/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 A health-food store stocks two d... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A health-food store stocks two different brands of a certain type of grain. Let \(X=\) the amount (Ib) of brand A on hand and \(Y=\) the amount of brand B on hand. Suppose the joint pdf of \(X\) and \(Y\) is $$ f(x, y)=\left\\{\begin{array}{cl} k x y & x \geq 0, y \geq 0,20 \leq x+y \leq 30 \\ 0 & \text { otherwise } \end{array}\right. $$ a. Draw the region of positive density and determine the value of \(k .\) b. Are \(X\) and \(Y\) independent? Answer by first deriving the marginal pdf of each variable. c. Compute \(P(X+Y \leq 25)\). d. What is the expected total amount of this grain on hand? e. Compute \(\operatorname{Cov}(X, Y)\) and \(\operatorname{Corr}(X, Y)\). f. What is the variance of the total amount of grain on hand?

Short Answer

Expert verified
a. The value of \(k\) ensures the pdf integrates to 1. X and Y are not independent. c. Integrate the pdf over the defined region. d. Use linearity of expectation for total grain. e. Calculate covariance and correlation using integration and marginal distributions. f. Use the formula involving variances and covariance.

Step by step solution

01

Define the Region of Positive Density

The region of positive density is defined by the constraints \(x \geq 0\), \(y \geq 0\), and \(20 \leq x+y \leq 30\). This forms a region in the first quadrant of the xy-plane bounded by the lines \(x + y = 20\) and \(x + y = 30\).
02

Determine the Value of k

The joint pdf \(f(x, y)\) must integrate to 1 over the region of positive density. We set up the integral:\[\int_{x=0}^{30} \int_{y=20-x}^{30-x} kxy \, dy \, dx = 1.\] Evaluating this integral will give us the value of \(k\). Calculate the inner integral with respect to \(y\), followed by the outer integral with respect to \(x\).
03

Check Independence of X and Y

To check for independence, we need the marginal pdfs. Compute \(f_X(x) = \int_{20-x}^{30-x} kxy \, dy\) and \(f_Y(y) = \int_{20-y}^{30-y} kxy \, dx\). If \(f(x, y) = f_X(x)f_Y(y)\) for all \(x, y\), then \(X\) and \(Y\) are independent.
04

Compute P(X+Y ≤ 25)

To find \(P(X+Y \leq 25)\), integrate the joint pdf over the region where \(20 \leq x+y \leq 25\). This is given by\[P(X + Y \leq 25) = \int_{x=0}^{25} \int_{y=20-x}^{25-x} kxy \, dy \, dx.\] Evaluate the integral to find the probability.
05

Expected Total Amount of Grain

Compute the expected value \(E(X+Y)\). By the linearity of expectation, \(E(X+Y) = E(X) + E(Y)\). Calculate \(E(X)\) and \(E(Y)\) using their marginal distributions.
06

Compute Cov(X, Y)

The covariance \(\operatorname{Cov}(X, Y)\) is given by \(E(XY) - E(X)E(Y)\). Calculate \(E(XY)\) by integrating \((xy \cdot f(x, y))\) over the defined region of positive density.
07

Compute Corr(X, Y)

The correlation \(\operatorname{Corr}(X, Y)\) is defined as \(\operatorname{Cov}(X, Y) / \sqrt{\operatorname{Var}(X) \cdot \operatorname{Var}(Y)}\). Use the results from previous steps to compute \(\operatorname{Var}(X)\) and \(\operatorname{Var}(Y)\) and then find the correlation.
08

Variance of Total Amount of Grain

The variance \(\operatorname{Var}(X+Y)\) can be computed using \(\operatorname{Var}(X+Y) = \operatorname{Var}(X) + \operatorname{Var}(Y) + 2\operatorname{Cov}(X, Y)\). Substitute the known values to get the result.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Marginal Distribution
In the world of joint probability density functions, understanding marginal distributions is crucial. Marginal distribution allows us to focus on each variable individually, even when they're part of a joint distribution. For two variables, like in our exercise with amounts of grain stocks for brands A and B, the marginal probability density function (pdf) of each variable helps us understand the behavior of one variable without considering the other.

To derive the marginal distribution for a variable, say for brand A (\(X\)), you integrate out the other variable (\(Y\)) from the joint pdf. This looks like:
  • For \(X\): \(f_X(x) = \int f(x,y) \, dy\)
  • For \(Y\): \(f_Y(y) = \int f(x,y) \, dx\)

By finding these marginal distributions, you can understand the probability properties and behavior of each brand's grain stock separately, even if they affect each other in the joint setting.
Independence of Random Variables
Random variables are independent if the occurrence or behavior of one does not affect the other. In the context of our grain stocks, independence means that the stock level of brand A wouldn't influence brand B, and vice versa. This idea is essential, as it can greatly simplify calculations and understanding.

To check if variables are independent through their distributions, you compare the joint distribution with the product of the marginals. If for all values,\(f(x, y) = f_X(x) f_Y(y)\), then \(X\) and \(Y\) are truly independent.

However, if this condition isn't met, then the two brands influence each other in some way. Thus, independence gives insight into the relationship between two or more random variables.

