/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Suppose you were given a hypothe... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose you were given a hypothesized population mean, a sample mean, a sample standard deviation, and a sample size for a study involving a random sample from one population. What formula would you use for the test statistic?

Short Answer

Expert verified
Use the t-test statistic formula: \( t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \).

Step by step solution

01

Understanding the Problem

We need to find the formula for the test statistic to compare the sample mean with a hypothesized population mean. This involves hypothesis testing.
02

Identify the Variables

We have the following variables: hypothesized population mean \( \mu_0 \), sample mean \( \bar{x} \), sample standard deviation \( s \), and sample size \( n \).
03

Selecting the Right Test

Since we have the sample standard deviation, the appropriate test is the t-test, used for small sample sizes or unknown population standard deviations.
04

Formula for Test Statistic

The formula for the t-test statistic is: \[ t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]where \( \bar{x} \) is the sample mean, \( \mu_0 \) is the hypothesized population mean, \( s \) is the sample standard deviation, and \( n \) is the sample size.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions or inferences about a population parameter based on a sample statistic. It starts with a claim or assumption about the population, called the null hypothesis (\(H_0\)). This hypothesis usually represents no effect or no difference between groups. For example, you might say the population mean is equal to a specified value.
  • Null Hypothesis (\(H_0\)): The assumption we test about the population parameter, usually stating no effect or no difference.
  • Alternative Hypothesis (\(H_a\)): The research hypothesis, suggesting there is an effect or a difference.
In practice, data is collected and used to calculate a test statistic, which helps determine if the observed data significantly deviates from what the null hypothesis predicts. We then use this test statistic to decide if we should reject the null hypothesis or fail to reject it.
Hypothesis testing is critical in fields such as medicine, psychology, and economics, where decisions are based on sample data rather than entire populations.
Sample Mean
The sample mean (\(\bar{x}\)) is one of the fundamental concepts of statistics. It is the average of all the data points in a sample. The sample mean provides an estimate of the overall population mean when it is impractical to measure the entire population.
Calculating the sample mean involves adding up all the data values in the sample and dividing by the number of values (sample size, \(n\)). The formula for this is:\[ \bar{x} = \frac{\sum x_i}{n} \]where \(x_i\) represents each data point in the sample.
The sample mean is crucial in hypothesis testing as it allows us to make inferences about the population mean. It is often used to compare against a hypothesized population mean to see if there is a statistical difference. In hypothesis testing, the sample mean is used in the formula to calculate the test statistic.
Population Mean
The population mean (\(\mu\)) is the average of all data points in a population. While it provides a complete picture of the population's central tendency, it is often difficult or impossible to calculate because obtaining data from every member of a population is not usually feasible.
When conducting hypothesis testing, we often have a hypothesized population mean (\(\mu_0\)). This is the value we assume for the population mean and is the basis for forming the null hypothesis.
  • Hypothesized Population Mean (\(\mu_0\)): This is the assumed value of the population mean for the purpose of hypothesis testing.
The hypothesized population mean is compared with the sample mean in the hypothesis test to determine if any observed difference is statistically significant. The outcome of this test can either support the initial hypothesis or suggest an alternative hypothesis might be more plausible.
Sample Standard Deviation
Sample standard deviation (\(s\)) measures the dispersion or variability of a dataset about its mean. It quantifies the amount of variation or spread in the sample data points.
To calculate the sample standard deviation, you need to:
  • Compute the difference between each data point and the sample mean.
  • Square these differences.
  • Sum up all the squared differences.
  • Divide by the sample size minus one (\(n-1\)), since we're dealing with a sample rather than a whole population.
  • Take the square root of the result.
Expressed mathematically, this is:\[s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}\]The sample standard deviation plays a vital role in hypothesis tests like the t-test, where it is used to normalize data, allowing meaningful comparisons between sample data and hypothesized population parameters.
Test Statistic
The test statistic is a key calculation in hypothesis testing that allows us to decide whether or not to reject the null hypothesis. It is calculated using sample data and is compared against a standard value from the statistical distribution that applies to the test you are conducting.
In cases where the population standard deviation is unknown and the sample size is small, the t-test is commonly used. For the t-test, the test statistic (\(t\)) is calculated using the formula:\[ t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]where:
  • \(\bar{x}\) is the sample mean,
  • \(\mu_0\) is the hypothesized population mean,
  • \(s\) is the sample standard deviation,
  • \(n\) is the sample size.
The test statistic measures how far the sample mean deviates from the hypothesized mean in units of standard error. A large absolute value of the test statistic indicates that the sample mean is far from the hypothesized mean, suggesting that it may be statistically significant, while a small value indicates the sample mean is close to the hypothesized mean.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A CNN/ORC poll conducted in January, 2013 , asked 814 adults in the United States, "Which of the following do you think is the most pressing issue facing the country today?" and then presented seven choices, one of which was "The Economy." (Source: http://www.pollingreport.com/prioriti.htm, accessed July 16, 2013.) "The Economy" was chosen by \(46 \%\) of the respondents. Suppose an unscrupulous politician wanted to show that the economy was not a pressing issue, and stated "Significantly fewer than half of adults think that the economy is a pressing issue." a. What are the null and alternative hypotheses the politician is implicitly testing in this quote? Make sure you specify the population value being tested and the population to which it applies. b. Using the results of the poll, find the value of the standardized score that would be used as the test statistic. c. If you answered parts (a) and (b) correctly, the \(p\) -value for the test should be about 0.011 . Explain how the politician reached the conclusion stated in the quote. d. Do you think the statement made by the politician is justified? Explain.

