Chapter 3: Problem 30
Let \(a, b>1\), and let \(f\) be a bounded function on \([0,1]\) such that $$ f(a x)=b f(x) \quad(0 \leq x \leq 1 / a) $$ Show that \(f\) is continuous at 0 .
Short Answer
Expert verified
Function \( f \) is continuous at 0 because the limit of \( f(x) \) as \( x \) approaches 0 is equal to \( f(0) \).
Step by step solution
01
Analyze the given function equation
We are given that the function satisfies the equation \( f(ax) = b f(x) \) for \( 0 \leq x \leq 1/a \). This implies a recursive relationship where the function at scaled inputs \( ax \) and outputs \( b \) forms a consistent pattern over small intervals.
02
Consider the behavior of function near 0
We need to show that \( \lim_{x \to 0} f(x) = f(0) \). Start by considering a sequence \( x_n = \frac{1}{a^n} \) that tends to 0 as \( n \to \infty \). For these \( x_n \), \( a(x_n) = \frac{1}{a^{n-1}} \). By applying the functional equation, we have \( f\left(\frac{1}{a^{n-1}}\right) = b^n f\left(\frac{1}{a^n}\right) \).
03
Investigate boundedness using function equation
Given that \( f \) is bounded, there exists some \( M > 0 \) such that \( |f(x)| \leq M \) for all \( x \in [0, 1] \). Thus, \( |f(x_n)| \leq M \) for each \( x_n = \frac{1}{a^n} \). Over multiple iterations using the functional equation, \( b^n |f(x_n)| = |f(1)| \), showing that \( |f(x_n)| \) decreases as \( n \) increases since \( b > 1 \).
04
Show limit of function equals function value at 0
Since \( |f(x_n)| = |f(1)| / b^n \) and \( b > 1 \), it follows that \( b^n \to \infty \) making \(|f(x_n)| \to 0 \) as \( n \to \infty \). Hence, \( \lim_{x \to 0} f(x) = 0 \). Checking continuity at \( x=0 \), since \( f(0) = 0 \) and the limit equals the function value, \( f \) is continuous at 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity
Continuity is a fundamental concept in calculus. It concerns the behavior of a function at a particular point and in its neighborhood. A function is considered continuous at a point if the limit of the function's value as it approaches the point is equal to the function's value at that point. In simpler terms, a function doesn't "jump" or have "holes" at that point.
For a function to be continuous at 0, we need the limit as it approaches 0 from both directions to be equal to its value at 0. Mathematically, this means:
For a function to be continuous at 0, we need the limit as it approaches 0 from both directions to be equal to its value at 0. Mathematically, this means:
- \[ \lim_{x \to 0} f(x) = f(0) \].
Functional Equations
A functional equation is an equation in which the variables are functions rather than simple numbers. Solving these equations typically involves finding a function that satisfies the given equality for all inputs. Complex problems often arise from analyzing relationships and constraints between these functions.
In our exercise, the given functional equation is:
In our exercise, the given functional equation is:
- \[ f(ax) = b f(x) \] for \( 0 \leq x \leq \frac{1}{a} \).
Limits
Limits are a foundational concept in calculus, used to find the behavior of a function as the input approaches a particular value. They are instrumental in defining both the derivative and integral of a function, as well as in discussing continuity.
In context of this exercise, limits were used to show:
In context of this exercise, limits were used to show:
- \[ \lim_{x \to 0} f(x) = f(0) = 0 \].