Fancy words aside, knowing if two variables are independent helps in simplifying predictions and understanding of the system as they'd then evolve separately.
Expected Value
The expected value of a random variable is like a weighted average, summarizing its possible values into a single meaningful number. It's a crucial concept, especially in statistics and probability, providing a sense of the central tendency.

For two random variables, like our brands of grain, the expected value helps in predicting how much grain is typically on hand. To find the expected value (\(E(X)\)) of a variable, use the formula:
  • \(E(X) = \int x \, f_X(x) \, dx\)
  • Likewise, \(E(Y) = \int y \, f_Y(y) \, dy\)

Adding these results from both \(E(X)\) and \(E(Y)\) gives the expected total grain amount on hand. Expected value is foundational in many calculations, making it a key component in understanding random variables' behavior.
Covariance and Correlation
Covariance and correlation are two powerful mathematical tools that help measure the relationship between two random variables.

Covariance tells you how two variables change together. A positive covariance indicates that as one variable increases, the other tends to increase as well. Conversely, a negative covariance implies an inverse relationship. It is calculated as:
  • \(\operatorname{Cov}(X, Y) = E(XY) - E(X)E(Y)\)

Though useful, covariance's units can be hard to interpret. This is where correlation steps in. Correlation standardizes covariance, providing a dimensionless value between -1 and 1. This makes it easier to understand the strength of the relationship between variables:
  • A correlation of 1 or -1 signifies perfect linear relationship.
  • 0 indicates no linear relationship.

  • The correlation is computed as:\(\operatorname{Corr}(X, Y) = \frac{\operatorname{Cov}(X, Y)}{\sqrt{\operatorname{Var}(X) \cdot \operatorname{Var}(Y)}}\).

    Understanding both allows you to see not just if the amounts of grain from brand A and B influence each other, but how strong and in what way their relationship is.

    One App. One Place for Learning.

    All the tools & learning materials you need for study success - in one app.

    Get started for free

    Most popular questions from this chapter

    Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of \(1.2\). a. If the distribution is normal, what is the probability that the sample mean hardness for a random sample of 9 pins is at least 51 ? b. What is the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 ?

    Let \(A\) denote the percentage of one constituent in a randomly selected rock specimen, and let \(B\) denote the percentage of a second constituent in that same specimen. Suppose \(D\) and \(E\) are measurement errors in determining the values of \(A\) and \(B\) so that measured values are \(X=A+D\) and \(Y=B+E\), respectively. Assume that measurement errors are independent of one another and of actual values. a. Show that \(\operatorname{Corr}(X, Y)=\operatorname{Corr}(A, B) \cdot \sqrt{\operatorname{Corr}\left(X_{1}, X_{2}\right)} \cdot \sqrt{\operatorname{Corr}\left(Y_{1}, Y_{2}\right)}\) where \(X_{1}\) and \(X_{2}\) are replicate measurements on the value of \(A\), and \(Y_{1}\) and \(Y_{2}\) are defined analogously with respect to \(B\). What effect does the presence of measurement error have on the correlation? b. What is the maximum value of \(\operatorname{Corr}(X, Y)\) when \(\operatorname{Corr}\left(X_{1}, X_{2}\right)=.8100\) and \(\operatorname{Corr}\left(Y_{1}, Y_{2}\right)=.9025 ?\) Is this disturbing?

    Two components of a minicomputer have the following joint pdf for their useful lifetimes \(X\) and \(Y\) : $$ f(x, y)=\left\\{\begin{array}{cl} x e^{-x(1+y)} & x \geq 0 \text { and } y \geq 0 \\ 0 & \text { otherwise } \end{array}\right. $$ a. What is the probability that the lifetime \(X\) of the first component exceeds 3 ? b. What are the marginal pdf's of \(X\) and \(Y\) ? Are the two lifetimes independent? Explain. c. What is the probability that the lifetime of at least one component exceeds 3 ?

    Let \(X\) and \(Y\) be independent standard normal random variables, and define a new rv by \(U=.6 X+.8 Y\). a. Determine \(\operatorname{Corr}(X, U)\). b. How would you alter \(U\) to obtain \(\operatorname{Corr}(X, U)=\rho\) for a specified value of \(\rho\) ?

    The inside diameter of a randomly selected piston ring is a random variable with mean value \(12 \mathrm{~cm}\) and standard deviation \(.04 \mathrm{~cm}\). a. If \(\bar{X}\) is the sample mean diameter for a random sample of \(n=16\) rings, where is the sampling distribution of \(\bar{X}\) centered, and what is the standard deviation of the \(\bar{X}\) distribution? b. Answer the questions posed in part (a) for a sample size of \(n=64\) rings. c. For which of the two random samples, the one of part (a) or the one of part (b), is \(\bar{X}\) more likely to be within \(.01 \mathrm{~cm}\) of \(12 \mathrm{~cm}\) ? Explain your reasoning.

    See all solutions

    Recommended explanations on Math Textbooks

    View all explanations

    What do you think about this solution?

    We value your feedback to improve our textbook solutions.

    Study anywhere. Anytime. Across all devices.