Chapter 1: Problem 10
Given a measure space \((X, \mathcal{M}, \mu)\) and \(E \in \mathcal{M}\), define \(\mu_{E}(\mathcal{A})=\mu(A \cap E)\) for \(A \in \mathcal{M}\). Then \(\mu_{E}\) is a measure.
Short Answer
Expert verified
\(\mu_E\) is a measure since it satisfies all measure properties.
Step by step solution
01
Understand the Measure Definition
A measure is a function \( \mu : \mathcal{M} \to [0, \infty] \) that satisfies three properties: non-negativity, null empty set, and \(\sigma\)-additivity.
02
Check Non-Negativity
For any \( A \in \mathcal{M} \), \( \mu_E(A) = \mu(A \cap E) \geq 0 \) since \( \mu \) is non-negative and measures intersections as subsets of measurable sets.
03
Verify the Null Empty Set Property
Consider \( A = \emptyset \). Then \( A \cap E = \emptyset \), and thus \( \mu_E(\emptyset) = \mu(\emptyset \cap E) = \mu(\emptyset) = 0 \). This satisfies the property for measures.
04
Establish \(\sigma\)-additivity
Take a countable collection \( \{A_i\}_{i=1}^{\infty} \subseteq \mathcal{M} \). We have \( \mu_E\left(\bigcup_{i=1}^{\infty} A_i\right) = \mu\left(\bigcup_{i=1}^{\infty} (A_i \cap E)\right) \). Since \(\mu\) is \(\sigma\)-additive, \( \mu\left(\bigcup_{i=1}^{\infty} (A_i \cap E)\right) = \sum_{i=1}^{\infty} \mu(A_i \cap E) \), hence \( \mu_E\left(\bigcup_{i=1}^{\infty} A_i\right) = \sum_{i=1}^{\infty} \mu_E(A_i) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Non-Negativity
In measure theory, one of the foundational properties of a measure is non-negativity. This means that for any measurable set \( A \), the measure \( \mu(A) \) must be greater than or equal to zero. This makes sense because a measure can be thought of as assigning a size or volume to sets, and it's logical that size can't be negative.
When checking non-negativity for our specific measure \( \mu_E \), defined as \( \mu_E(A) = \mu(A \cap E) \), we need to consider the intersection \( A \cap E \).
Since \( \mu \) is already a non-negative measure, the intersection \( A \cap E \) as a subset is also measured in a non-negative way:
Understanding this is crucial because it ensures all measurements are logically consistent; you cannot have a negative size in a system measuring size or probability.
When checking non-negativity for our specific measure \( \mu_E \), defined as \( \mu_E(A) = \mu(A \cap E) \), we need to consider the intersection \( A \cap E \).
Since \( \mu \) is already a non-negative measure, the intersection \( A \cap E \) as a subset is also measured in a non-negative way:
- For any \( A \in \mathcal{M} \), \( \mu_E(A) = \mu(A \cap E) \geq 0 \).
Understanding this is crucial because it ensures all measurements are logically consistent; you cannot have a negative size in a system measuring size or probability.
Null Empty Set
The null empty set property is another important attribute of a measure. This property essentially states that the measure of an empty set is always zero.
\(\mu(\emptyset) = 0 \) signifies that there's nothing to measure, hence it cannot possess any volume or size.
When we look at \( \mu_E \), the measure is slightly adapted but retains this fundamental property.
Consider:
Grasping this concept helps underline that non-existent elements in a set don't mistakenly contribute to the total measure, maintaining both theoretical and practical precision.
\(\mu(\emptyset) = 0 \) signifies that there's nothing to measure, hence it cannot possess any volume or size.
When we look at \( \mu_E \), the measure is slightly adapted but retains this fundamental property.
Consider:
- The measure \( \mu_E(\emptyset) = \mu(\emptyset \cap E) \).
- Since \( \emptyset \cap E = \emptyset \), then \( \mu_E(\emptyset) = \mu(\emptyset) = 0 \).
Grasping this concept helps underline that non-existent elements in a set don't mistakenly contribute to the total measure, maintaining both theoretical and practical precision.
Sigma-additivity
Sigma-additivity (or \( \sigma \)-additivity) is the property that ensures the measure can handle countable unions of sets in a consistent manner.
This is an essential trait as it ensures that a measure can combine over an infinite count of sets while retaining reliability and accuracy.
To verify \( \sigma \)-additivity for \( \mu_E \), consider a countable collection of sets \( \{A_i\}_{i=1}^{\infty} \):
By doing so, we ensure our measure remains reliable whether dealing with simple or complex and infinite set arrangements.
This is an essential trait as it ensures that a measure can combine over an infinite count of sets while retaining reliability and accuracy.
To verify \( \sigma \)-additivity for \( \mu_E \), consider a countable collection of sets \( \{A_i\}_{i=1}^{\infty} \):
- With \( \mu_E \), we define: \( \mu_E\left(\bigcup_{i=1}^{\infty} A_i\right) = \mu\left(\bigcup_{i=1}^{\infty} (A_i \cap E)\right) \).
- Because the original measure \( \mu \) is \( \sigma \)-additive, it applies: \( \mu\left(\bigcup_{i=1}^{\infty} (A_i \cap E)\right) = \sum_{i=1}^{\infty} \mu(A_i \cap E) \).
- Thus, \( \mu_E \) follows that \( \mu_E\left(\bigcup_{i=1}^{\infty} A_i\right) = \sum_{i=1}^{\infty} \mu_E(A_i) \).
By doing so, we ensure our measure remains reliable whether dealing with simple or complex and infinite set arrangements.