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The article "Statistical Evidence of Discrimination" \((J\). Amer. Stat. Assoc., 1982: 773-783) discusses the court case Swain v. Alabama (1965), in which it was alleged that there was discrimination against blacks in grand jury selection. Census data suggested that \(25 \%\) of those eligible for grand jury service were black, yet a random sample of 1050 called to appear for possible duty yielded only 177 blacks. Using a level \(.01\) test, does this data argue strongly for a conclusion of discrimination?

Short Answer

Expert verified
Yes, the data strongly suggests discrimination.

Step by step solution

01

Define Hypotheses

Start by defining the null and alternative hypotheses. The null hypothesis \( H_0 \) states that the proportion of black individuals eligible for grand jury service is \( 0.25 \), as claimed. The alternative hypothesis \( H_a \) states that the proportion is less than \( 0.25 \). Mathematically, \( H_0: p = 0.25 \) and \( H_a: p < 0.25 \).
02

Determine the Sample Proportion

Calculate the sample proportion of black individuals in the sample. There are 177 black people out of 1050 sampled. The sample proportion \( \hat{p} \) is given by \( \hat{p} = \frac{177}{1050} \approx 0.1686 \).
03

Calculate the Test Statistic

Use the formula for the test statistic for a proportion. The formula is \( z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \), where \( p_0 = 0.25 \) and \( n = 1050 \). Compute \( z = \frac{0.1686 - 0.25}{\sqrt{\frac{0.25(0.75)}{1050}}} \approx -5.98 \).
04

Determine the Critical Value and Compare

For a one-tailed test at \( \alpha = 0.01 \), find the critical value from the standard normal distribution. The critical value \( z_{\alpha} \) for \( \alpha = 0.01 \) is approximately \( -2.33 \). Compare the test statistic \( z = -5.98 \) to the critical value \( -2.33 \).
05

Decision on Null Hypothesis

Since the test statistic \( z = -5.98 \) is less than the critical value \( -2.33 \), we reject the null hypothesis \( H_0 \).
06

Conclusion

The data provides strong evidence at the \( 0.01 \) significance level to conclude that there is discrimination against blacks in the grand jury selection.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis is the foundation of hypothesis testing. It represents the default or original assumption we aim to test against. In this context, the null hypothesis, denoted as \( H_0 \), claims that there is no discrimination against black individuals in grand jury selection.
Mathematically, it assumes the proportion of eligible black individuals is \( 0.25 \). This means that, according to the null hypothesis, 25% of those eligible for jury duty should be black, as predicted by census data. The null hypothesis acts as a baseline for testing whether the observed data deviates significantly from this assumption.
Rejecting the null hypothesis implies evidence contrary to this established belief. It suggests that the actual proportion might be significantly lower than 0.25 due to factors like discrimination.
Alternative Hypothesis
The alternative hypothesis, represented as \( H_a \), offers a contrasting perspective to the null hypothesis. It proposes what we suspect might be true: that there is indeed discrimination, leading to a lower proportion of black individuals in grand jury selection compared to the stated 0.25.
In this exercise, \( H_a \) is mathematically defined as \( p < 0.25 \). This indicates our suspicion that the actual proportion is less than 25%.
If the alternative hypothesis is supported by the data, it suggests that the observed sample proportion of 0.1686 could be due to genuine discrimination rather than random variability. Thus, the alternative hypothesis directs the aim of the test to identify evidence of an effect contrary to the assumed norm in the null hypothesis.
Critical Value
The critical value is a threshold we use to decide whether to reject the null hypothesis. In hypothesis testing, it demarcates the boundary of the null hypothesis's rejection region within the chosen significance level, \( \alpha \).
For this scenario, with a significance level of 0.01, we employ a one-tailed test because we suspect the proportion is specifically lower than 0.25. This gives us a critical value of approximately \(-2.33\) from the standard normal distribution.
By comparing the test statistic to the critical value, we determine if our data falls within the range of unlikely outcomes under \( H_0 \). If the test statistic is lower than this critical value, it indicates that the result is significant enough to reject \( H_0 \). The critical value is essential as it helps us to make an informed decision about the validity of the null hypothesis.
Test Statistic
The test statistic is a calculation that helps us quantify the difference between the observed data and what is expected if the null hypothesis were true. In this case, we're using a z-test for proportions, ascertaining how many standard deviations the observed sample proportion \( \hat{p} = 0.1686 \) is away from the expected proportion \( p_0 = 0.25 \).
Employing the formula \( z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \), where \( n = 1050 \), we calculate a test statistic of approximately \(-5.98\).
This negative value signifies that the sample proportion is significantly lower than the expected proportion. Given it exceeds the critical value \(-2.33\), it further reinforces that the data strongly contradicts \( H_0 \), supporting the presence of an effect, potentially indicating discrimination within the context of jury selection.

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Most popular questions from this chapter

For a fixed alternative value \(\mu^{\prime}\), show that \(\beta\left(\mu^{\prime}\right) \rightarrow 0\) as \(n \rightarrow \infty\) for either a one-tailed or a two-tailed \(z\) test in the case of a normal population distribution with known \(\sigma\).

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Let the test statistic \(Z\) have a standard normal distribution when \(H_{0}\) is true. Give the significance level for each of the following situations: a. \(H_{\mathrm{a}}: \mu>\mu_{0}\), rejection region \(z \geq 1.88\) b. \(H_{\mathrm{a}}: \mu<\mu_{0}\), rejection region \(z \leq-2.75\) c. \(H_{\mathrm{a}}: \mu \neq \mu_{0}\), rejection region \(z \geq 2.88\) or \(z \leq-2.88\)

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