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It is known that roughly \(2 / 3\) of all human beings have a dominant right foot or eye. Is there also right-sided dominance in kissing behavior? The article "Human Behavior: Adult Persistence of Head-Turning Asymmetry" (Nature, 2003: 771) reported that in a random sample of 124 kissing couples, both people in 80 of the couples tended to lean more to the right than to the left. a. If \(2 / 3\) of all kissing couples exhibit this right-leaning behavior, what is the probability that the number in a sample of 124 who do so differs from the expected value by at least as much as what was actually observed? b. Does the result of the experiment suggest that the \(2 / 3\) figure is implausible for kissing behavior? State and test the appropriate hypotheses.

Short Answer

Expert verified
The 2/3 figure is plausible; we fail to reject the null hypothesis.

Step by step solution

01

Define the Hypotheses

Firstly, we define the null hypothesis \(H_0\) and alternative hypothesis \(H_a\). \(H_0: p = 2/3\) (the proportion of right-leaning couples is \(2/3\)). \(H_a: p eq 2/3\) (the proportion deviates from \(2/3\)).
02

Identify the Distribution

We view the problem in terms of a binomial distribution where \(n = 124\) and \(p = 2/3\). We will use a normal approximation due to the large sample size, with mean \(\mu = np\) and variance \(\sigma^2 = np(1-p)\).
03

Calculate the Parameters

Compute the mean \(\mu\) and standard deviation \(\sigma\) of the distribution: \(\mu = 124 \times \frac{2}{3} = 82.67\) and \(\sigma = \sqrt{124 \times \frac{2}{3} \times \frac{1}{3}} \approx 4.675\).
04

Use Normal Approximation

Use the normal distribution to approximate the probability of observing exactly 80 couples leaning right. Calculate the z-score: \(z = \frac{80 - 82.67}{4.675} \approx -0.571\).
05

Calculate the Probability

Find the probability that the number of right-leaning couples differs from \(\mu = 82.67\) by as much or more than what was observed using two-tailed test: \(P(Z \leq -0.571) + P(Z \geq 0.571)\). From the standard normal table, \(P(Z \leq -0.571) = 0.2835\). Double this for the two-tailed test (due to symmetry), giving a total probability of \(2 \times 0.2835 \approx 0.567\).
06

Conclusion on Hypotheses

Since the probability \(0.567\) is much greater than typical significance levels (like \(0.05\) or \(0.01\)), we do not reject the null hypothesis. The experiment does not provide evidence that the proportion deviates from \(2/3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The concept of binomial distribution is central to understanding hypothesis testing in this context. A binomial distribution describes the probability of having a fixed number of successful outcomes in a series of independent trials, each with the same probability of success. In this exercise, each kissing couple is a trial, and leaning right is considered a success with two potential outcomes: right or not right leaning.

- Number of trials (=124, as there are 124 couples in the sample.
- Probability of success (=\( \frac{2}{3} \), meaning each couple is expected to lean right with a probability of two-thirds.

The goal is to evaluate how many couples lean to the right in this given sample and whether this aligns with = 2/3. Understanding this likelihood involves examining both the binomial distribution and its normal approximation.
Normal Approximation
When dealing with a large number of trials, such as the 124 couples in our sample, it becomes cumbersome to calculate probabilities directly from the binomial distribution. Here, normal approximation comes to our rescue by simplifying the process.

For a binomial distribution with a large sample size, the distribution can be approximated as a normal distribution. This approximation is valid under the condition that both np and n(1-p) are greater than 5, which holds in our case. The benefits are:
  • Simplifying calculations by using a continuous normal distribution.
  • Facilitating the calculation of probabilities with z-scores.
The mean (= 82.67$ as calculated, represents the expected number of right-leaning couples, and the standard deviation (=\(4.675\)). With these, we translate the observation into a z-score to determine probability.
Statistical Significance
Statistical significance is about determining whether our observed data is meaningful compared to what we expect under a null hypothesis. In this scenario, we hypothesized that is 2/3. We wanted to assess the likelihood that our observed right-leaning couples number, 80, was unusual if 82.67 couples were expected to lean right.

Through our hypothesis test:
  • This calculation yielded the probability of the sample statistic deviating from the mean as observed under the normal approximation.
  • The calculated z-score of -0.571 allows us to find the p-value, which indicates the extremeness of the observed result.
A p-value much greater than typical significance levels (0.05 or 0.01) means we wouldn't conclude that the proportion deviates from 2/3 in terms of right-leaning behavior.
Right-Sided Dominance
Right-sided dominance refers to the tendency of individuals to exhibit a preference for using the right side of their bodies, whether it be the hand, foot, eye, or even which way they lean when engaging in actions, like kissing. Exploring whether this dominance transfers to actions like kissing was the crux of the study.

In this situation:
  • The hypothesis tested whether the percentage of couples leaning right while kissing aligns with the general right-side preference (2/3).
  • The outcome indicated no statistically significant deviation from the hypothesis, suggesting that kissing too might reflect right-sided preference proportionally.
Therefore, although the study did not find statistical evidence to suggest deviation from the right-sided preference figure, it laid important groundwork for understanding behavioral dominance in different contexts.

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Most popular questions from this chapter

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