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Parts (a) through (d) below provide additional results for Case Study 21.1 . For each of the parts, compute an approximate \(95 \%\) confidence interval for the difference in mean symptom scores between the placebo and calcium-treated conditions for the symptom listed. In each case, the results given are mean \(\pm\) standard deviation. There were 228 participants in the placebo group and 212 in the calcium-treated group. a. Mood swings: placebo \(=0.70 \pm 0.75 ;\) calcium \(=0.50 \pm 0.58\) b. Crying spells: placebo \(=0.37 \pm 0.57 ;\) calcium \(=0.23 \pm 0.40\) c. Aches and pains: placebo \(=0.49 \pm 0.60 ;\) calcium \(=0.31 \pm 0.49\) d. Craving sweets or salts: placebo \(=0.60 \pm 0.78 ;\) calcium \(=0.43 \pm 0.64\)

Short Answer

Expert verified
The 95% confidence intervals are: (a) Mood swings: (0.061, 0.339) (b) Crying spells: (0.042, 0.238) (c) Aches and pains: (0.075, 0.285) (d) Craving sweets or salts: (0.024, 0.316)

Step by step solution

01

Understand the Confidence Interval Formula

The confidence interval (CI) for the difference between two means is given by the formula: \[ CI = (\bar{x_1} - \bar{x_2}) \pm Z \times \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } \]Where:- \(\bar{x_1}\) and \(\bar{x_2}\) are the sample means.- \(s_1\) and \(s_2\) are the sample standard deviations.- \(n_1\) and \(n_2\) are the sample sizes.- \(Z\) is the Z-value from the standard normal distribution, which is 1.96 for a 95% confidence interval.
02

Calculate the Confidence Interval for Mood Swings

For mood swings, we have:- Placebo mean \(\bar{x_1} = 0.70\), standard deviation \(s_1 = 0.75\), sample size \(n_1 = 228\)- Calcium mean \(\bar{x_2} = 0.50\), standard deviation \(s_2 = 0.58\), sample size \(n_2 = 212\)Calculate the standard error (SE):\[ SE = \sqrt{ \frac{0.75^2}{228} + \frac{0.58^2}{212} } \approx 0.0709 \]The confidence interval is:\[ (0.70 - 0.50) \pm 1.96 \times 0.0709 = 0.20 \pm 0.139 \]\[ CI = (0.061, 0.339) \]
03

Calculate the Confidence Interval for Crying Spells

For crying spells, we have:- Placebo mean \(\bar{x_1} = 0.37\), standard deviation \(s_1 = 0.57\)- Calcium mean \(\bar{x_2} = 0.23\), standard deviation \(s_2 = 0.40\)Calculate the standard error (SE):\[ SE = \sqrt{ \frac{0.57^2}{228} + \frac{0.40^2}{212} } \approx 0.0501 \]The confidence interval is:\[ (0.37 - 0.23) \pm 1.96 \times 0.0501 = 0.14 \pm 0.098 \]\[ CI = (0.042, 0.238) \]
04

Calculate the Confidence Interval for Aches and Pains

For aches and pains, we have:- Placebo mean \(\bar{x_1} = 0.49\), standard deviation \(s_1 = 0.60\)- Calcium mean \(\bar{x_2} = 0.31\), standard deviation \(s_2 = 0.49\)Calculate the standard error (SE):\[ SE = \sqrt{ \frac{0.60^2}{228} + \frac{0.49^2}{212} } \approx 0.0536 \]The confidence interval is:\[ (0.49 - 0.31) \pm 1.96 \times 0.0536 = 0.18 \pm 0.105 \]\[ CI = (0.075, 0.285) \]
05

