Chapter 10: Problem 6
Let \(X, Y\) be independent random variables taking values in \(\mathbf{N}\) with $$ P(X=i)=P(Y=i)=\frac{1}{2^{i}} \quad(i=1,2, \ldots) $$ Find the following probabilities: a) \(P(\min (X, Y) \leq i) \quad\left[\right.\) Ans.: \(\left.1-\frac{1}{4^{4}}\right]\) b) \(P(X=Y)\) [Ans.: \(\frac{1}{3}\) ] c) \(P(Y>X) \quad\left[\right.\) Ans.: \(\left.\sum_{i \geq 0}^{3} \frac{1}{2^{2}\left(2^{i}-1\right)}\right]\) d) \(P(X\) divides \(Y)\) [Ans,: \(\frac{1}{3}\) ] e) \(P(X \geq k Y)\) for a given positive integer \(k\) [Ans,: \(\frac{1}{2^{1+k}-1}\) ]
Short Answer
Step by step solution
Calculate P(min(X, Y) ≤ i)
Determine P(X = Y)
Compute P(Y > X)
Find P(X divides Y)
Establish P(X ≥ kY)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Random Variables
The probabilities associated with these values are described by a probability distribution, which, in this case, specifies that the probabilities decrease geometrically as the values increase. Understanding how random variables behave and interact is essential for solving complex probability problems.
- Discrete Random Variable: Only takes distinct, separate values.
- Continuous Random Variable: Can take any numerical value within a range.
Independent Events
This independence justifies multiplying their probabilities when considering their joint behavior. For example, in calculating \(P(X > i, Y > i)\), because selecting a specific value for \(X\) does not alter the likelihood of \(Y\) being greater than \(i\), their probabilities are multiplied together. This independence can greatly simplify calculations in probability theory.
- Joint Probability of Independent Events: \(P(A \cap B) = P(A) \times P(B)\)
- Independent vs. Dependent: In independent events, the outcome of one does not influence the other's probability.
Geometric Series
For example, to find \(P(X = Y)\), a series is formed by the probability products \(\left(\frac{1}{2^i}\right)^2\) summed over all positive integers \(i\). This forms a geometric series with a common ratio of \(\frac{1}{4}\). The sum can be calculated using the formula for an infinite geometric series:
\[ \text{Sum} = \frac{a}{1-r} \]
where \(a\) is the first term of the series and \(r\) is the common ratio.
- Geometric Series Formula: \(S_n = a \frac{1-r^n}{1-r}\), for finite, or \(\frac{a}{1-r}\) for infinite \(|r|<1\).
- Application: Used in calculating probabilities of repeating scenarios or series in probability theory.
Probability Distributions
In this exercise, \(P(X=i) = \frac{1}{2^i}\) represents the distribution of \(X\) (and similarly \(Y\)). This shows a decreasing geometric distribution where each subsequent value is half as likely as the previous. The specific shape of this distribution affects how likely various events will be.
- Discrete Probability Distribution: Probabilities are assigned to specific standalone values.
- Continuous Probability Distribution: Probabilities are described over a range of values, such as in normal distributions.