-score that corresponds with the desired percentile, such as the 98th.
  • A 98th percentile rank tells us how a score compares with the rest of the data.
  • Percentiles can help in ranking how well an individual performs relative to others.
By knowing how percentiles work, you can assess your standing in various contexts, like exams and standardized tests.
Z-score
The Z-score is a statistical measurement that describes a value's relation to the mean of a group of values, measured in terms of standard deviations from the mean.
To put it simply: it tells you how many standard deviations a data point is from the mean. In our example, a Z-score allows us to find what raw score corresponds to a specific percentile of a normal distribution.
The Z-score is particularly useful to compare data points from different distributions or to find out how unusual a particular data point is.
  • The formula for Z-score is: \( Z = \frac{X - \mu}{\sigma} \)
  • \(X\) is the value of the element, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
For the Mensa IQ example, a Z-score of approximately 2.05 corresponds to the 98th percentile. By plugging this Z-score into the formula, it helps us find the IQ threshold for Mensa membership. Similarly, we can calculate the required GRE score to meet the top percentiles for qualification.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. It tells us how much the members of a dataset differ from the mean.
A small standard deviation means the data points are close to the mean, whereas a large standard deviation indicates that the data points are spread out over a wider range.
For normally distributed data, 68% of data points lie within one standard deviation of the mean, 95% within two, and 99.7% within three. In our context, it helps to understand how scores such as IQ or GRE are distributed around the average.
  • Standard deviation formula: \( \sigma = \sqrt{\frac{\sum{(X_i - \mu)^2}}{N}} \)
  • \(X_i\) is each value in the dataset, \(\mu\) is the mean, and \(N\) is the number of data points.
Understanding standard deviation is key to interpreting the variability and spread of scores in standardized testing, which is crucial for determining percentile and Z-scores.

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Most popular questions from this chapter

Remember from Chapter 7 that the range for a data set is found as the difference between the maximum and minimum values. Explain why it makes sense that for a bell-shaped data set of a few hundred values, the range should be about 4 to 6 standard deviations. (Hint: Use the Empirical Rule.)

Over many years, rainfall totals for Sacramento, CA, in January ranged from a low of about 0.05 inch to a high of about 19.5 inches. The median was about 3.1 inches. Based on this information, explain how you can tell that the distribution of rainfall values in Sacramento in January cannot be bell-shaped.

A graduate school program in Statistics will admit only students with quantitative reasoning GRE scores in the top \(30 \%\). What is the lowest GRE score it will accept? (Recall the mean is 151.3 and the standard deviation is \(8.7,\) and round your answer to the closest whole number.)

For every 100 births in the United States, the number of boys follows, approximately, a normal curve with a mean of 51 boys and standard deviation of 5 boys. If the next 100 births in your local hospital resulted in 36 boys (and thus 64 girls), would that be unusual? Explain.

Give an example of a population of measurements that would not have a normal distribution for each of the following reasons. a. The measurement can only result in a small number of possible values, instead of the continuum over a substantial range that is required for a normal distribution. b. The measurement cannot go below \(0,\) but is likely to be skewed to the right because it is extremely high for a small subset of all individuals.

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