Calculate the Confidence Interval for Craving Sweets or Salts

For craving sweets or salts, we have:- Placebo mean \(\bar{x_1} = 0.60\), standard deviation \(s_1 = 0.78\)- Calcium mean \(\bar{x_2} = 0.43\), standard deviation \(s_2 = 0.64\)Calculate the standard error (SE):\[ SE = \sqrt{ \frac{0.78^2}{228} + \frac{0.64^2}{212} } \approx 0.0744 \]The confidence interval is:\[ (0.60 - 0.43) \pm 1.96 \times 0.0744 = 0.17 \pm 0.146 \]\[ CI = (0.024, 0.316) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The **Standard Error (SE)** is a measure of the variability or spread of sample means if you were to take multiple samples from the same population. It helps us understand how much uncertainty or noise there is around our sample mean when estimating the population mean. The formula for calculating the standard error of the difference between two means is:
  • SE = \(\sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }\)
Where:
  • \(s_1\) and \(s_2\) are the standard deviations of the two samples.
  • \(n_1\) and \(n_2\) are the sizes of the respective samples.
A smaller standard error indicates that the sample mean is a more accurate reflection of the population mean. When comparing two groups, like the placebo and calcium-treated conditions in this study, the smaller the SE, the more confident we are that our calculated confidence interval is accurate and tight. This makes SE crucial in statistical analysis as it tells us how much we can trust our conclusions based on sample data.
Statistical Analysis
Statistical analysis is the process of collecting, analyzing, and interpreting data to uncover patterns and trends. In this context, it involves using techniques like confidence intervals to understand differences between placebo and treatment groups. **Steps in Statistical Analysis**:
  • Collect data from experiments or observations. In our example, the data comes from symptom scores.
  • Summarize the data using descriptive statistics like means and standard deviations.
  • Apply inferential statistical methods, like calculating confidence intervals, to generalize findings from a sample to a larger population.
Statistical analysis helps researchers determine whether differences in data (like symptom scores) are significant, meaning they are unlikely to be due to random chance. In our case study, confidence intervals are calculated to ascertain how different the placebo and calcium-treated groups are.
Z-value
The **Z-value** is part of the standard normal distribution used in hypothesis testing and confidence interval calculation. It represents the number of standard deviations a data point is from the mean:
  • For a 95% confidence interval, the Z-value is typically 1.96.
Using Z-values helps determine the likelihood that a sample mean accurately reflects the population mean. When calculating a confidence interval for the difference between two means, the Z-value multiplies with the standard error:
  • \(CI = (\bar{x_1} - \bar{x_2}) \pm Z \times SE\)
Where:
  • \(\bar{x_1} - \bar{x_2}\) is the difference between the sample means.
  • \(SE\) is the standard error of the mean difference.
By using the Z-value, we can determine a range where the true difference in means is likely to fall with 95% certainty. The choice of the Z-value is based on the desired level of confidence, and a 95% confidence level is a common standard in many studies. This consideration ensures that the findings are statistically significant and not just happenstance.

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Most popular questions from this chapter

Refer to the following statement: "For example, as you can see from the reported confidence intervals, we can't rule out the possibility that the differences in IQ at 1 and 2 years of age were in the other direction because the interval covers some negative values." The statement refers to a confidence interval given in the previous paragraph, ranging from -3.03 to \(8.20 .\) Write a paragraph explaining how to interpret this confidence interval that would be understood by someone with no training in statistics. Make sure you are clear about the population to which the result applies. The following information is for Exercises 23 to 25 : Refer to Original Source 5 on the companion website, "Distractions in Everyday Driving." Table 14 on page 51 provides \(95 \%\) confidence intervals for the average percent of time drivers in the population would be observed not to have their hands on the wheel during various activities while the vehicle was moving, assuming they were like the drivers in this study. The confidence intervals were computed using a different method than the one presented in this book because of the type of data available, but the interpretation is the same. (See Appendix D of the report if you are interested in the details.)

Refer to Exercises 18 and \(19 .\) The 200 men in the sample had a mean height of 68.2 inches, with a standard deviation of 2.7 inches. The 200 women had a mean height of 63.1 inches, with a standard deviation of 2.5 inches. Assuming these were independent samples, compute an approximate \(95 \%\) confidence interval for the mean difference in heights between British males and females. Interpret the resulting interval in words that a statistically naive reader would understand.

Using the data presented by Hand and colleagues (1994) and discussed in previous chapters, we would like to estimate the average age difference between husbands and wives in Britain. Recall that the data consisted of a random sample of 200 couples. Following are two methods that were used to construct a confidence interval for the difference in ages. Your job is to figure out which method is correct: Method 1: Take the difference between the husband's age and the wife's age for each couple, and use the differences to construct an approximate \(95 \%\) confidence interval for a single mean. The result was an interval from 1.6 to 2.9 years. Method 2: Use the method presented in this chapter for constructing an approximate confidence interval for the difference in two means for two independent samples. The result was an interval from -0.4 to 4.3 years. Explain which method is correct, and why. Then interpret the confidence interval that resulted from the correct method.

In Chapter 20, we saw that to construct a confidence interval for a population proportion it was enough to know the sample proportion and the sample size. Is the same true for constructing a confidence interval for a population mean? That is, is it enough to know the sample mean and sample size? Explain.

Suppose a university wants to know the average income of its students who work, and all students supply that information when they register. Would the university need to use the methods in this chapter to compute a confidence interval for the population mean income? Explain. (Hint: What is the sample mean and what is the population mean?)

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