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Find the value of \(\frac{p^{2}+q^{2}}{r^{2}+s^{2}}\), if \(p: q:: r: s\). (a) \(\frac{1}{4}\) (b) \(\frac{p q}{r s}\) (c) \(\left(\frac{p+q}{r+s}\right)^{2}\) (d) both (b) and (c)

Short Answer

Expert verified
Answer: (c) \(\left(\frac{p+q}{r+s}\right)^{2}\)

Step by step solution

01

Note the proportion

We are given that \(p: q:: r: s\), meaning that \(p/q = r/s\).
02

Represent the proportion as an equation

The given proportion can be represented as a single equation: \(\frac{p}{q} = \frac{r}{s}\)
03

Use the equation in our target expression and simplify

Our target expression is \(\frac{p^{2}+q^{2}}{r^{2}+s^{2}}\). We can rewrite this using the equation we found in Step 2: \(\frac{p^{2}+q^{2}}{r^{2}+s^{2}} = \frac{p^{2} + q^{2}}{\left(\frac{p^2}{q^2}s^2 + s^2\right)}\) Now, we can express the denominator with a common denominator to simplify further: \(\frac{p^{2}+q^{2}}{\frac{p^2s^2 + q^2s^2}{q^2}} = \frac{(p^{2}+q^{2})q^2}{p^2s^2 + q^2s^2} = \frac{q^2(p^2 + q^2)}{s^2(p^2 + q^2)}\) Since the numerators are equal, we can cancel them, resulting in: \(\frac{q^2}{s^2}\) However, recall from Step 2 that \(\frac{p}{q} = \frac{r}{s}\), which means that \(q^2 = \frac{p^2s^2}{r^2}\). So, our expression can be rewritten as: \(\frac{\frac{p^2s^2}{r^2}}{s^2} = \frac{p^2}{r^2}\) Finally, we can rewrite this expression using the proportion from Step 2: \(\frac{p^2}{r^2} = \left(\frac{p}{r}\right)^2 = \left(\frac{q}{s}\right)^2\) Now, our expression becomes: \(\left(\frac{p}{r}\right)^2 = \left(\frac{p+q}{r+s}\right)^2\)
04

Identify the correct answer among the given choices

Based on our simplification, the correct answer is: (c) \(\left(\frac{p+q}{r+s}\right)^{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Simplification
Algebraic simplification involves breaking down complex mathematical expressions into simpler forms that are easier to work with. This usually makes calculations easier and results more understandable.
When simplifying the expression \(\frac{p^{2}+q^{2}}{r^{2}+s^{2}}\) given \(p: q:: r: s\), we start by translating proportions into equations. In our exercise, that meant expressing \( \frac{p}{q} = \frac{r}{s} \).
Such equations let us rewrite parts of the expression to match forms that cancel out unnecessary terms. This step decreases complexity and often reveals the structure or patterns in the expression. Such a revelation allows us to see that both expressions in the numerator and denominator share factors, which we further translate by substituting equivalent terms.
Ultimately, following simplification, we see patterns reemerge leading to meaningful conclusions like our solution, \(\left(\frac{p+q}{r+s}\right)^{2}\). Understanding how and when to simplify expressions is a foundational algebra skill that benefits solving various mathematical problems.
Proportion Equation
A proportion equation is simply a mathematical equation that states two ratios are equal. In our exercise, we had the proportion that \(p: q:: r: s\). This can also be written as the equation \(\frac{p}{q} = \frac{r}{s}\).
Proportions are useful in algebra, particularly when you need to express relationships between variables or when scaling numbers. Recognizing proportions allows equations to be rearranged or transformed for simpler manipulation and resolution.
The idea is to maintain the balance of the equation while expressing one ratio in terms of another. This often involves cross-multiplication—a process where you multiply across the equals sign to eliminate fractions. This also implies replacement of parts of the original equation with corresponding terms from the proportion, simplifying calculations as we saw in our exercise.
Due to the equivalency maintained by a proportion equation, substitutions align with the unknowns making solving them more straightforward and leading to concise solutions.
Expression Evaluation
Evaluating an expression involves calculating the numerical value of the expression when values for the variables are known, or in some cases, simplifying the expression like in our exercise.
For the given expression, \(\frac{p^{2}+q^{2}}{r^{2}+s^{2}}\), understanding the substitution based on the known proportion \(\frac{p}{q} = \frac{r}{s}\), allows us to transform variables effectively.
The expression's evaluation in this scenario depends on viewing the entire structure through our known ratio, allowing substitutions that simplify the expression to a term like \(\left(\frac{p+q}{r+s}\right)^{2}\).
The process highlights how expression evaluation often extends beyond pure computation to include recognizing relationships and dependencies captured in algebraic forms, thus directing us towards constructing the simplest version of that expression. This helps all students comprehend and efficiently solve problems tied to similar algebraic expressions and their evaluations.

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Most popular questions from this chapter

The ratio of prices of Cello and Rotomac pens in 2000 were in the ratio of \(3: 5\) In 2005 the price of Cello pen trebles itself and the price of Rotomac pen is increased by Rs. 100 , then the new ratio of prices of the same pens becomes \(4: 5\). What was the original price of the Rotomac pen in \(2000 ?\) (a) Rs. 60 (b) Rs. 80 (c) Rs. 100 (d) Rs. 120

Equal quantities of three mixtures of milk and water are mixed in the ratio of \(1: 2,2: 3\) and \(3: 4\). The ratio of water and milk in the mixture is : (a) \(193: 122\) (b) \(122: 193\) (c) \(61: 97\) (d) \(137: 178\)

A milk man has a mixture of milk in which ratio of milk and water is \(5: 3\) He sells 40 litres of milk \(i . e\), mixture then he adds up 15 litres of pure water. Now the ratio of milk and water is \(5: 4\). What is the new quantity of mixture? (a) 72 litres (b) 270 litres (c) 135 litres (d) data insufficient

The concentration of petrol in three different mixtures (petrol and kerosene) is \(\frac{1}{2}, \frac{3}{5}\) and \(\frac{4}{5}\) respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of petrol and Kerosene in the new mixture? (a) \(4: 5\) (b) \(3: 2\) (c) \(3: 5\) (d) \(2: 3\)

The value of a diamond is directly proportional to the square of its weight. A diamond unfortunately breaks into three pieces with weights in the ratio of \(3: 4\) : 5 thus a loss of Rs. \(9.4\) lakh is incurred. What is the actual value of diamond : (a) \(28.8\) lakh (b) \(13.5\) lakh (c) \(14.4 \mathrm{lakh}\) (d) \(18.8\) lakh

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