Chapter 1: Problem 10
How many numbers are there from 100 to 200 ? (a) 100 (b) 101 (c) 99 (d) none of these
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 1: Problem 10
How many numbers are there from 100 to 200 ? (a) 100 (b) 101 (c) 99 (d) none of these
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
When a natural number divided by a certain divisor, we get 15 as a remainder. But when the 10 times of the same number is divided by the same divisor we get 6 as a remainder. The maximum possible number of such divisors is : (a) 6 (b) 7 (c) 15 (d) can't be determined
A number of the form \(10^{n}-1\) is always a 0y every \(n\) is a natural number, when : (a) \(n\) is odd (b) \(n\) is prime (c) \(n\) is even (d) can't say
The maximum possible difference between the 4 digit numbers formed by using the 4 different digits \(1,2,3,5\) is : (a) 4086 (b) 5076 (c) 4386 (d) 3242
The value of \(k\) if \(k 35624\) is divisible by 11 : (a) 2 (b) 5 (c) 7 (d) 6
At least which number must be subtracted from 9999999 so that it will become the multiple of \(125 ?\) (a) 124 (b) 4 (c) 24 (d) none of these
What do you think about this solution?
We value your feedback to improve our textbook solutions.