One of the results was "there were no significant sex differences in memory for pictures rated less intense \((0-2)\) or in false-positive rates \((12 \text { and } 10 \%\) for women and men, respectively)" (Canli et al., 2002, p. 10790). a. What is meant by "false positive rates" in this example? b. Specify in words the null hypothesis being tested regarding false positives. Make sure you don't confuse the population with the sample and that you state the hypothesis using the correct one. c. Is the use of the word significant in the quote the statistical version or the English version or both? Explain how you know.

Participants were given psychological tests measuring positive and negative affect (mood) as well as anxiety at three time periods. Time 1 was before the meditation training. Time 2 was at the end of the 8 weeks of training, and Time 3 was 4 months later. One of the results reported is: There was a significant decrease in trait negative affect with the meditators showing less negative affect at Times 2 and 3 compared with their negative affect at Time \(1[t(20)=2.27 \text { and } t(21)=2.45, \text { respectively, } p<.05 \text { for both }] .\) Subjects in the control group showed no change over time in negative affect ( \(t<1\) ) (Davidson et al, \(p .565\) ). The first sentence of the quote reports the results of two hypothesis tests for the meditators. Specify in words the null hypothesis for each of the two tests. They are the same except that one is for Time 2 and one is for Time 3. State each one separately, referring to what the time periods were. Make sure you don’t confuse the population with the sample and that you state the hypotheses using the correct one.

On January \(30,1995,\) Time magazine reported the results of a poll of adult Americans, in which they were asked, "Have you ever driven a car when you probably had too much alcohol to drive safely?" The exact results were not given, but from the information provided we can guess at what they were. Of the 300 men who answered, 189 ( \(63 \%\) ) said yes and 108 ( \(36 \%\) ) said no. The remaining three weren't sure. Of the 300 women, 87 ( \(29 \%\) ) said yes while \(210(70 \%)\) said no, and the remaining three weren't sure. a. Ignoring those who said they weren't sure, there were 297 men asked, and 189 said yes, they had driven a car when they probably had too much alcohol. Does this provide statistically significant evidence that a majority of men in the population (that is, more than half) would say that they had driven a car when they probably had too much alcohol, if asked? Go through the four steps to test this hypothesis. b. For the test in part (a), you were instructed to perform a one-sided test. Why do you think it would make sense to do so in this situation? If you do not think it made sense, explain why not. c. Repeat parts (a) and (b) for the women. (Note that of the 297 women who answered, 87 said yes.) The following information is for Exercises 20 to 22 : In Example 23.3 , we tested to see whether dieters and exercisers had significantly different average fat loss. We concluded that they did because the difference for the samples under consideration was \(1.8 \mathrm{kg}\), with a standard error of \(0.83 \mathrm{kg}\) and a standardized score of \(2.17 .\) Fat loss was higher for the dieters.

Siegel (1993) reported a study in which she measured the effect of pet ownership on the use of medical care by the elderly. She interviewed 938 elderly adults. One of her results was reported as: "After demographics and health status were controlled for, subjects with pets had fewer total doctor contacts during the one-year period than those without pets (beta \(=-.07, p < .05\) )" (p. 164). a. State the null and alternative hypotheses Siegel was testing. Be careful to distinguish between a population and a sample. b. State the conclusion you would make. Be explicit about the wording.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.